BACK TO CONTENTS Worksheet 69: Area of composite shapes Worksheet 69 Learning Number Level 2 Area of composite shapes To find areas of composite shapes with straight edges: Example 1 ● split the shape into rectangles and triangles; ● find the areas of the individual bits; ● add or deduct the areas to get the total area. We use formulae to calculate area. breadth RECTANGLE Area = length × breadth length length SQUARE Area = length × length Note length and breadth in same units length Keep the units the same. 1 If a rectangle measures 5m by 3m, its area is 5 x 3 = 15 m2 (square metres). ● If a square is 12 mm along each side, its area is 12 x 12 = 144 mm2 (square millimetres). See how all the measurements are in the same ‘family’ – nt Hi ● lengths in metres (m) give area in square metres (m2) lengths in millimetres (mm) give area in square millimetres (mm2). © National Extension College Trust Ltd BACK TO CONTENTS Learning Number Level 2 Worksheet 69: Area of composite shapes More complicated shapes can often be split into rectangles, like this: 10.5 m C Setting out is 3.5 m it easier to total your 6m important as it makes A 2m nt Hi 3.8 m B individual areas and find any mistakes. 3m 4m Area A = 6 × 4 = 24 m2 Area B = 3.5 × 1.8 = 6.3 m2 Area C = 3 × 3.8 = 11.4 m2 Total area = A + B + C = 41.7 m2 © National Extension College Trust Ltd 2 BACK TO CONTENTS Worksheet 69: Area of composite shapes Learning Number Level 2 Or we can treat them as larger rectangles with smaller rectangles or squares removed, as below. 13 m 8.5 m C A B 3m 3m 3.5 m 3.5 m 8.5 m 3m 3m Shaded area = area of large rectangle – (total area of A + B + C) Area of large rectangle = 13 × 12 = 156 m2 Area A = 3 × 3.5 = 10.5 m2 Area B = 3 × 3.5 = 10.5 m2 Area C = 3 × 3 = 9 m2 Total area of A + B + C = 30 m2 Area of shaded area = 156 m2 – 30 m2 = 126 m2 3 © National Extension College Trust Ltd BACK TO CONTENTS Learning Number Level 2 Worksheet 69: Area of composite shapes Make sketches of these diagrams and calculate the shaded areas. Exercise 1 Where there are decimals in an answer, round the final answer to two decimal places. In some cases, you may have to work out missing measurements before you start. 3.10 m 1.82 m 0.71 m 4.00 m 1.94 m 2.41 m 3.62 m 2.91 m 3.10 m 1.68 m 2 4.71 m 1.21 m 1 4.00 m 2.89 m 3 4 12.2 m 7.3 m 4.6 m 3.4 m 5.8 m 2.3 m 3.1 m 11.8 m 3m 1m 5 6 11.5 m 6.5 m 5m 8m 12 m 8m 6m 2.4 m 5m 2.3 m 1m 3.1 m 1.8 m 2.8 m 3.2 m 3.1 m © National Extension College Trust Ltd 4 BACK TO CONTENTS Worksheet 69: Area of composite shapes Learning Number Level 2 Area of a triangle Sometimes, the shapes might be triangular. Example 2 It is quicker to work out the area of a triangle by this rule: Area of triangle = 1 2 × base × height The base can be any side. The height is the line from the base to the opposite corner. Example: Area of triangle = 1 2 × 10 × 3 = 1 2 × 30 = 15 cm2 height 3 cm base 10 cm Exercise 2 1 Find the areas of these triangles. (a) (b) 12 2 cm 8 cm 5 cm 25 cm © National Extension College Trust Ltd BACK TO CONTENTS Learning Number Level 2 Worksheet 69: Area of composite shapes 2 Find the total areas of these shapes. 1m (a) (b) 4m 3.5 m 8m 5m (c) 3m 2m 4m Exercise 3 Find the area of the gable end of this building. 5m 3.5 m 6m © National Extension College Trust Ltd 6 BACK TO CONTENTS Worksheet 69: Area of composite shapes Learning Number Level 2 Area of a circle nt Hi π (pronounced pie) Use the formula: π × radius × radius is usually rounded to 3.14, or 3.142. 2.5 m table The radius is 2.5 ÷ 2 = 1.25 m. nt Hi radius The radius is half the diameter. The surface area of the table is: π × radius × radius 3.14 × 1.25 × 1.25 = 4.90625 m2. Exercise 4 7 Calculate the surface area of the table above using π = 3.142 (to 3 decimal places). © National Extension College Trust Ltd BACK TO CONTENTS Learning Number Level 2 Worksheet 69: Area of composite shapes Sometimes you have composite shapes that consist of, say, rectangles and circles (or semi-circles). For example, an ironing board: Example 3 Find the surface area of the shape below, using π = 3.142. 90 cm 1.6 m The two ends are semi-circular, with diameter 90 cm = 0.9 m. nt Hi Note the change to common units of 1 Area of rectangle = 1.6 × 0.9 = 1.44 m2 2 Area of semi-circles = area of a full circle with radius 0.9 ÷ 2 = 0.45 m. measurement. A = π r2 = 3.142 × 0.45 × 0.45 = 0.64 m2 (2 decimal places) Total area = 1.44 + 0.64 = 2.08 m2 Exercise 5 Find the surface of the ironing board shown below. (Use π = 3.142.) 95 cm 1.2 m © National Extension College Trust Ltd 8
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