Chem RG Chapter 13 worksheet. Dr. Lachman. SHOW YOUR WORK!
13.2 Worksheet (2 pages): See sample problem “A” p. 461 to do p. 420 #1-7.
Answers: 1) 1.5 ppm; 2) 130 ppm; 3) 4250 ppm; 4) 7.4 ppm;
5) 63ppm; 6) 155 ppm; 7) 2.3 ppm
Worksheet 13.2 continued: See sample problem “B” p. 465 to do p. 465 #1-7.
Answers: 1) 0.83 M; 2) 1.001 M; 3) 0.816 M; 4) 1.75 M;
5) 0.2501 M; 6) 2.5 g; 7) 11 g
Ch 13 Test Review Worksheet – Show your work below
See p. 489 #s 37, 40, 41, 43, 46, 48
37. A saturated solution of PbCO3 contains 0.00011 g PbCO3 in 100 g of water.
What is this concentration in ppm? Answer. 1.1 ppm
40. A 12.5 kg sample of shark meat contained 22 mg of methyl mercury, CH3Hg1+. Is this amount within the
legal limit of 1.0 ppm of methyl mercury in meat? Hint: Use your number line to convert kg to g and also to
convert mg to g. Then use your ppm formula and compare your answer to 1.0 ppm in the question. Ans. 1.76
ppm, which is above the limit. (See if you can get this answer.)
41. If 15.55 g NaOH are dissolved in enough water to make a 500.00 mL solution, what is the molarity of the
solution? Ans. 0.7776 M NaOH.
43. How many moles of AgNO3 are needed to prepare 0.50 L of a 4.0 M solution? Ans. 2.0 mol AgNO3
46. Calculate the mass of NaOH in 65 mL of 2.25 M solution. Hint: Convert mL to L, then rearrange the
M = mol divided by L molarity formula to solve for mol. Then use bar = bar to get the mass. Ans. 5.85 g
48. What is the molarity of a hydrochloric acid solution that contains 18.3 g HCl in 100.0 mL of solution?
Ans. 5.02 M HCl