Write the equation for the dissociation of
hydrochloric acid.
• HCl + H2O  H3O+ + Cl• Acid + Base  Conj. acid + Conj. base
• Given a 0.00476 M hydrochloric acid solution,
complete the following.
• Find the [H+].
• [H+] = Concentration
• [H+] = 0.00476 M
• Given a 0.00476 M hydrochloric acid solution,
complete the following.
• Find the [OH-].
• Kw = [H+] × [OH−] is rearranged to…
• [OH-] = Kw / [H+]
• Kw = 1.0 x 10-14 M
• [H+]= 0.00476 M or 4.76 x 10-3 M
• [OH-] = (1.0 x 10-14 M) / (4.76 x 10-3 M)
• [OH-] = 0.21 x 10-11 M or 2.1 x 10-12 M
• Given a 0.00476 M hydrochloric acid solution,
complete the following.
• Find the pH.
• pH = -log[H+]
• [H+]= 0.00476 M or 4.76 x 10-3 M
• pH = −log(4.76 x 10-3 M)
• pH = 2.32
• Given a 0.00476 M hydrochloric acid solution,
complete the following.
• Find the pOH.
• pOH = -log[OH-]
• [OH-] = 2.1 x 10-12 M
• pOH = -log[2.1 x 10-12 M]
• pOH = 11.66
• pH + pOH = 14
• 2.3 + pOH = 14
• pOH = 11.6
Write the equation for the dissociation of sodium
hydroxide.
• NaOH + H2O  Na+ + OH- + H2O
• Write the equation for the dissociation of sodium
hydroxide.
• Given a 0.000841 M solution of sodium hydroxide.
• Find the [H+].
Given a 0.000841 M solution of sodium hydroxide.
• Find the [OH-].
Given a 0.000841 M solution of sodium hydroxide.
• Find the pH.
Given, pH = 3.78
• Find [H3O+]
• pH = -log[H3O+]
• 3.78 = -log[H3O+]
• [H3O+] = 10-3.78 = 1.66 x 10-4 M
Given, pH = 3.78
• Find pOH
• pH + pOH = 14
• 3.78 + pOH = 14
• pOH = 10.22
Given, pH = 3.78
• Find [OH-]
• Kw = [H+] × [OH−] is rearranged to…
• [OH-] = Kw / [H+]
• Kw = 1.0 x 10-14 M
• [H+]= 1.66 x 10-4 M
• [OH-] = (1.0 x 10-14 M) / (1.66 x 10-4 M)
• [OH-] = 0.602 x 10-10 M = 6.02 x 10-11 M
Given, pH = 3.78
• Acid or Base?
• pH < 7  Acid!