Announcements Topics: -‐ Finish sec2on 3.3, work on 4.1 and 4.2, start 4.3 * Read these sec2ons and study solved examples in your textbook! Work On: -‐ Prac2ce problems from the textbook and assignments from the coursepack as assigned on the course web page (under the link “SCHEDULE + HOMEWORK”) Calculus On Con2nuous Func2ons In order to start studying con2nuous-‐2me dynamical systems, we need to develop the usual tools of calculus on con2nuous func2ons: Limits Con2nuity these are all defined Deriva2ves in terms of limits Integrals } Rates of Change The rate of change of a func2on tells us how the dependent variable changes when there is a change in the independent variable. Geometrically, the rate of change of a func2on corresponds to the slope of it’s graph. Secant Lines and Tangent Lines A secant line is a line that intersects two points on a curve. A tangent line is a line that just touches a curve at a point and most closely resembles the curve at that point. y tangent P Q secant y = f(x) x Average Rate of Change = Slope of Secant Line The average rate of change of f(t) from t=t1 to t=t2 corresponds to the slope of the secant line PQ. y Q f(t2) f( t1) P t1 t2 secant y = f(t) t Average Rate of Change = Slope of Secant Line Alterna(ve Nota(on: The average rate of change y of f(t) from the base point f(t0 +Δt ) t=t0 to t=t0+Δt is f(t0) Q secant P t0 +Δt t0 Δt y = f(t) t Average Rate of Change = Slope of Secant Line Example #2 (modified): Find the average rate of change of the func2on h(t) = t 2 + 1 star2ng from 2me t=1 and las2ng 1, 0.1, and 0.01 units of 2me. € t0 . Δt t0+Δt 1 1 2 1 0.1 1.1 1 0.01 1.01 f(t0+Δt) -‐ f(t0) Δt Es2ma2ng the Slope of the Tangent Steps: 1. Approximate the tangent at P using secants intersec2ng P and a nearby point Q. 2. Obtain a beber approxima2on to the tangent at P by moving Q closer to P, but Q ≠ P. 3. Define the slope of the tangent at P to be the limit of the slopes € PQ as Q approaches P of secants (if the limit exists). y P Q3 Q2 Q1 y = f(t) t € Instantaneous Rate of Change = Slope of Tangent Line The instantaneous rate of change of f(t) at t=t0 corresponds to the slope of the tangent line at t=t0. Δf f '(t 0 ) = lim Δt →0 Δt Note: The slope of the curve y=f(t) at P is the slope of its tangent line at P. y f(t0 +Δt ) f(t0) tangent Q P t0 t0 +Δt y = f(t) t Instantaneous Rate of Change = Slope of Tangent Line This special limit is called the deriva*ve of f at t0 and is denoted by f ’(t0) (read “f prime of t0”). Alterna2ve nota2on: y f(t0 +Δt ) f(t0) tangent Q P t0 t0 +Δt y = f(t) t Instantaneous Rate of Change = Slope of Tangent Line Example #10 (modified): 2 h(t) = t + 1 (a) Guess the limit of the slopes of the secants as the second point approaches the base point. t0 Δt t0+Δt f(t0+Δt) -‐ f(t0) Δt 1 0.1 1.1 2.1 1 0.01 1.01 2.01 1 0.001 1.001 2.001 y € (b) Use this to find the equa2on of the tangent line to h(t) at t=1. . x The Limit of a Func2on y Nota(ons: y=f(x) f (2) = 5 means that the y-‐value of the func2on AT x=2 is 5 5 2 € 2 ⎧ x 2 − 4 ⎪ if x ≠ 2 € f (x) = ⎨ x − 2 ⎪⎩5 if x = 2 x lim f (x) = 4 x →2 means that the y-‐values of the func2on APPROACH 4 as x APPROACHES 2 € The Limit of a Func2on Defini(on: lim f (x) = L x →a “the limit of f(x), as x approaches a, equals L” means that the values of f(x) (y-‐values) approach the number L more and more closely as x approaches a more and more closely (from either side of a), but x≠ a. € Limit of a Func2on Some examples: y y y x=3 y=g(x) y=h(x) y=f(x) x x Note: f may or may not be defined at x=a. Limits are only asking how f is defined NEAR a. x Lee-‐Hand and Right-‐Hand Limits lim− f (x) = L x →a means f (x) → L as x → a from the lee (x < a). lim+ f (x) = L x →a € € € means f (x) → L as x → a from the right (x > a). ** The full limit exists if and only if € the lee and right € € limits both exist (equal a real number) and are the same value. Lee-‐Hand and Right-‐Hand Limits For each func2on below, determine the value of the limit or state that it does not exist. y y y y=f(x) x y=g(x) x y=h(x) x Evalua2ng Limits We can evaluate the limit of a func2on in 3 ways: 1. Graphically 2. Numerically 3. Algebraically Evalua2ng Limits Example: Use a table of values to es2mate the value of x 2 −16 lim x →4 x − 4 x f(x) 3.5 3.9 3.99 4 undefined 4.01 4.1 4.5 € € € Evalua2ng Limits Algebraically BASIC LIMITS Limit of a Constant Func2on Limit of the Iden2ty Func2on lim x = a lim c = c, where c ∈ R x →a x →a Example: lim 2 = 2 Example: y x=3 € lim x →3 x →3 y=2 x € y y=x x LIMIT LAWS [used to evaluate limits algebraically] Suppose that c is a constant and the limits exist. Then lim f (x) and lim g(x) x →a x →a [ f (x) + g(x)] = lim f (x) + lim g(x) 1. lim x →a x →a x →a € [ f (x) − g(x)] = lim f (x) − lim g(x) 2. lim x →a x →a x →a € € € c f (x)] = c lim f (x) [ 3. lim x →a x →a LIMIT LAWS [used to evaluate limits algebraically] Con2nued… [ f (x) ⋅ g(x)] = lim f (x) ⋅ lim g(x) 4. lim x →a x →a x →a € € [ f (x) ÷ g(x)] = lim f (x) ÷ lim g(x), 5. lim x →a x →a x →a if lim g(x) ≠ 0 x →a Evalua2ng Limits Algebraically Example: Evaluate the limit and jus2fy each step by indica2ng the appropriate Limit Laws. lim (x 2 − 5x + 6) x →1 = lim x 2 − lim 5x + lim 6 x →1 x →1 x →1 = lim x ⋅ lim x − 5lim x + lim 6 x →1 x →1 = (1)(1) − 5(1) + 6 =2 x →1 x →1 Direct Subs2tu2on Property From the previous slide, we have lim (x 2 − 5x + 6) = 2 x →1 f (1) f (x) No2ce that we could have s€imply found the € € value of the limit by plugging in x=1 into the func2on. Direct Subs2tu2on Property Direct SubsFtuFon Property: If f(x) is an algebraic, exponenFal, logarithmic, trigonometric, or inverse trigonometric func2on, and a is in the domain of f(x), then lim f (x) = f (a) x →a € € Equal Limits Property Consider the func2ons: x 2 − 4 f (x) = g(x) = x + 2. x −2 y y y=g(x) y=f(x) € € 4 4 2 2 2 x 2 * Note: f(x)=g(x) everywhere except at x=2 x € Equal Limits Property Example: x2 − 4 Calculate lim . x →2 Note: direct subs2tu2on does not work x −2 € FACT: If f (x) = g(x) when x ≠ a , then lim f (x) = lim g(x) x →a x →a provided the limits exist. € € Strategy for Evalua2ng Limits # = ±∞ THENTHELIMIT$.% 0 MAYWANTTODOLEFTANDRIGHTCASES 4RY$IRECT3UBSTITUTION )FYOUGET € € 3IMPLIFY € real # THENTHELIMITEXISTSANDEQUALS THATREALNUMBER 0 0 INDETERMINATE Evalua2ng Limits Algebraically Evaluate each limit or state that it does not exist. 1 1 − x+2 2 x lim lim (a) x →−1 (b) x →2 x +1 x −2 € € 1− x x −2 (c) lim € (d) lim x →1 x −1 x →4 4 − x € Infinite Limits Example: Use a table of values to es2mate the value of 1 lim x →0 x x f(x) 0.1 0.01 0.001 0 undefined -‐0.001 -‐0.01 -‐0.1 € € Infinite Limits Defini(on: lim f (x) = ∞ x →a “the limit of f(x), as x approaches a, is infinity” means that the values o€f f(x) (y-‐values) increase without bound as x becomes closer and closer to a (from either side of a), but x ≠ a. € Defini(on: lim f (x) = −∞ x →a “the limit of f(x), as x approaches a, is nega2ve infinity” means that the values of f(x) (y-‐values) decrease without bound as x becomes closer and closer to a (from either side of a), but x ≠ a. € Infinite Limits Example: Determine the infinite limit. (a) lim x + 2 x →−1 € € x +1 (b) lim csc x x →π + Note: Since the values of these func2ons do not approach a real number L, these limits do not exist. Ver2cal Asymptotes Defini(on: The line x=a is called a verFcal asymptote of the curve y=f(x) if either lim f (x) = ±∞ or lim f (x) = ±∞ x →a− € Example: x →a + Basic func2ons we know that have VAs: Limits at Infinity The behaviour of func2ons “at” infinity is also known as the end behaviour or long-‐term behaviour of the func2on. What happens to the y-‐values of a func2on f(x) as the x-‐values increase or decrease without bounds? lim f (x) = ? x →−∞ lim f (x) = ? x →∞ Limits at Infinity Possibility: y-‐values also approach infinity or -‐ infinity Examples: f (x) = e f (x) = −0.01x 3 x 20 25 15 € € 10 -25 . -5 0 5 -25 0 5 10 15 20 25 30 25 50 75 100 Limits at Infinity Possibility: y-‐values approach a unique real number L Examples: 3x + 1 f (x) = x −2 sin x f (x) = x 16 € 1 8 0.5 -10 . -5 0 5 10 15 20 25 -25 0 -8 -16 € -0.5 25 50 75 100 125 150 Limits at Infinity Possibility: y-‐values oscillate and do not approach a single value Example: 1.5 1 0.5 f (x) = sin x -30 -25 -20 -15 -10 -5 0 -0.5 . -1 -1.5 5 10 15 20 25 30 € Limits at Infinity Defini(on: Defini(on: lim f (x) = L lim f (x) = L x →−∞ x →∞ “the limit of f(x), as x approaches ∞ , equals L” “the limit of f(x), as x approaches −∞ , equals L” means that the values of f(x) (y-‐values) can be made as € as we’d like to L by close taking x sufficiently large. means that the values of f(x) (y-‐values) can be made as € as we’d like to L by close taking x sufficiently small. € Calcula2ng Limits at Infinity *The Limit Laws listed previously are s2ll valid if “ x → a ” is replaced by “ x → ∞ ” Limit Laws for Infinite Limits (abbreviated): € € ∞+∞=∞ ∞⋅ ∞ = ∞ c⋅∞=∞ where c is any non-‐zero constant € Calcula2ng Limits at Infinity Theorem: 1 If r>0 is a ra2onal number, then lim r = 0. x →∞ x If r>0 is a ra2onal number such that x is defined for all x, then lim 1 = 0. r x →−∞ x r € € € Calcula2ng Limits at Infinity Examples: Find the limit or show that it does not exist. 2x 2 + 1 (a) xlim 2 →−∞ 4x − x € € arctan(3x + 5) € (b) lim [ ] x →∞ Horizontal Asymptotes Defini(on: The line y=L is called a horizontal asymptote of the curve y=f(x) if either lim f (x) = L or lim f (x) = L x →∞ x →−∞ Example: € € Basic func2ons we know that have HAs: . Limits at Infinity What about the limits at infinity of these func2ons? 2x ln x e (a) f (x) = (b) g(x) = x 10x Which part (top or bobom) goes to infinity faster? € € Limits at Infinity y = e 2x y = 10x 20 15 15 10 y= x y = ln x 10 5 € -5 -4 € -3 -2 -1 5 0 0 1 2 3 4 5 10 15 20 5 € € 25 30 35 Comparing Func2ons That Approach ∞ at ∞ Suppose lim f (x) = ∞ and lim g(x) = ∞ x →∞ x →∞ f (x) = ∞. 1. f(x) approaches infinity faster than g(x) if lim x →∞ g(x) € € f (x) = 0. 2. f(x) approaches infinity slower than g(x) if lim x →∞ g(x) € f (x) 3. f(x) and g(x) approach infinity at the same rate if lim = L. x →∞ g(x) € where L is any finite number other than 0. € € € Comparing Func2ons That Approach ∞ at ∞ The Basic Func2ons in Increasing Order of Speed FuncFon Comments Goes to infinity slowly aln x n with ax β x with ae € € € n>0 β >0 € € Approaches infinity faster for larger n Approaches infinity faster for larger β € Note: € The constant a can be any posi2ve number and does not € change the order of the func2ons. € € € Comparing Func2ons That Approach ∞ at ∞ y = ex 10 y=x y = x2 7.5 € € € € y= x 5 y = ln x 2.5 0 2.5 5 7.5 10 12.5 € € 15 17.5 Limits at Infinity What about the limits at infinity of these func2ons? −0.5 x e (a) f (x) = −2 (b) g(x) = −2 10x 5x −x Which part (top or bobom) goes to 0 faster? € € Limits at Infinity Semilog Graphs 10 0 5 10 15 y = ln5 − 2ln x 20 25 30 35 5 -5 0 5 10 -10 € y = −x -10 € € 20 y = −0.5ln x 25 30 35 y = ln10 − 2ln x -5 -15 15 € Comparing Func2ons That Approach 0 at ∞ Suppose lim f (x) = 0 and lim g(x) = 0. x →∞ x →∞ f (x) 1. f(x) approaches 0 faster than g(x) if lim = 0. x →∞ g(x) € € € € f (x) = ∞. 2. f(x) approaches 0 slower than g(x) if lim x →∞ g(x) € f (x) 3. f(x) and g(x) approach 0 at the same rate if lim = L. x →∞ g(x) € where L is any finite number other than 0. € Comparing Func2ons That Approach 0 at ∞ The Basic Func2ons in Increasing Order of Speed FuncFon Comments −n with n>0 Approaches 0 faster for larger n β >0 ae − β x 2 with β > 0 ae € Approaches 0 faster for larger β ax − β x with € € € € € Approaches 0 really €fast Note: Again, a can be any posi2ve constant and this €will not affect the ordering. € € Comparing Func2ons That Approach 0 at ∞ y =e y = x −2 −x 4 € € 3 € 2 1 -2 € y =e -1 −x 2 0 1 2 3 4 5 6 7 Comparing Func2ons That Approach 0 at ∞ y = e−x 0 1 2 3 -1 4 5 6 7 8 9 €Semilog Graphs € -2 -3 -4 -5 € y =e −x 2 y = −2ln y =ln−2ln x x y = −x 2 y = −x €€
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