Exercise Class Week 1 – Vectors - Answers 1. Write down the length r and the angle measured anticlockwise from the x-axis of each of the vectors a to e in the diagram. Not much to explain here – note that angles are measured anticlockwise, because this is angle from x towards y, consistent with a righthand rule that gives z upwards out of the page, and with = tan–1 y/x. Note that e is the same vector as it would be if it were shifted to start – or finish – at the origin. a: r = 4 = 0 b: r = 4 = 90° c: r = 4◊2 = 45° d: r = 2◊2 = 135° e: r = 2 = 180° OR –2, 0 2. Write each vector in component form, v = (vx, vy). Again, e is the same vector as it would be if it were shifted to start – or finish – at the origin. a= (4, 0) b= (0, 4) c= (4, 4) d= (–2, 2) e= (–2, 0) 3. Calculate the following scalar products, using u.v = uv cos where u and v are the lengths and is the angle between the two vectors a.a = 44cos 0 = 16 a is like a (same direction, parallel) a.b = 44cos 90° =0 a is totally unlike b (a and b are orthogonal) b.c = 44◊2cos 45° = 16 b and c are neither orthogonal nor parallel c.b = 4◊24cos 45° = 16 and that doesn’t depend on the order taken c.d = 4◊22◊2cos 90° =0 c and d are orthogonal b.d = 42◊2cos 45° =8 d.e = 2◊22cos 45° =4 a.e = 42cos 180° = –8 a is like e (parallel) 4. Calculate the following scalar products, using u.v = uxvx + uyvy a.a = 16 + 0 = 16 a.b = 0+0 =0 b.c = 0 + 16 = 16 c.b = 0 + 16 = 16 c.d = –8 + 8 =0 b.d = 0+8 =8 d.e = 4+0 =4 a.e = –8 + 0 = –8 Same answers as using uv cos Which method is easier? 5. Calculate the following vector products, using uv = uv sin aa = 44sin 0° =0 Area between is zero ab = 44sin 90° = 16 Area between is maximum cd = 4◊22◊2sin 90° = 16 Note that dc would be –16 6. Calculate the following vector products, using uv = (uzvy – uyvz, uz vx – ux vz, ux vy – uy vx) aa = (0 – 0, 0 – 0, 0 – 0) = (0, 0, 0) ab = (0 – 0, 0 – 0, 16 – 0) = (0, 0, 16) cd = (0 – 0, 0 – 0, 8 – –8) = (0, 0, 16) Same answers as using uv sin But direction is given explicitly. 7. What are the following vector products (note: hats not easily available in Word) ii = 0 Note that i = (1, 0, 0) ij = k ik = –j As expected (Why?) kj = –i Note how one can cycle the symbols 8. For each of the following relationships between two vectors both of length r = 1, what can you say about the two vectors concerned? Their dot product vanishes; they are . . . Orthogonal [OR at right angles, perpendicular] Their dot product vanishes; the angle between them is . . . 90° Their dot product is 1; they are . . . Parallel Their dot product is 1; the angle between them is . . . 0° 3 1 3 1 , and v 0, , . 9. Two vectors are u 3 , 2 2 4 4 Find their lengths u: and v: u2 = 3 + ¾ + ¼ = 4 2 v = 0 + 3/16 + 1/16 = ¼ so u = 2 so u = ½ Calculate their scalar product: 0 + 3/8 + 1/8 = ½ Hence find the angle between them: uvcos = ½ so = 60° Write down the unit vectors uˆ : ½u = ½ (◊3, ½◊3, ½) = (½◊3, ¼◊3, ¼) and vˆ : 2v = 2 (0, ¼◊3, ¼) = (0, ½◊3, ½) [These are the vector over its length.] (Note: here the hats are essential, so I had to sort out how to get them in Word.)
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