Answer on Question #40670, Physics, Mechanics Question: A STONE OF MASS 1KG TIED TO A LIGHT INEXTENSIBLE STRING OF LENGTH = 10/3m , WHIRLING IN A CIRCULAR PATH IN A VERTICAL PLANE. THE RATIO OF MAX. TENSION IN THE STRING TO THE MIN. TENSION IN THE STRING IS 4. THE SPEED OF THE STONE AT THE HIGHEST POINT OF THE CIRCLE IS : 1. 10 m/s 2. 5(2)^1/2 m/s 3. 10(3)^1/3 m/s 4. 20 m/s Answer: Fup Fdown From Newtonβs second law of motion πΉπ’π and πΉπππ€π equals: πΉπππ€π πΉπ’π where π£2 π ππ£π2 = ππ + π 2 ππ£π’π = β ππ π is centripetal acceleration, π£ is velocity. The law of conservation of energy: 2 ππ£π2 ππ£π’π = + 2πππ 2 2 The ratio of tensions equals 4: πΉπππ€π πΉπ’π 2 ππ£π’π ππ + + 4ππ π =4= 2 ππ£π’π β ππ π Therefore: 2 3π£π’π = 9π π π£π’π = β3ππ = β3 Answer: 1. 10 π π 10 π 10 = 10 3 π
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