Polyhedral Computation Jayant Apte ASPITRG October 3, 2012 Jayant Apte. ASPITRG 1 Part I October 3, 2012 Jayant Apte. ASPITRG 2 The Three Problems of Polyhedral Computation ● ● Representation Conversion ● H-representation of polyhedron ● V-Representation of polyhedron Projection ● ● Redundancy Removal ● Compute the minimal representation of a polyhedron October 3, 2012 Jayant Apte. ASPITRG 3 Outline ● Preliminaries ● Representations of convex polyhedra, polyhedral cones ● ● ● Homogenization - Converting a general polyhedron in a cone in Polar of a convex cone to The three problems ● Representation Conversion – – ● Projection of polyhedral sets – – – ● Fourier-Motzkin Elimination Block Elimination Convex Hull Method (CHM) Redundancy removal – October 3, 2012 Review of LRS Double Description Method Redundancy removal using linear programming Jayant Apte. ASPITRG 4 Outline for Part 1 ● Preliminaries ● ● ● ● Representations of convex polyhedra, polyhedral cones Homogenization – Converting a general polyhedron in to a cone in Polar of a convex cone The first problem ● Representation Conversion – – October 3, 2012 Review of LRS Double Description Method Jayant Apte. ASPITRG 5 Preliminaries October 3, 2012 Jayant Apte. ASPITRG 6 Convex Polyhedron October 3, 2012 Jayant Apte. ASPITRG 7 Examples of polyhedra Bounded- Polytope October 3, 2012 Unbounded - polyhedron Jayant Apte. ASPITRG 8 H-Representation of a Polyhedron October 3, 2012 Jayant Apte. ASPITRG 9 V-Representation of a Polyhedron October 3, 2012 Jayant Apte. ASPITRG 10 Example (0.5,0.5,1.5) (1,1,1) (0,1,1) (0,0,1) (1,1,0) (0,1,0) (1,0,0) (0,0,0) October 3, 2012 Jayant Apte. ASPITRG 11 Switching between the two representations : Representation Conversion Problem ● ● ● H-representation V-representation: The Vertex Enumeration problem Methods: ● Reverse Search, Lexicographic Reverse Search ● Double-description method V-representation H-representation The Facet Enumeration Problem ● Facet enumeration can be accomplished by using polarity and doing Vertex Enumeration October 3, 2012 Jayant Apte. ASPITRG 12 Polyhedral Cone October 3, 2012 Jayant Apte. ASPITRG 13 A cone in October 3, 2012 Jayant Apte. ASPITRG 14 Homogenization October 3, 2012 Jayant Apte. ASPITRG 15 H-polyhedra October 3, 2012 Jayant Apte. ASPITRG 16 Example(d=2,d+1=3) October 3, 2012 Jayant Apte. ASPITRG 17 Example October 3, 2012 Jayant Apte. ASPITRG 18 V-polyhedra October 3, 2012 Jayant Apte. ASPITRG 19 Polar of a convex cone October 3, 2012 Jayant Apte. ASPITRG 20 Polar of a convex cone Looks like an H-representation!!! Our ticket back to the original cone!!! October 3, 2012 Jayant Apte. ASPITRG 21 Polar: Intuition October 3, 2012 Jayant Apte. ASPITRG 22 Polar: Intuition October 3, 2012 Jayant Apte. ASPITRG 23 Polar: Intuition October 3, 2012 Jayant Apte. ASPITRG 24 Polar: Intuition October 3, 2012 Jayant Apte. ASPITRG 25 Use of Polar ● Representation Conversion ● ● No need to have two different algorithms i.e. for and . Redundancy removal ● No need to have two different algorithms for removing redundancies from H-representation and V-representation ● Safely assume that input is always an Hrepresentation for both these problems October 3, 2012 Jayant Apte. ASPITRG 26 Polarity: Intuition October 3, 2012 Jayant Apte. ASPITRG 27 Polar: Intuition Then take polar again to get facets of this cone Perform Vertex Enumeration on this cone. October 3, 2012 Jayant Apte. ASPITRG 28 Problem #1 Representation Conversion October 3, 2012 Jayant Apte. ASPITRG 29 Review of Lexicographic Reverse Search October 3, 2012 Jayant Apte. ASPITRG 30 Reverse Search: High Level Idea ● ● ● Start with dictionary corresponding to the optimal vertex Ask yourself 'What pivot would have landed me at this dictionary if i was running simplex?' Go to that dictionary by applying reverse pivot to current dictionary ● Ask the same question again ● Generate the so-called 'reverse search tree' October 3, 2012 Jayant Apte. ASPITRG 31 Reverse Search on a Cube Ref.David Avis, lrs: A Revised Implementation of the Reverse Search Vertex Enumeration Algorithm October 3, 2012 Jayant Apte. ASPITRG 32 Double Description Method ● First introduced in: “ Motzkin, T. S.; Raiffa, H.; Thompson, G. L.; Thrall, R. M. (1953). "The double description method". Contributions to the theory of games. Annals of Mathematics Studies. Princeton, N. J.: Princeton University Press. pp. 51–73” ● The primitive algorithm in this paper is very inefficient. (How? We will see later) ● ● Several authors came up with their own efficient implementation(viz. Fukuda, Padberg) Fukuda's implementation is called cdd October 3, 2012 Jayant Apte. ASPITRG 33 Some Terminology October 3, 2012 Jayant Apte. ASPITRG 34 Double Description Method: The High Level Idea ● ● ● ● An Incremental Algorithm Starts with certain subset of rows of H-representation of a cone to form initial H-representation Adds rest of the inequalities one by one constructing the corresponding V-representation every iteration Thus, constructing the V-representation incrementally. October 3, 2012 Jayant Apte. ASPITRG 35 How it works? October 3, 2012 Jayant Apte. ASPITRG 36 How it works? October 3, 2012 Jayant Apte. ASPITRG 37 Initialization October 3, 2012 Jayant Apte. ASPITRG 38 Initialization Very trivial and inefficient October 3, 2012 Jayant Apte. ASPITRG 39 Example: Initialization October 3, 2012 Jayant Apte. ASPITRG 40 Example: Initialization October 3, 2012 Jayant Apte. ASPITRG 41 Example : Initialization -1 1 0 -1 -1 1 18 0 -4 A B 4.0000 14.0000 4.0000 4.0000 1.0000 1.0000 October 3, 2012 Jayant Apte. ASPITRG C 9.0000 9.0000 1.0000 42 How it works? October 3, 2012 Jayant Apte. ASPITRG 43 Iteration: Insert a new constraint October 3, 2012 Jayant Apte. ASPITRG 44 Iteration 1 A B 4.0000 14.0000 4.0000 4.0000 1.0000 1.0000 October 3, 2012 Jayant Apte. ASPITRG C 9.0000 9.0000 1.0000 45 Iteration 1: Insert a new constraint Constraint 2 October 3, 2012 Jayant Apte. ASPITRG 46 Iteration 1: Insert a new constraint October 3, 2012 Jayant Apte. ASPITRG 47 Iteration 1: Insert a new constraint October 3, 2012 Jayant Apte. ASPITRG 48 Main Lemma for DD Method October 3, 2012 Jayant Apte. ASPITRG 49 Iteration 1: Insert a new constraint October 3, 2012 Jayant Apte. ASPITRG 50 Iteration 1: Get the new DD pair -1 -1 18 1 -1 0 0 1 -4 -1 1 6 10.0000 12.0000 4.0000 6.0000 1.0000 1.0000 October 3, 2012 4.0000 4.0000 1.0000 Jayant Apte. ASPITRG 9.0000 9.0000 1.0000 51 Iteration 2 October 3, 2012 Jayant Apte. ASPITRG 52 Iteration 2: Insert new constraint October 3, 2012 Jayant Apte. ASPITRG 53 Iteration 2: Insert new constraint October 3, 2012 Jayant Apte. ASPITRG 54 Iteration 2: Insert new constraint October 3, 2012 Jayant Apte. ASPITRG 55 Get the new DD pair -1 -1 18 1 -1 0 0 1 -4 -1 1 6 0 -1 8 9.2000 10.0000 8.0000 10.0000 12.0000 4.0000 8.0000 8.0000 8.0000 4.0000 6.0000 4.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 October 3, 2012 Jayant Apte. ASPITRG 56 Iteration 3 October 3, 2012 Jayant Apte. ASPITRG 57 Get the new DD pair -1 -1 18 1 -1 0 0 1 -4 -1 1 6 0 -1 8 1 1 -12 A 6.2609 5.7391 1.0000 B 6.4000 5.6000 1.0000 October 3, 2012 C 6.0000 6.0000 1.0000 D 8.0000 4.0000 1.0000 E F 7.2000 4.8000 1.0000 9.2000 8.0000 1.0000 Jayant Apte. ASPITRG G H I J 10.0000 8.0000 10.0000 12.0000 8.0000 8.0000 4.0000 6.0000 1.0000 1.0000 1.0000 1.0000 58 Termination October 3, 2012 Jayant Apte. ASPITRG 59 Efficiency Issues ● Is the implementation I just described good enough? October 3, 2012 Jayant Apte. ASPITRG 60 Efficiency Issues ● Is the implementation I just described good enough? ● Hell no! – October 3, 2012 The implementation just described suffers from profusion of redundancy Jayant Apte. ASPITRG 61 Efficiency Issues October 3, 2012 Jayant Apte. ASPITRG We can totally do without this one!! 62 Efficiency Issues October 3, 2012 Jayant Apte. ASPITRG And without all these!!! 63 Efficiency Issues October 3, 2012 Jayant Apte. ASPITRG 64 The Primitive DD method October 3, 2012 Jayant Apte. ASPITRG 65 What to do? ● Add some more structure ● Strengthen the Main Lemma October 3, 2012 Jayant Apte. ASPITRG 66 Add some more structure October 3, 2012 Jayant Apte. ASPITRG 67 Some definitions October 3, 2012 Jayant Apte. ASPITRG 68 October 3, 2012 Jayant Apte. ASPITRG 69 October 3, 2012 Jayant Apte. ASPITRG 70 Algebraic Characterization of adjacency October 3, 2012 Jayant Apte. ASPITRG 71 Combinatorial Characterization of adjacency (Combinatorial Oracle) October 3, 2012 Jayant Apte. ASPITRG 72 Example: Combinatorial Adjacency Oracle October 3, 2012 Jayant Apte. ASPITRG 73 Example: Combinatorial Adjacency Oracle Only the pairs generate new rays October 3, 2012 and Jayant Apte. ASPITRG will be used to 74 Strengthened Main Lemma for DD Method October 3, 2012 Jayant Apte. ASPITRG 75 Procedural Description October 3, 2012 Jayant Apte. ASPITRG 76 Part 2 October 3, 2012 Jayant Apte. ASPITRG 77 ● Projection of polyhedral sets – – – ● Redundancy removal – October 3, 2012 Fourier-Motzkin Elimination Block Elimination Convex Hull Method (CHM) Redundancy removal using linear programming Jayant Apte. ASPITRG 78 Projection of a Polyhedra October 3, 2012 Jayant Apte. ASPITRG 79 Fourier-Motzkin Elimination ● Named after Joseph Fourier and Theodore Motzkin October 3, 2012 Jayant Apte. ASPITRG 80 How it works? October 3, 2012 Jayant Apte. ASPITRG 81 How it works? Contd... October 3, 2012 Jayant Apte. ASPITRG 82 Efficiency of FM algorithm October 3, 2012 Jayant Apte. ASPITRG 83 Convex Hull Method(CHM) ● ● ● First appears in “C. Lassez and J.-L. Lassez, Quantifier elimination for conjunctions of linear constraints via aconvex hull algorithm, IBM Research Report, T.J. Watson Research Center (1991)” Found to be better than most other existing algorithms when dimension of projection is small Cited by Weidong Xu, Jia Wang, Jun Sun in their ISIT 2008 paper “A Projection Method for Derivation of NonShannon-Type Information Inequalities” October 3, 2012 Jayant Apte. ASPITRG 84 CHM intuition October 3, 2012 Jayant Apte. ASPITRG 85 CHM intuition October 3, 2012 Jayant Apte. ASPITRG 86 CHM intuition October 3, 2012 Jayant Apte. ASPITRG (12,6,6) (12,6) 87 CHM intuition October 3, 2012 Jayant Apte. ASPITRG 88 Moral of the story ● ● ● We can make decisions about actually having its H-representation. It suffices to have , the original polyhedron We run linear programs on decisions October 3, 2012 without Jayant Apte. ASPITRG to make these 89 Input: Faces A of P Construct an initial Approximation of extreme points of Convex Hull Method: Flowchart Perform Facet Enumeration on to get Update by adding r to it Take an inequality from that is not a face of and move it outward To find a new extreme point r Are all inequalities In faces Of ? No Yes Stop October 3, 2012 Jayant Apte. ASPITRG 90 Example October 3, 2012 Jayant Apte. ASPITRG 91 Example October 3, 2012 Jayant Apte. ASPITRG 92 Example October 3, 2012 Jayant Apte. ASPITRG 93 Input: Faces A of P Construct an initial Approximation of extreme points of Convex Hull Method: Flowchart Perform Facet Enumeration on to get Update by adding r to it Take an inequality from that is not a face of and move it outward To find a new extreme point r Are all inequalities In facets Of ? Stop October 3, 2012 Jayant Apte. ASPITRG 94 How to get the extreme points of initial approximation? October 3, 2012 Jayant Apte. ASPITRG 95 Example: Get the first two points October 3, 2012 Jayant Apte. ASPITRG 96 Example: Get the first two points October 3, 2012 Jayant Apte. ASPITRG 97 Example: Get the first two points October 3, 2012 Jayant Apte. ASPITRG 98 Get rest of the points so you have a total of d+1 points October 3, 2012 Jayant Apte. ASPITRG 99 Get the rest of the points so you have a total of d+1 points October 3, 2012 Jayant Apte. ASPITRG 100 Get the rest of the points so you have a total d+1 points October 3, 2012 Jayant Apte. ASPITRG 101 How to get the initial facets of the projection? October 3, 2012 Jayant Apte. ASPITRG 102 How to get the initial facets of the projection? October 3, 2012 Jayant Apte. ASPITRG 103 Input: Faces A of P Construct an initial Approximation of extreme points of Convex Hull Method: Flowchart Incrementally update The Convex Hull (Perform Facet Enumeration on to get ) Are all inequalities In faces Of ? Update by adding r to it Take an inequality from that is not a face of and move it outward To find a new extreme point r No Yes Stop October 3, 2012 Jayant Apte. ASPITRG 104 Input: Faces A of P Construct an initial Approximation of extreme points of Convex Hull Method: Flowchart Incrementally update The Convex Hull (Perform Facet Enumeration on to get ) Are all inequalities In faces Of ? Update by adding r to it Take an inequality from that is not a face of and move it outward To find a new extreme point r No Yes Stop October 3, 2012 Jayant Apte. ASPITRG 105 Input: Faces A of P Construct an initial Approximation of extreme points of Convex Hull Method: Flowchart Incrementally update The Convex Hull (Perform Facet Enumeration on to get ) Are all inequalities In faces Of ? Update by adding r to it Take an inequality from that is not a facet of and move it outward To find a new extreme point r No Yes Stop October 3, 2012 Jayant Apte. ASPITRG 106 Incremental refinement ● ● Find a facet in current approximation of that is not actually the facet of How to do that? October 3, 2012 Jayant Apte. ASPITRG 107 Incremental refinement This inequality is Not a facet of October 3, 2012 Jayant Apte. ASPITRG 108 Incremental refinement October 3, 2012 Jayant Apte. ASPITRG 109 Input: Faces A of P Construct an initial Approximation of extreme points of Convex Hull Method: Flowchart Incrementally update The Convex Hull (Perform Facet Enumeration on to get ) Are all inequalities In faces Of ? Update by adding r to it Take an inequality from that is not a facet of and move it outward To find a new extreme point r No Yes Stop October 3, 2012 Jayant Apte. ASPITRG 110 How to update the H-representation to accommodate new point ? October 3, 2012 Jayant Apte. ASPITRG 111 Example October 3, 2012 Jayant Apte. ASPITRG 112 Example October 3, 2012 Jayant Apte. ASPITRG 113 Example: New candidate facets October 3, 2012 Jayant Apte. ASPITRG 114 How to update the H-representation to accommodate new point ? Determine validity of The candidate facet And also its sign October 3, 2012 Jayant Apte. ASPITRG 115 Example October 3, 2012 Jayant Apte. ASPITRG 116 Example October 3, 2012 Jayant Apte. ASPITRG 117 How to update the H-representation to accommodate new point ? October 3, 2012 Jayant Apte. ASPITRG 118 Example October 3, 2012 Jayant Apte. ASPITRG 119 Example October 3, 2012 Jayant Apte. ASPITRG 120 Example October 3, 2012 Jayant Apte. ASPITRG 121 nd 2 iteration Not a facet of October 3, 2012 Jayant Apte. ASPITRG 122 rd 3 iteration Not a facet of October 3, 2012 Jayant Apte. ASPITRG 123 th 4 iteration: Done!!! October 3, 2012 Jayant Apte. ASPITRG 124 Comparison of Projection Algorithms ● ● ● Fourier Motzkin Elimination and Block Elimination doesn't work well when used on big problems CHM works very well when the dimension of projection is relatively small as compared to the dimention of original polyhedron. Weidong Xu, Jia Wang, Jun Sun have already used CHM to get non-Shannon inequalities. October 3, 2012 Jayant Apte. ASPITRG 125 Computation of minimal representation/Redundancy Removal October 3, 2012 Jayant Apte. ASPITRG 126 Definitions October 3, 2012 Jayant Apte. ASPITRG 127 References K. Fukuda and A. Prodon. Double description method revisited. Technical report, Department of Mathematics, Swiss Federal Institute of Technology, Lausanne, Switzerland, 1995 G. Ziegler, Lectures on Polytopes, Springer, 1994, revised 1998. Graduate Texts in Mathematics. ● Tien Huynh, Catherine Lassez, and Jean-Louis Lassez. Practical issues on the projection of polyhedral sets. ● Annals of mathematics and artificial intelligence, November 1992 Catherine Lassez and Jean-Louis Lassez. Quantifier elimination for conjunctions of linear constraints via a ● convex hull algorithm. In Bruce Donald, Deepak Kapur, and Joseph Mundy, editors, Symbolic and Numerical Computation for Artificial Intelligence. Academic Press, 1992. R. T. Rockafellar. Convex Analysis (Princeton Mathematical Series). Princeton Univ Pr. ● W. Xu, J. Wang, J. Sun. A projection method for derivation of non-Shannon-type information inequalities. In ● IEEE International Symposiumon Information Theory (ISIT), pp. 2116 – 2120, 2008. ● October 3, 2012 Jayant Apte. ASPITRG 128 Minkowski's Theorem for Polyhedral Cones Weyl's Theorem for Polyhedral Cones October 3, 2012 Jayant Apte. ASPITRG 129
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