6.3 Vectors.notebook March 19, 2012 6.3 Vectors 1 6.3 Vectors.notebook March 19, 2012 Vector: has magnitude (length) and direction Q (x2, y2) PQ terminal point ||v|| magnitude P (x1, y1) initial point 2 6.3 Vectors.notebook March 19, 2012 Component Form of a Vector A vector whose initial point is at the origin (0, 0) can be represented by the coordinates of its terminal point (v1, v2). v = < v1 , v2 > The component form of the vector with initial point P = (x1, y1) and terminal point Q = (x2, y2) is: The magnitude (or length) of v is: 3 6.3 Vectors.notebook March 19, 2012 Example 1: Find the component form and magnitude of the vector v that has (1, 7) as its initial point and (4, 3) as its terminal point. 4 6.3 Vectors.notebook March 19, 2012 Vector Operations Geometrically, the product of a vector v and a scalar k is . . . the vector that is k times as long as v If k is positive, kv has the same direction as v, and if k is negative, kv has the opposite direction. v 1/2v 2v v 5 6.3 Vectors.notebook To add two vectors geometrically, position them so the initial point of one coincides with the terminal point of the other March 19, 2012 v u This technique is called the parallelogram law for vector addition because the vector u + v, often called the resultant of vector addition, is . . . the diagonal of a parallelogram with u and v as sides 6 6.3 Vectors.notebook March 19, 2012 Let u = 〈u1, u2〉 and v = 〈v1, v2〉 be vectors and let k be a scalar (vector addition) ku = < ku1 , ku2 > (Scalar multiplication) 7 6.3 Vectors.notebook March 19, 2012 Let u = 〈1, 6〉 and v = 〈− 4, 2〉. Sketch the operations geometrically. Then find: (a) 3v (b) u + v 8 6.3 Vectors.notebook March 19, 2012 Unit Vector: has a magnitude of 1 To find a unit vector u that has the same direction as vector v . . . u = v ||v|| 9 6.3 Vectors.notebook March 19, 2012 Find a unit vector in the direction of v = 〈− 8, 6〉. 10 6.3 Vectors.notebook March 19, 2012 Find the vector v with the given magnitude and same direction as u. ||v|| = 3, u = < 4, -4 > find the unit vector multiply it by the magnitude 11 6.3 Vectors.notebook Standard Unit Vectors: i = <1, 0> j = <0, 1> March 19, 2012 Linear Combination Vector v = 〈v1, v2〉 can also be represented as: j = <0, 1> v = v1i + v2j i = <1, 0> 12 6.3 Vectors.notebook March 19, 2012 Let v = 〈− 5, 3〉. Write v as a linear combination of the standard unit vectors i and j. 13 6.3 Vectors.notebook March 19, 2012 The initial point of a vector is (-6, 4) and the terminal point is (0, 1) Write a linear combination of the standard vector. 14 6.3 Vectors.notebook March 19, 2012 Find the component form of v and sketch the specified vector operations geometrically. w = i + 2j u = 2i - j v = -u + 2w 15 6.3 Vectors.notebook March 19, 2012 (x, y) Direction Angles u Direction Angle: measured counterclockwise from the x axis to terminal point of u y = sinθ θ x = cosθ u = 〈x, y〉 = < cosθ , sinθ > = (cosθ)i + (sinθ)j v = ||v|| < cosθ , sinθ > = ||v|| cosθ i + ||v|| sinθ j Since v = ai + bj, tan θ = b (like a reference angle) a 16 6.3 Vectors.notebook March 19, 2012 Find the component form of V given its magnitude and angle. ||v|| = 4, θ = 45o 17 6.3 Vectors.notebook March 19, 2012 Let v = − 4i + 5j. Find the magnitude and direction angle for v. 18 6.3 Vectors.notebook March 19, 2012 Applications of Vectors force / velocity / tension = magnitude / length also think: Geometry, right triangle trig, law of cosines and sines 19 6.3 Vectors.notebook March 19, 2012 Using Vectors to Find Speed and Direction Example 10 p.416 An airplane is traveling at a speed of 500 mph with a bearing of 330o. The airplane encounters a wind blowing 70 mph in the direction N 45o E. What are the resultant speed and direction of the airplane? 20 6.3 Vectors.notebook March 19, 2012 Highlight of Important Vocab / Formulas: Component Form: v = < v1, v2 > found by subtracting x values and y values of points Magnitude: ||v|| found by: √(v1 + v22) or the distance formula 2 Unit Vector: v ||v|| Linear Combination of v: v1i + v2j Direction Angles: v = ||v|| cosθ i + ||v|| sinθ j If v = ai + bj, then tan θ = b a 21 6.3 Vectors.notebook March 19, 2012 22
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