CHE230 Environmental Chemistry 2010 Tutorial Problem 6B The toxicity of chromium depends upon its oxidation state. The speciation of chromium varies due to redox reactions, complex formation and acid/base dissociation. As part of their fourth year plant design project, a student group examines the speciation of chromium in a water sample at 298K. Having developed a deep appreciation for Environmental Chemistry from second year, they recognize that the speciation of chromium can be described through the following set of reactions: R1) R2) R3) R4) R5) R6) R7) HCrO4- (aq) + 3e- + 4H+ (aq) [Cr(OH)3](aq) + H2O HCrO4- (aq) CrO42- (aq) + H+ (aq) Cr3+ (aq) + OH-(aq) [CrOH] 2+ (aq) [CrOH] 2+ (aq) + OH-(aq) [Cr(OH)2] + (aq) [Cr(OH)2] + (aq) + OH- (aq) [Cr(OH)3](aq) [Cr(OH)3] (aq) + OH- (aq) [Cr(OH)4] - (aq) [Cr(OH)3](s) Cr3+ (aq) + 3OH-(aq) ε0= 1.12 pKa = 6.51 Log K = 10.34 Log K = 8.08 Log K = 5.57 Log K = 4.61 Ksp = 6x10-31 a) Give the chemical formula and name of the predominant species of chromium in water with pH = 8 and pE= 10. R3 to R6 give the speciation of Cr3+ between different hydroxy complexes. R1 represents a chemical change (reduction), so we will consider it separately. First, the stepwise equilibrium constants K3-K6 can be combined by multiplying the constants: Cr3+ (aq) + 2OH-(aq) [CrOH2]+ (aq); β = K1K2 = 1010.34+8.08 etc. to derive an expression for Cr3+ species: So of these species, [Cr(OH)2]+ dominates. For R1: So . For R2: So So there is more than . Overall, , chromate(VI), predominates. b) Give the equation of the line describing the pE and pH conditions under which the concentrations of [Cr(OH)2] + (aq) and HCrO4- (aq) are equal. Combining R1 and R5, HCrO4- (aq) + 3e- + 4H+ (aq) [Cr(OH)3](aq) + H2O [Cr(OH)3](aq) [Cr(OH)2]+ (aq) + OH- (aq) HCrO4- (aq) + 3e- + 4H+ (aq) [Cr(OH)2]+ (aq) + OH- (aq) + H2O log(Koverall) = At the line, [Cr(OH)2]+ (aq) = [HCrO4- (aq)] ε0= 1.12 Log K = -5.57
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