Unit 3.6 ! Date:!__________ Slope-intercept form. A line may be graphed MANY ways. One way to graph is to randomly select x values and calculate the corresponding y values. y = 4x + 2 x y ( ( ( , , , ) ) ) Another way, was to select two specific points, the intercepts. x-int., let y = 0 ( , ) y-int., let x = 0 ( , ) 1 y =− x−3 3 This section points out some facts about linear equations in two variables that will provide still a 3rd (and best) method for graphing. But first consider: Graph the line whose y-intercept is (0, 2 ) And that has a slope of m= 1 4 EQUATIONS IN SLOPE-INTERCEPT FORM y = 2x + 3 Consider an equation: ! ! !What would the y-intercept be? To determine the slope of the line, find two ordered pairs and compute the slope formula. ! x y 0 3 y 2 − y1 m= x 2 − x1 It is not just a coincidence unique to the previous equation. Given any equation in the form: y = mx + b , ! ! it is said to be in slope-intercept form and it represents a line of slope m with y-intercept (0, b ). Ex. 2)! Find the slope and y-int. for the following eq. 4 y = x−8 y − int. = 5 ! a)! ! ! ! ! ! b)! 2x + y = 5 ! y − int. = ! ! m= ! c)! 3x − 4 y = 7 ! y − int. = ! ! m= ! ! ! ! ! m= 12 Ex. 3)! A line has a slope of 5 and a y-intercept of (0,11). Find the equation of that line. Your equation should be of the form: y = mx + b − Ex. 4)! ROO Graphing and Slope-intercept Form. Recall from Ex. 1, we were able to draw a line w/out an eq. Now that we have an equation, we can pull out the pieces of information that made that possible. Ex. 5) a) Graph: y= 3 x+5 4 y − int. = m= Ex. 5b) Graph: 2x + 3y = 3 Note this is not in slopeintercept form. You can’t draw any data from it until it is. y − int. = m= PARALLEL AND PERPENDICULAR LINES Parallel means that two lines running side by side, never cross. When looked at on a grid, they would have the same slope. Ex. 6) Are the lines parallel? y = −3x + 4 6x + 2y = −10 y − int. = m= y − int. = m= The relationship between the slope of lines that are perpendicular is not as straight forward. Perpendicular lines form a 90 degree angle where they cross. Are the lines perpendicular? y = 3x − 5 1 y =− x+4 3 y − int. = m= y − int. = m= Look at the two lines graphed above. What is the product of their slopes? This is also not just a coincidence. The product of the slopes of perpendicular lines will always be (-1). ! ! ! The slope of the first line times ! ! ! the slope of the second line equals -1. ( m )( m ) = −1 1 2 Ex. 7)! Determine whether the graphs of 2x + y = 8 and 1 y = x+7 2 are perpendicular. Ex. 8)! Write a slope-intercept equation for the line whose graph is described. ! a)! Parallel to the graph of 2x − 3y = 7 , with a yintercept of (0,-1) ! ! b)! Perpendicular to the graph of 2x − 3y = 7, with a y-intercept of (0,-1)
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