WJEC 2014 Online Exam Review GCSE Chemistry Unit 2 4472-01 All Candidates' performance across questions Question Title 1 2 3 4 5 6 7 8 9 10 N 4801 4802 4800 4800 4802 4799 4741 4748 4779 4718 Mean 2.1 2.8 4.4 2.9 5.3 3.4 1.8 2.3 2.2 2.4 SD 0.9 1.1 1.8 1.3 1.7 1.6 1.3 1.2 1.3 1.4 Max Mark 3 4 7 5 10 7 5 6 7 6 FF 71.7 69 62.6 57.8 52.9 48.8 35.4 37.6 30.7 40.6 Attempt % 100 100 100 100 100 99.9 98.7 98.9 99.5 98.3 Question GCSE Chemistry Unit2 4472-01 10 9 8 7 6 5 4 3 2 1 40.6 30.7 37.6 35.4 48.8 52.9 57.8 62.6 69 71.7 0 10 20 30 40 50 60 Facility Factor % 70 80 90 100 5 9 10 8 Examiner only 5.(a)Zinc reacts with dilute hydrochloric acid to produce hydrogen gas. The diagram below shows apparatus that can be used to investigate the rate of the reaction between zinc and hydrochloric acid. A small amount of copper sulfate is added because it acts as a catalyst for the reaction. bung gas syringe flask bubbles of hydrogen hydrochloric acid zinc A few pieces of zinc were placed in excess dilute hydrochloric acid and the volume of hydrogen produced was recorded every 10 seconds. The experiment was carried out at room temperature. The results obtained are shown below. Time (s) 0 10 20 30 40 50 60 70 Volume of hydrogen (cm3) 0 8 33 40 45 48 49 49 (i) All the results were measured accurately but the volume recorded after 10 seconds is lower than expected. Suggest a possible reason for this. [1] © WJEC CBAC Ltd. (4472-01) 9 (ii)Plot all the results from the table on the grid below and draw a suitable line. [3] Examiner only 50 40 30 Volume of hydrogen (cm3) 20 4 472 010 0 0 9 10 0 0 10 20 30 40 50 60 70 Time (s) (iii) Use your graph to give the volume of hydrogen expected after 10 seconds. [1] 3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . cm (iv) State how the graph shows that the reaction has stopped. [1] © WJEC CBAC Ltd. (4472-01) Turn over. I (ii) Plot all the results from the table on the grid below and draw a suitable line. [3] Examiner only Volume of hydrogen (cm ) 3 o Time (s) Use your graph to give the volume of hydrogen expected after 10 seconds. [1] cm^ (iv) State how the graph shows that the reaction has stopped. JQeCOJU..^. \.k lAjU-iAA S.hOLOS a..K0.G20.^k3J lk...f%&£UjU) © WJEC CBAC Ltd. [1] ^Q.S€J1J^^ (4472-01) rV\e Turn over. I Examiner (ii) Plot all the results from the table on the grid below and draw a suitable line. 50 — L 40 — * Volume of hydrogen (cm ) •4t • ! 1 \u \ 1 w — Y \1 )\ - & [3] 30 ... — 3 20 - i •• 1 — r — _ —— 1 10 . _ I i 0 1 - ! r - L 10 20 1 30 40 50 60 70 Time (s) (iii) Use your graph to give the volume of hydrogen expected after 10 seconds. [1] cm^ (iv) State how the graph shows that the reaction has stopped. ©WJEC CBAC Ltd. (4472-01) [1] Turn over. only Time (s) (iii) Use your graph to give the volume of hydrogen expected after 10 seconds. ^ X (iv) cm 3 State how the graph shows that the reaction has stopped. bc.fe^ 6Q W ~7Q ^.o.rwk, ike ..^mh. Qi <k<*\^l IjM © W J E C CBAC Ltd. [1] (4472-01) [1] cymfL Turn over. 0 16 9. The table below shows the amount of soap solution required by different samples of water to form a permanent lather. In each case 25 cm3 of the water samples were used and the soap solution was added 1 cm3 at a time. Volume of soap solution added (cm3) Sample distilled water A B C A after boiling B after boiling C after boiling Test 1 2 8 11 15 8 6 2 Test 2 2 8 18 14 7 5 2 Test 3 2 9 12 14 9 6 2 Test 4 2 7 13 13 8 7 2 Mean 2 8 14 8 6 2 (a) Two pupils, David and Haf, calculated the mean value for sample B. David calculated a value of 13.5 and Haf calculated a value of 12. Show how both values were obtained. State which is the better value to use and give a reason for your choice. [3] © WJEC CBAC Ltd. (4472-01) Examiner only 16 T h e table below s h o w s the a m o u n t o fs o a p solution required b ydifferent s a m p l e s o f water t o f o r m a p e r m a n e n t lather. I n e a c h c a s e 2 5 c m o f t h e w a t e r s a m p l e s w e r e u s e d a n d the s o a p solution w a s added 1 c m ata time. 3 3 3 V o l u m e o fsoap solution added (cm ) Sample Test 1 Test 2 Test 3 Test 4 Mean distilled w a t e r 2 2 2 2 2 A 8 8 9 7 8 B 11 18 12 13 \-Z- C 15 14 14 13 14 A after boiling 8 7 9 8 8 B after boiling 6 5 6 7 6 C after boiling 2 2 2 2 2 (a) T w o pupils, David and Haf, calculated the m e a n value for s a m p l e B . David calculated a value o f 13.5 and Haf calculated a value o f 12. S h o w h o w both values w e r e obtained. State which isthe better value t o u s e and give a reason for your choice. [3] •11 + ' ~l -v i ^> - 3 3fo ^ 3 - Examiner only 16 T h e table below s h o w s the a m o u n t o fs o a p solution required b ydifferent s a m p l e s o f water t o f o r m a p e r m a n e n t lather. I n e a c h c a s e 2 5 c m o f t h e w a t e r s a m p l e s w e r e u s e d a n d the s o a p solution w a s added 1 c m ata time. 3 3 3 V o l u m e o fsoap solution added (cm ) Sample Test 1 Test 2 Test 3 Test 4 Mean distilled w a t e r 2 2 2 2 2 A 8 8 9 7 8 B 11 18 12 13 \-Z- C 15 14 14 13 14 A after boiling 8 7 9 8 8 B after boiling 6 5 6 7 6 C after boiling 2 2 2 2 2 (a) T w o pupils, David and Haf, calculated the m e a n value for s a m p l e B . David calculated a value o f 13.5 and Haf calculated a value o f 12. S h o w h o w both values w e r e obtained. State which isthe better value t o u s e and give a reason for your choice. [3] •11 + ' ~l -v i ^> - 3 3fo ^ 3 - Examiner only 16 Examiner 9. T h e table below s h o w s t h e a m o u n t o f soap solution required b y different s a m p l e s o fwater t o f o r m a p e r m a n e n t lather. In e a c h c a s e 2 5 c m o f t h e w a t e r s a m p l e s w e r e u s e d a n dt h e s o a p solution w a s added 1c m ata time. 3 3 3 V o l u m e o f soap solution added ( c m ) Sample Test 1 Test 2 Test 3 Test 4 Mean distilled w a t e r 2 2 2 2 2 A 8 8 9 7 8 B 11 18 12 13 C 15 14 14 13 14 A after boiling 8 7 9 8 8 B after boiling 6 5 6 7 6 C after boiling 2 2 2 2 2 (a) T w o p u p i l s , D a v i d a n d H a f , c a l c u l a t e d t h e m e a n v a l u e f o r s a m p l e B. D a v i d c a l c u l a t e d a value o f 13.5 a n d H a f calculated a value o f 12. S h o w h o w both values w e r e obtained. State which ist h e better value t o u s e a n d give a reason for your choice. [3] ..bc.C.^X: i-i5rtgW' ij l \ WovfU jfL^JJIL^ ''v U }.W^ !.>. U U ^#.....tlv6^ (X.oVo^^ iVlt^n 0^ ft;? |MH4. only 16 T h e table below s h o w s the a m o u n t o f s o a p solution required b y different s a m p l e s o f water t o f o r m a p e r m a n e n t lather. I n e a c h c a s e 2 5 c m o f t h e w a t e r s a m p l e s w e r e u s e d a n d t h e s o a p solution w a s added 1 c m at a time. Examiner only 3 3 3 V o l u m e of soap solution added (cm ) Sample distilled w a t e r A B C A after boiling B after boiling C after boiling (a) Uj- Test 1 2 8 11 15 8 6 2 ..1<JL Test 4 2 7 13 13 8 7 2 Test 3 2 9 12 14 9 6 2 Mean 2 8 lift* 14 8 6 2 T w o p u p i l s , D a v i d a n d H a f , c a l c u l a t e d t h e m e a n v a l u e f o r s a m p l e B. D a v i d c a l c u l a t e d a value o f 13.5 a n d H a f calculated a value o f 12. S h o w h o w both v a l u e s w e r e obtained. S t a t e w h i c h is t h e better v a l u e t o u s e a n d give a r e a s o n for y o u r choice. [3] AX. r ^ ^ . ^ S .a.^..^^...l..?r....tJVl.' Mr. . Test 2 2 8 18 14 7 5 2 - ,Cms,%9! -..Mfrfr g&xQsric S. \rrf^S .i^G^^.vSr k^. VviovS Bo^e W ^ t ^ fee?Lt±£^4&... \/AIAJ<.... 1 17 Examiner only 10. An atom of element E is represented as follows. 35 17 E State and explain what information this gives you about element E. You may wish to refer to the key on the Periodic Table to help you answer this question. [6 QWC] END OF PAPER © WJEC CBAC Ltd. (4472-01) Turn over. 6 17 Examiner only 10. An atom of element E is represented as follows. 35 17 E State and explain what information this gives you about element E. You may wish to refer to the key on the Periodic Table to help you answer this question. [6 QWC] *k ...I/i^M^tf* Mo$> $ M cyfld. /UtAikf (dm*:. t/jM/Mt. m>. iuJ.C^Ma. W...M kmj. Cm. c^ork acfW pfo/m out. i% gAckvnl.c cyn.d. iMotmi ci k ^ ...^^.^gg^g. hd^.,kJc S M M ^ A C \ ^A^kon^., <^e. m....^k. and C ^ . M , . ^ . ^LOCA.. .3. . Ca*\ AA OiufcatS (^A..../k?a*J.. aA....i^o.r.k 1* db.. Ihx.wzr... Mmic OdUmh^r. OOUCUJ. .JLm A . ijflbkem tLt. tk C^QUf?.. S&iMm c£.. &tetr.o(\S u\ %}. ..^m u*. it... $ku^€.A&...£jg..&fe.o.ik ..M tfaf.. ma...y& 14. Iks m>. u& tlwt.. fh,:s Mm**... id. .2,3., J..., m A tV*A%r. \ \M. (Ylfaty.. d.. °h.^t. IM. /m;S5. (lUtnLr, i/L......tkil END OF PAPER WJEC CBAC Ltd. (4472-01) Turn over. 6 17 Examiner only 10. An atom of element E is represented as follows. 35 17 E State and explain what information this gives you about element E. You may wish to refer to the key on the Periodic Table to help you answer this question. [6 QWC] gVewenV £ ^es frr>e vWe €te>yveftV 5 s^mboXE.^ cxVoyy>\c hV»ynW&r>1 ^,,,,(^A^)rn£^ t...,,^~h;a^ ilfc ...pm*^^ oJt pyoVoy^ .y-s V V \ ^ .£<Qitav£ a s . hVM.b&f ...pi re.l.f.c.te^..n^ tNj.Wx.cio i s vtye. S Q i r w e . g\>r £\-cvy>^iV .,...^te..!Y\.LC 'y.s !b^..caM.^ tk.-e i^a^....ny.J»?..te i A ^ u W o v x ^ iWvs \5 ^Ue tay..tok £r:.....Q..£ pjpsfcnJ if\v£.wto..^.B§.....^.^ A Q ^ . . . . ^ e u ^y.M.b.^Br:....G>..£.... 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