Lesson 5 The Shell Model Why models? • Nuclear force not known! • What do we know about the nuclear force? (chapter 5) • It is an exchange force, mediated by the virtual exchange h off gluons l or mesons. Electromagnetic force • Virtual exchange of photons ΔE • Δt ≥ h ΔE Δt ≈ h hc hc R = cΔt ≈ = ΔE Eγ Nuclear Force • Virtual exchange of particles of mass m h Δt ≤ mc 2 h R≤ mc R = 1.4 fm ⇒ m ≥ 140 MeV / c 2 Assuming nuclear force is short range saturation property of nuclear forces Nuclear Force • Strongly attractive • Repulsive core • Not spherically h i ll symmetric i (deuteron (d quadrupole moment), has symmetric central component and d asymmetric i tensor component. • Spin dependent (deuteron ground state is triplet, singlet state is unbound) Nuclear potential Other potentials of note Other potentials of note Table 5-1 Charge independence of nuclear forces The nuclear force between a neutron and a proton is the same as the force between two protons or two neutrons. Nucleus Total Binding Energy (MeV) Coulomb Energy (MeV) Net nuclear binding energy (MeV) 3H -8.486 0 -8.486 3He -7.723 0.829 -8.552 13C -97.10 7.631 -104.734 13N -94.10 10.683 -104.770 23Na -186.54 23.13 -209.67 23Ne -181.67 27.75 -209.42 41Ca -350.53 65.91 -416.44 41Sc -343 79 -343.79 72 84 72.84 -416 63 -416.63 A 3 13 23 41 Isospin Consider that the neutron and the proton are just two states of the nucleon. Consider further that these two states are labeled by a quantum number, T, called isospin. For the nucleon, T T=1/2. 1/2. There are two projections of T in isospace, T3=+1/2 (proton) and T3=-1/2 (neutron) For a nucleus containing Z protons and N neutrons, T3=(Z-N)/2. Example Consider the A=14 isobars, 14C, 14N and 14O. 14C and 14O have T3=±1. Thus they must be part of an isospin multiplet, T=1. In 14N, T3=0, but there must be a state with T T=1. 1. This state is called the isobaric analog of the ground states of 14C and 14O. Getting back to the shell model Evidence for nuclear shell structure: •Peaks in binding energy /nucleon •Changes Changes in separation energies for certain numbers of neutron and protons in separation energies for certain numbers of neutron and protons •Magic numbers (2,8,20,28,50,82,….) Zero quadrupole moments Low neutron absorption cross sections Abundance systematics More Examples p Spin-orbit Spin orbit coupling More on spin-orbit spin orbit force Consider the Woods-Saxon potential Aufbau Prinzip 1. Fill in lowest energy first 2. Pair up particles as you add them (“Katz’s rule”) 3. Spin and parity of the ground state is the spin and parity of the last nucleon for odd A nuclei. For e‐e nuclei, J,π =0+. For o‐o nuclei, use Brennan‐Bernstein rules. Reality Check Brennan-Bernstein Brennan Bernstein Rules 1. When the odd nucleons are both particles or holes in their respective subshells, Rule 1 states that when j1 = ℓ1 ½ and j2 = ℓ2 ∓ ½, then J = ∣j1 – j2∣. 2. Rule 2 states that when j1 = ℓ1 ½ and j2 = ℓ2 ½, then J = ∣j1 j2∣ 3. Rule 3 states that for configurations in which the odd nucleons are a combination of particles and holes, such as 36Cl, J=j1 + j2 +1 Example Consider the o-o nuclei, 38Cl, 26Al and 56Co. Predict the ground state spin and parity for these nuclei. (a) 38Cl has 17 protons and 21 neutrons. The last proton is in a d3/2 level while the last neutron is in an f7/2 level. (Figure 6-3). jp = 2 – 1/2, jn = 3 + 1/2 J = |7/2 – 3/2| = 2 π=– (b) 26Al has 13 protons and 13 neutrons. The last proton and the last neutron are in d5/2 hole states, i.e., jp = jn = 2 + 1/2. J = |5/2 + 5/2| = 5 π=+ (c) 56Co has 27 protons and 29 neutrons. The last proton is in a f7/2 hole state and the last neutron is in a p3/2 state (1 + 1/2) J = 7/2 + 3/2 – 1 = 4 π=+ Statistics on B B-B B rule. rule Successes of Shell Model •Ground state spins and parities of nuclei •Some information about excited states Magnetic Moments; Schmidt Limits Focus on a single particle μi = gℓLi + gsSi gℓ = ℓμ0, gs = 5.5845μ 5 5845μ0 for protons and gℓ = 0, gs = - 3.8263μ0 for neutrons where μ0 is the nuclear magneton: μ0 = eħ/2mpc Application to Nuclei; Schmidt limits For j = ℓ + s , μ = ℓgℓ + ½ gs For j = ℓ - s, μ = (j/j+1)[(ℓ + 1) gℓ – ½ gs] Islands of Isomerism What is a nuclear isomer? What causes an isomer? Where do they occur? Mirror nuclei Definition: nuclear-pairs in which the numbers of protons and neutrons are interchanged, for example, 3He and 3H Failures of the Shell Model •Positions and origin of low lying 2+ states in nuclei •Rotational and vibration levels in deformed nuclei, like the rare earths and the actinides.
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