PHYS208 Exam 2 Formula/Information Sheet Basic constants: Gravitational acceleration Electric permittivity in vacuum π ππ Electric constant in vacuum π Speed of light in vacuum Elementary charge Atomic mass unit Rest mass of electron Rest mass of proton π π 1π’ ππ ππ = 9.8 π/π 2 = 8.854 β 10β12 πΉ/π 1 = = 8.99 β 109 ππ2 /πΆ 2 4πππ β 3.00 β 108 π/π = 1.60 β 10β19 πΆ = 1.66 β 10β27 ππ = 9.11 β 10β31 ππ = 1.67 β 10β27 ππ Electron-volt Kilowatt-hour 1 ππ 1ππβ = 1.60 β 10β19 π½ = 3.6 β 106 π½ Units of energy: Some indefinite integrals: ππ₯ π₯ ππ₯ β« 2 (π₯ + π2 )3/2 ππ₯ β« 2 (π₯ ± π2 )1/2 ππ₯ β« π + ππ₯ π₯ππ₯ β« 2 (π₯ + π2 )3/2 π₯ ππ₯ β« 2 (π₯ ± π2 )1/2 = ππ π₯ + πΆ β« = = ππ (π₯ + βπ₯ 2 ± π2 ) + πΆ 1 ln(π + ππ₯) + πΆ π β1 = 2 +πΆ (π₯ + π2 )1/2 = = (π₯ 2 ± π2 )1/2 + πΆ β= β Definition of the gradient operator: Some basic geometry: π₯ +πΆ π2 (π₯ 2 + π2 )1/2 π π π πΜ + πΜ + πΜ ππ₯ ππ¦ ππ§ π΄ = 4ππ 2 4π 3 = π 3 = 2ππ β V = ππ 2 β πΊ = 4π π΄ Sphere of radius R V Cylinder of radius R and height h (Area here refers to the cylindrical barrel, not including the ends) Solid angle of a sphere Coulombβs Law for point charges πΉ Unit vector directed from a source to an observation point Definition πΜ for a point charge πΈβ (π) Definitions and Laws: = 1 π1 π2 π β 4πππ π 2 π |πΜ | = 1 = 1 π πΜ 4πππ π 2 π Electric field [1N/C=1V/m] Electric force [1N] π 1 ππ πΜ 4πππ ππ 2 π for a group of point charges (discrete charge distribution) πΈβπππ‘ for a continuous charge distribution πΈβπππ‘ on q placed in πΈβ πΉ β‘ ππΈβ through a small flat area βπ΄ βΞ¦πΈ = πΈβ β βπ΄ =|πΈβ ||βπ΄| πππ π through an entire surface Ξ¦πΈ = lim β βΞ¦πΈ,π = β― πΈβ β ππ΄ β‘ β πΈβπ = β π=1 =β« π=1 1 ππ πΜ 4πππ π 2 Electric flux [1Vβm] βπ΄β0 Gaussβs Law (for a closed surface) in vacuum Ξ¦πΈ,π‘ππ‘ in dielectric Ξ¦πΈ,π‘ππ‘ πππππ ππ πππππ β‘ β― πΈβ β ππ΄ = π β‘ β― πΈβ β ππ΄ = π βπ β‘ ππ βππ = β β« πΈβ β ππ for a point charge, with π(β) = 0 π(π) 1 π = 4πππ π for a group of point charges, with ππ (β) = 0 π(π ) Definition π Electric Potential [1V=1J/C] Electric potential energy[1J=1Nβm] π π=1 π=1 for a continuous charge distribution, with ππ (β) = 0 π(π ) 1 ππ = β« 4πππ |πβββπ β π | for a test charge ππ in πΈβ βπ β‘ ππ β ππ = ππ (ππ β ππ ) for a system of two point charges π12 πΈβ Electric field πΈβ from potential V For a capacitor = 1 π1 π2 4πππ π12 β π (β β = gradient operator) β‘ ββ β‘ π/π For an insulated conductor Electric capacitance[1F] π 1 ππ β‘ β ππ = β 4πππ |ππ β π| C β‘ π/πππ ππ π΄ π π0 πΎπ πΈ 2 = 2 =π Formula for parallelβplates Density of electric field energy [J/m3] π’πΈ Moment of an electric dipole [1Cβm] π β‘ ππ Torque of the electric dipole [1Nβm] π =π βββ × πΈβ Potential energy of an electric dipole [1J] ππΈ = βπ β πΈβ Energy stored in a capacitor [1J] ππΈ (π‘) Intensity of the electric current [1A] Current density [1A/m2] Definition I for a current density π I for a steady current I through a surface of area A for charges in motion j j Resistivity [1Ξ©βm] Definition Ο Resistance [1Ξ©] Definition for a steady current R for a metallic wire of length l and crosssection A R Energy-rate dissipated on resistors [1W] P = 1 π(π‘)2 2 πΆ ππ β‘ ππ‘ = β― π β ππ΄ πΌ π΄ = ππvπ 1 |πΈβ | = = π |π| π = πΌ π =π π΄ = = πΌπ = π πΌ 2 = π2 π ππ πΆ = π πΆ Charging a capacitor π(π‘) = ππππ₯ β (1 β exp(βπ‘/π)) Discharging a capacitor π(π‘) = ππ β exp(βπ‘/π) Time constant for an RC circuit [1s] Definition
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