(Find solu2on for y minimum)!
Minimum y = 841 mm!
1!
2!
3!
Undeformed 1.5 m Deformed 2.5 m 2 m 2.828 m 2 m 2 m TAC 45° TAB TAC = kx = 100 N/m (2.828-­‐2.5)m = 32.84 N ∑Fy = 0; 32.84 cos 45° - m (9.81) = 0 m = 2.37 kg
Ans m (9.81) 4!
5!
6!
(Radius to point B, C and D = 0.9 m) θ =30 o
D!
θ
B!
A (0, 0, 1.2)
B (0, 0.9, 0)
C (0.9cos θ , - 0.9sin θ , 0)
D (-0.9cos θ , -0.9sin θ, 0)!
y!
θ
C!
x!
7!
k N!
Or
Due to symmetry, all cable are subjected to the same tensile force;
FAB=FAC=FAD=F, then summation of force along z-axis yields; !
8!
A (0, 1.5, -­‐3) B (-­‐1.5sin60, -­‐1.5cos60, -­‐3) C (1.5sin60, -­‐1.5cos60, -­‐3) Assume that FOA is compression and FOB and FOC are tension!
9!