Relating pH to Acid and Base Concentrations AP CHEMISTRY Acid-Base Chemistry and pH The chemistry of an aqueous solution often depends critically on pH It is therefore important to examine how pH relates to acid and base concentrations The simplest cases are those involving strong acids and bases Calculating pH for Strong Acids Remember, strong acids are strong electrolytes Aqueous solutions of strong acids consists entirely of conjugate base ions and H3O+ ions Equilibrium lies very far to the right so LARGE Ka The acid is the only significant source of H+ ions As a result, calculating the pH of a solution of a strong acid is straight forward because [H+] equals the original concentration of acid Strong Acid Animation Steps for Calculating pH of Strong Acids THINK – Strong acid, complete dissociation! 2. WRITE – Dissociation equation 3. WRITE – Major species at equilibrium 1. H+, A-, H2O 4. THINK – At equilibrium: [HA] ≈ 0.0 M, [H+] = [A-] = [HA]0 5. WRITE – pH = -log[H+] [H+] from the autoionization of water is 1.0 x 10-7 which is very small relative to [H+] from the acid, so neglect it! Practice! #1 on Ka Practice WS Calculating pH for Weak Acids Remember, weak acids only partially ionize in aqueous solution Aqueous solutions of weak acids are equilibria systems At equilibrium, solutions consist almost entirely of acid molecules with only relatively few H3O+ and conjugate base ions Ka is much smaller than 1 Weak Acid Animation We can use the equilibrium constant for the ionization reaction to express the extent to which a weak acid ionizes As a result, calculating the pH of a weak acid solution always represents an equilibrium condition Steps for Calculating pH of Weak Acid Solutions THINK – Weak acid, incomplete dissociation! 2. WRITE – Equilibrium equation 3. WRITE – Major species at equilibrium 1. 4. HA and H2O THINK – Do not know equilibrium conditions so use ICE table and Ka expression to solve for [H+] ([H3O+] ) Make assumption that [HA]int – x = [HA]eq = [HA]int if Ka << 1 WRITE – pH = -log[H+] 5. [H+] from the autoionization of water is 1.0 x 10-7 which is very small relative to [H+] from the acid, so neglect it! Practice! Let’s take a look at AP FRQ #18 WS! Using % Ionization to Measure Acid Strength We have seen that the magnitude of Ka indicates the strength of a weak acid Another measure of acid strength is percent ionization, and it is mathematically defined as: [H+ ]equilibrium Percent Ionization = × 100 [HA]initial Solving Weak Acid Equilibrium Problems Calculating Percent Ionization THINK – Weak acid, incomplete dissociation! 2. WRITE – Equilibrium equation 3. WRITE – Major species at equilibrium 1. HA and H2O 4. THINK – Do not know equilibrium conditions so use ICE table and Ka expression to solve for [H+] ([H3O+] ) Make assumption that [HA]int – x = [HA]eq = [HA]int if Ka << 1 5. WRITE – %dissociation = [H+ ] [HA]0 × 100 Practice! #11 on Ka Worksheet! Weak Base Equilibria The Strength of Bases If a base completely dissociates to produce OH- ions in solution, it is a STRONG BASE BOH (aq) → B+ (aq) + OH- (aq) Solution consists almost entirely of OH- ions and conjugate acid ions with a negligible concentration of base molecules Because the reaction lies very far to the right, the equilibrium constant, Kc, is much greater than 1 More products than reactants at equilibrium Solving Strong Base Equilibrium Problems Calculating pH THINK – Strong base, complete dissociation! 2. WRITE – Dissociation equation 3. WRITE – Major species at equilibrium 1. BH+, OH-, H2O 4. THINK – At equilibrium: [B] ≈ 0.0 M, [BH+] = [OH-] = [B]0 5. WRITE – pOH = -log[OH-]; pH = 14 - pOH [OH-] from the autoionization of water is 1.0 x 10-7 which is very small relative to [OH-] from the base, so neglect it! Weak Base Equilibria Weak bases react with water by abstracting protons from water Products include a conjugate acid and hydroxide ion (OH-) B (aq) + H2O (l) ↔ BH+ (aq) + OH- (aq) Because the reaction lies mostly to the left, the equilibrium constant Kc is much less than 1 More reactants than products at equilibrium Major species at equilibrium are B and H2O The equilibrium constant, K, has a specific notation for basic solutions, called the base-dissociation constant: Kb Equilibrium expression is written the same as Kc: [BH + ][OH − ] Kb = [B] Solving Weak Base Equilibrium Problems Calculating pH THINK – Weak base, incomplete dissociation! 2. WRITE – Equilibrium equation 3. WRITE – Major species at equilibrium 1. B and H2O 4. THINK – Do not know equilibrium conditions so use ICE table and Kb expression to solve for [OH-] Make assumption that [B]int – x = [B]eq = [B]int if Kb << 1 5. WRITE – pOH = -log[OH-]; pH = 14 - pOH [OH-] from the autoionization of water is 1.0 x 10-7 which is very small relative to [OH-] from the base, so neglect it! Practice! #5 on Kb worksheet! Relationship Between Ka and Kb We have seen in a qualitative way that the stronger the acid, the weaker its conjugate base The quantitative relationship that describes this relationship is as follows: K a × K b = K w = 1.0 × 10−14 As the strength of the acid increases (Ka gets larger), the strength of its conjugate base much decrease (Kb gets smaller) so that the product K a × K b remains 1.0 × 10−14 Introducing pKa and pKb Recall that we often express [H+] as pH pH = -log [H+] This “p” nomenclature is often used for other very small numbers such as pKa and Kb pKa = -log Ka pKb = -log Kb pKa + pKb = 14 Acids and Bases Tutorial Solving Acid and Base pH Problems Tutorial
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