An example on binomial probabili.es, inspired by the book The Science of Fear by Daniel Gardner ECE 302 Fall 2009 TR 3‐4:15pm Purdue University, School of ECE Prof. Ilya Pollak Binomial r.v.’s and journalism majors • Excerpts from The Science of Fear by D. Gardner (DuSon, 2008). – The probability of the earth being walloped by a 300‐meter asteroid in any given year is 1 in 50,000, which makes the odds 1 in 500 over the course of the century. Binomial r.v.’s and journalism majors • Excerpts from The Science of Fear by D. Gardner (DuSon, 2008). – The probability of the earth being walloped by a 300‐meter asteroid in any given year is 1 in 50,000, which makes the odds 1 in 500 over the course of the century. … For a 100‐meter rock, the odds are 1 in 10,000 in one year and 1 in 100 over the next 100 years. Binomial r.v.’s and journalism majors • Excerpts from The Science of Fear by D. Gardner (DuSon, 2008). – The probability of the earth being walloped by a 300‐meter asteroid in any given year is 1 in 50,000, which makes the odds 1 in 500 over the course of the century. … For a 100‐meter rock, the odds are 1 in 10,000 in one year and 1 in 100 over the next 100 years. At 30 meters, the odds are 1 in 250 per year and 1 in 2.5 over the next 100 years. Binomial r.v.’s and journalism majors • Excerpts from The Science of Fear by D. Gardner (DuSon, 2008). – The probability of the earth being walloped by a 300‐meter asteroid in any given year is 1 in 50,000, which makes the odds 1 in 500 over the course of the century. … For a 100‐meter rock, the odds are 1 in 10,000 in one year and 1 in 100 over the next 100 years. At 30 meters, the odds are 1 in 250 per year and 1 in 2.5 over the next 100 years. • Excerpt from an online review of the book: – He says 'The probability of the earth being walloped by a 300‐metre asteroid in any given year is 1 in 50,000, which makes the odds 1 in 500 over the course of a century.' No it doesn't. Binomial r.v.’s and journalism majors • Excerpts from The Science of Fear by D. Gardner (DuSon, 2008). – The probability of the earth being walloped by a 300‐meter asteroid in any given year is 1 in 50,000, which makes the odds 1 in 500 over the course of the century. … For a 100‐meter rock, the odds are 1 in 10,000 in one year and 1 in 100 over the next 100 years. At 30 meters, the odds are 1 in 250 per year and 1 in 2.5 over the next 100 years. • Excerpt from an online review of the book: – He says 'The probability of the earth being walloped by a 300‐metre asteroid in any given year is 1 in 50,000, which makes the odds 1 in 500 over the course of a century.' No it doesn't. That's like saying 'The odds of ge\ng a head with one throw of a coin is 1 in 2, which makes the odds 1 in 1 over two throws.' That's not how probabili.es combine. Binomial r.v.’s and journalism majors • Excerpts from The Science of Fear by D. Gardner (DuSon, 2008). – The probability of the earth being walloped by a 300‐meter asteroid in any given year is 1 in 50,000, which makes the odds 1 in 500 over the course of the century. … For a 100‐meter rock, the odds are 1 in 10,000 in one year and 1 in 100 over the next 100 years. At 30 meters, the odds are 1 in 250 per year and 1 in 2.5 over the next 100 years. • Excerpt from an online review of the book: – He says 'The probability of the earth being walloped by a 300‐metre asteroid in any given year is 1 in 50,000, which makes the odds 1 in 500 over the course of a century.' No it doesn't. That's like saying 'The odds of ge\ng a head with one throw of a coin is 1 in 2, which makes the odds 1 in 1 over two throws.' That's not how probabili.es combine. • Interes.ngly, they are both wrong. Some assump.ons • Assume that Gardner’s sta.s.cs of asteroid hits for one year are correct: 1/50000 probability for a 300‐meter asteroid, 1/10000 for a 100‐meter, and 1/250 for a 30‐ meter. Some assump.ons • Assume that Gardner’s sta.s.cs of asteroid hits for one year are correct: 1/50000 probability for a 300‐meter asteroid, 1/10000 for a 100‐meter, and 1/250 for a 30‐ meter. • Assume that asteroid hits in different years are independent, and that there cannot be more than one hit per year. Some assump.ons • Assume that Gardner’s sta.s.cs of asteroid hits for one year are correct: 1/50000 probability for a 300‐meter asteroid, 1/10000 for a 100‐meter, and 1/250 for a 30‐ meter. • Assume that asteroid hits in different years are independent, and that there cannot be more than one hit per year. • If P(1 hit in 1 year) = p then P(≥1 hits in 100 years) = 1 – P(0 hits in 100 years) = 1 – (1 – p) 100 Call this quan.ty f(p). Some calcula.ons • f(p) = P(≥1 hits in 100 years) = 1 – (1 – p) 100 Taylor series : f ( p) = f (0) + f '(0) p + f ''(0) 2 p +… 2! Some calcula.ons • f(p) = P(≥1 hits in 100 years) = 1 – (1 – p) 100 Taylor series : f ''(0) 2 f ( p) = f (0) + f '(0) p + p +… 2! When p is very small, f ( p) ≈ f (0) + f '(0) p = 100 p (because f '( p) = 100(1− p) 99 ) Some calcula.ons • f(p) = P(≥1 hits in 100 years) = 1 – (1 – p) 100 Taylor series : f ''(0) 2 f ( p) = f (0) + f '(0) p + p +… 2! When p is very small, f ( p) ≈ f (0) + f '(0) p = 100 p (because f '( p) = 100(1− p) 99 ) E.g., if p = 1/50000, then f ( p) ≈ 100 /50000 = 1/500 = 0.002 (actually, 0.001998) Some calcula.ons • f(p) = P(≥1 hits in 100 years) = 1 – (1 – p) 100 Taylor series : f ''(0) 2 f ( p) = f (0) + f '(0) p + p +… 2! When p is very small, f ( p) ≈ f (0) + f '(0) p = 100 p (because f '( p) = 100(1− p) 99 ) E.g., if p = 1/50000, then f ( p) ≈ 100 /50000 = 1/500 = 0.002 (actually, 0.001998) E.g., if p = 1/10000, then f ( p) ≈ 100 /10000 = 1/100 = 0.01 (actually, 0.009951) Some calcula.ons • f(p) = P(≥1 hits in 100 years) = 1 – (1 – p) 100 Taylor series : f ( p) = f (0) + f '(0) p + f ''(0) 2 p +… 2! When p is very small, f ( p) ≈ f (0) + f '(0) p = 100 p (because f '( p) = 100(1− p) 99 ) E.g., if p = 1/50000, then f ( p) ≈ 100 /50000 = 1/500 = 0.002 (actually, 0.001998) E.g., if p = 1/10000, then f ( p) ≈ 100 /10000 = 1/100 = 0.01 (actually, 0.009951) But when p = 1/250, the quadratic term in the Taylor series is no longer negligible : f ''(0) 2 9900 p =− = −0.0792 (because f ''( p) = −9900(1− p) 98 ) 2! 2 ⋅ 62500 Some calcula.ons • f(p) = P(≥1 hits in 100 years) = 1 – (1 – p) 100 Taylor series : f ( p) = f (0) + f '(0) p + f ''(0) 2 p +… 2! When p is very small, f ( p) ≈ f (0) + f '(0) p = 100 p (because f '( p) = 100(1− p) 99 ) E.g., if p = 1/50000, then f ( p) ≈ 100 /50000 = 1/500 = 0.002 (actually, 0.001998) E.g., if p = 1/10000, then f ( p) ≈ 100 /10000 = 1/100 = 0.01 (actually, 0.009951) But when p = 1/250, the quadratic term in the Taylor series is no longer negligible : f ''(0) 2 9900 p =− = −0.0792 (because f ''( p) = −9900(1− p) 98 ) 2! 2 ⋅ 62500 f (0) + f '(0) p = 100 /250 = 0.4, whereas f ( p) ≈ 0.330217
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