6/15/2010 ž ž ž Implicit Differentiation Local Extrema Def 1: Suppose that is differentiable and the equation defines y as an implicit function of x, y=f(x), then 1 6/15/2010 ž Eg 1: Find equation if defines the ž Def 2: Suppose that defines an implicit function f with two variables, , then ž Eg 2: Find and defines the equation if . 2 6/15/2010 ž Def 3: A function defines in a domain D and (a,b) in D. (i) A function of two variables has a local maximum at (a,b) if for all points (x,y) in a region R where . The number is called a local maximum value (ii) A function of two variables has a local minimum at (a,b) if for all points (x,y) in a region R where . The number is called a local minimum value Local M axima ž ž ž Local M inima Local extrema point value(critical point or stationary point) can be determine by using First Derivative Test. Def 4: If f has a local maximum or minimum at (a,b), and the first order partial derivatives of f exists there, then and . [ First Derivative Test for Local Extrema] But, it happen to has a wired case..... 3 6/15/2010 (a,b,f(a,b)) [Planar Graph] ž Although graph above have and but the point (a,b,f(a,b)) is neither a local maximum or minimum. Its actually a saddle point. ž In order to know which properties is the critical point; either local maximum, local minimum or saddle, continuation of First Derivative Test is reveal by a name of Second Derivative Test. ž Def 5: For a function with , and all exist on a region, R and (a,b) is a critical point in R. Define 4 6/15/2010 Then if and , is a local minimum. (ii) if and , is a local minimum. (iii) if and, is a saddle point. (iv) if and, no conclusion can be made. ž (i) ž Eg 3: Find the critical points of . Consequently, determine whether the critical points have a local minimum value, local maximum value or a saddle point. ž Step 1: Find all the partial derivatives. ž Step 2: Find critical points. Take and . Set them equal, Therefore, the critical point at 5 6/15/2010 ž Step 3: Compute Therefore, produce a saddle point with the value of . 6
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