Name _______KEY___________________________________ Date _________ Period ______
Mixed Stoichiometry Review
Balance the reaction below. Use it to answer problems 1-8.
__4_FeCr2O7 + __8_K2CO3 + ____O2 → __2_Fe2O3 + __8_K2CrO4 + __8_CO2
271.85
1.
138.21
1 mol K2CO3
8 mol CO2
x
= 0.0329 mol CO2
138.21 g K2CO3 8 mol K2CO3
How many grams of O2 are required to react with 15.6 grams of FeCr2O7?
1 mol FeCr2O7
1 mol O2
32.00 g O2
x
x
= 0.459 g O2
271.85 g FeCr2O7 4 mol FeCr2O7
1 mol O2
How many moles of K2CrO4 can be made with 5.21 moles of Fe2O3?
5.21 mol Fe2O3 x
6.
1 mol K2CrO4
4 mol FeCr2O7 271.85 g FeCr2O7
x
x
= 45.6 g FeCr2O7
194.21 g K2CrO4 8 mol K2CrO4
1 mol FeCr2O7
How many grams of FeCr2O7 are required to produce 1.25 moles of Fe2O3?
1.25 mol Fe2O3 x
8.
8 mol K2CrO4
= 20.8 mol K2CrO4
2 mol Fe2O3
How many grams of FeCr2O7 can produce 65.2 grams of K2CrO4?
65.2 g K2CrO4 x
7.
2 mol Fe2O3
= 3.18 mol Fe2O3
8 mol K2CO3
How many moles of CO2 can be produced from 4.55 grams of K2CO3?
15.6 g FeCr2O7 x
5.
44.01
1 L O2
= 0.769 L O2
8 L CO2
4.55 g K2CO3x
4.
194.20
How many liters of O2 can be produce 6.15 liters of CO2 at STP?
6.15 L CO2 x
3.
159.70
How many moles of Fe2O3 are produced from 12.7 moles of K2CO3?
12.7 mol K2CO3 x
2.
32.00
4 mol FeCr2O7 271.85 g FeCr2O7
x
= 680. g FeCr2O7
2 mol Fe2O3
1 mol FeCr2O7
How many liters of O2 are required to react with 354 grams of K2CO3 at STP?
354 g K2CO3 x
1 mol K2CO3
1 mol O2
22.4 L O2
x
x
= 7.17 L O2
138.21 g K2CO3 8 mol K2CO3 1 mol O2