Significant Figures ReQuiz

Significant Figures ReQuiz
How many significant figures are in each of the following numbers? (7 pts each)
1)
2.400 ____
5)
12.00300 ____
2)
2.30 ____
6)
0.00120 ____
3)
0.6010 ____
7)
0.0102 ____
4)
26,000 ____
8)
370.000 ____
9)
Is there an instance when an object 5.0 cm wide will not pass through an
opening that is 5 cm wide? Explain. (5 pts)
10)
How do significant figures represent the accuracy of a measuring device?
(5 pts)
11)
What is the volume of the graduated cylinder? (2pts)
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12)
How long is the screw? (2pts)
13)
What is the length of the stick? (2pts)
(7 pts each)
14)
Solve: 2.12 L + 0.34 L = ____
15)
Solve: 0.4430 kg – 0.20 kg = ____
16)
Solve: 2.11 cm * 0.021 cm = ____
17)
Solve: 8.80 m / 2.2 m = ____
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© 2002 Cavalcade Publishing – All Rights Reserved
Significant Figures Worksheet - Answers
How many significant figures are in each of the following numbers?
1)
2.400
4
5)
12.00300
7
2)
2.30
3
6)
0.00120
3
3)
0.6010
4
7)
0.0102
3
4)
26,000
2
8)
370.000
6
9)
Is there an instance when an object 5.0 cm wide will not pass through an opening that is 5
cm wide? Explain. (5 pts) YES. If the opening is 5 cm wide, it means the opening could
range from 4.5 cm to 5.4 cm. If the object is 5.0 cm wide, it could have an actual size of
4.96 cm to 5.04 cm. If the opening is actually between 4.5 and 4.96, the object will not be
able to pass through it.
10)
How do significant figures represent the accuracy of a measuring device? (5 pts) The more
digits to the right of the decimal point indicate the greater precision of the measuring device
given the same units of measure.
11)
What is the volume of the graduated cylinder? (2pts) 37 mL. The acceptable range is
36 mL to 38 mL.
12)
How long is the screw? (2pts) 5.11 cm. The acceptable range is 5.10 cm to 5.12 cm.
13)
What is the length of the stick? (2 pts) 4.4 cm. The acceptable range is 4.3 cm to 4.5
cm.
(7 pts each)
14)
Solve: 2.12 L + 0.34 L = 2.46 L
15)
Solve: 0.4430 kg – 0.20 kg = 0.24 kg
16)
Solve: 2.11 cm * 0.021 cm = 0.044 cm2
17)
Solve: 8.80 m / 2.2 m = 4.0
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© 2002 Cavalcade Publishing – All Rights Reserved