Solving Quadratics – x2 = n, then x = ± n Up to this point, we have solved quadratic equations using the Zero Product Property (factoring). We used the following algorithm: 1. 2. 3. 4. Put everything on one side, zero on the other side Factor completely Set each fact equal to zero Solve the resulting equations So, if we had a problem like x2 = 16, we used that algorithm. Given Step 1 Step 2 Step 3 x2 = 16 x2 – 16 = 0 (x + 4)(x – 4) = 0 x + 4 = 0 or x – 4 = 0 x = – 4 or x = 4 If we did enough of those problems using that algorithm, you might see a pattern that would allow you to solve the equation in your head by taking the square root. Before moving on, let me make a point, this is an equation of degree 2 - a quadratic equation. That degree suggests that we will have two solutions. So, if we had the following equations to solve, would you be able to find the solutions in your head without using the algorithm – without factoring? 1) x2 = 25 x = ± 25 x= ± 5 2) x2 = 100 x = ± 100 x = ± 10 3) x2 = 64 x = ± 64 x= ± 8 My guess is you can solve those in your head. For instance, solving x2 = 36, most students would not need to put pencil to paper to come up with the solution x = ±6 Hanlonmath.com [email protected] 800.218.5482 The very nice thing about math is you can never make it more difficult, only longer. Example Find the solution set for x2 – 6 = 43 To make this problem look like the ones I just did, let’s isolate the x2. x2 = 49 x = ±7 To generalize this, let’s construct the following algorithm to solve equations in the form x2 = n 1. 2. 3. 4. Example Find the solution set Given Step 1 Step 2 Step 3 Example Isolate the quadratic term (variable) Take the square root of both sides, the right side of the equation is ± Simplify the radical Solve the resulting equations 3x2 + 2 = 50 3x2 + 2 = 50 3x2 = 48 x2 = 16 x = ± 16 x= ± 4 Find the solution set 2x2 – 3 = 21 2x2 = 24 x2 = 12 x = ± 12 x = ± 4i3 x = ±2 3 Hanlonmath.com [email protected] 800.218.5482 Example Find the solution set (2x + 1)2 + 4 = 29 (2x + 1)2 = 25 2x + 1 = ± 5 2x = ± 5 – 1 2x = +5 – 1 or 2x = –5 – 1 2x = 4 or 2x = – 6 x=2 or x=–3 Hanlonmath.com [email protected] 800.218.5482
© Copyright 2026 Paperzz