Chapter 0 Posttest
State which metric unit you would probably use to measure each item.
1. mass of a book
SOLUTION: The masses of objects that are small are measured in grams. The mass of a book is small. The gram is the
appropriate unit of measure.
2. length of a highway
SOLUTION: The length of a highway can not be measured using a ruler. This length is very long. The kilometer is the
appropriate length unit of measure.
Complete each sentence.
3. 8 in. =
ft
SOLUTION: 8 in. =
ft
4. 6 yd =
ft
SOLUTION: 6 yd = ft
6 yd = 6 × 3
= 18 ft
5. 24 fl oz = larger unit→smaller unit
1 yd = 3 ft, × by 3.
Simplify
pt
SOLUTION: 24 fl oz = c smaller unit→larger unit
24 fl oz = 24 ÷ 8 8 fl oz = 1 c, ÷ by 8
Simplify
3 c = pt smaller unit→larger unit
3 c = 3 ÷ 2 1 pt = 2 c, ÷ by 2
= 1.5 pt
Simplify
= 3c
eSolutions
Manual
= - Powered
6. 3.7 kg
lb by Cognero
SOLUTION: Page 1
3 c = pt smaller unit→larger unit
3 c = 3 ÷ 2 1 pt = 2 c, ÷ by 2
=
1.5
pt
Chapter 0 Posttest Simplify
6. 3.7 kg =
lb
SOLUTION: 3.7 kg =
lb
1 kg ≈2.2 lb, × by
2.2
Multiply.
Round.
3.7 kg ≈ 3.7 × 2.2
≈ 8.14
≈ 8.1 lb
7. 4.2 km =
m
SOLUTION: 4.2 km =
m
4.2 km = 4.2 × 1000 1 km =1000 m, × by 1000
8. 285 g =
kg
SOLUTION: 285 g =
kg 285 g = 285 ÷ 1000 1000 g = 1 kg, ÷ by 1000
= 0.285 kg Division.
≈ 0.29 kg Round
9. 0.75 kg =
mg
SOLUTION: 0.75 kg =
=
=
1g =
≈
≈
g
0.75 × 1000 1 kg = 1000 g, × by 1000
50 g
Multiply.
mg
750 × 1000 750,000 mg
1 g = 1000 mg, × by 1000
Multiply.
10. 1.9 L =
qt
SOLUTION: 1 L =
qt
1 L ≈ 1.9 × 1.057 1 L ≈ 1.057 qt, × by 1.057
Multiply.
≈ 2.1 qt
11. PROBABILITY The table shows the results of an experiment in which a number cube was rolled. Find the
experimental probability of rolling a 4.
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SOLUTION: 1 L =
qt
1 L ≈ 1.9 × 1.057 1 L ≈ 1.057 qt, × by 1.057
Multiply.
≈ 2.1 qt
Chapter 0 Posttest
11. PROBABILITY The table shows the results of an experiment in which a number cube was rolled. Find the
experimental probability of rolling a 4.
SOLUTION: The experimental probability for getting a 3 in this case is
or 12%.
CANDY A bag of candy contains 3 lollipops, 8 peanut butter cups, and 4 chocolate bars. A piece of candy
is randomly drawn from the bag. Find each probability.
12. P(peanut butter cup)
SOLUTION: The probability of an event A is the ratio of the number of favorable outcomes to the total number of outcomes.
There are a total of 3 + 8 + 4 = 15 candies in the bag.
Out of the 15, 8 are peanut butter cups. The number of possible outcomes is 15 and the number of favorable
outcomes is 8.
Therefore,
13. P(lollipop or peanut butter cup)
SOLUTION: The probability of an event A is the ratio of the number of favorable outcomes to the total number of outcomes.
There are a total of 3 + 8 + 4 = 15 candies in the bag.
Out of 15, 3 are lollipops and 8 are peanut butter cups. The number of possible outcomes is 15 and the number of
favorable outcomes is 3 + 8 = 11.
Therefore,
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Therefore,
Chapter 0 Posttest
13. P(lollipop or peanut butter cup)
SOLUTION: The probability of an event A is the ratio of the number of favorable outcomes to the total number of outcomes.
There are a total of 3 + 8 + 4 = 15 candies in the bag.
Out of 15, 3 are lollipops and 8 are peanut butter cups. The number of possible outcomes is 15 and the number of
favorable outcomes is 3 + 8 = 11.
Therefore,
14. P(not chocolate bar)
SOLUTION: The probability of an event A is the ratio of the number of favorable outcomes to the total number of outcomes.
There are a total of 3 + 8 + 4 = 15 candies in the bag.
Out of 15, 4 are chocolate bars. 15. P(chocolate bar or lollipop)
SOLUTION: The probability of an event A is the ratio of the number of favorable outcomes to the total number of outcomes.
There are a total of 3 + 8 + 4 = 15 candies in the bag.
Out of 15, 4 are chocolate bars and 3 are lollipops. The number of possible outcomes is 15 and the number of
favorable outcomes is 4 + 3 = 7.
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Chapter 0 Posttest
15. P(chocolate bar or lollipop)
SOLUTION: The probability of an event A is the ratio of the number of favorable outcomes to the total number of outcomes.
There are a total of 3 + 8 + 4 = 15 candies in the bag.
Out of 15, 4 are chocolate bars and 3 are lollipops. The number of possible outcomes is 15 and the number of
favorable outcomes is 4 + 3 = 7.
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