Student 1(£ Y A. Class Date _ _ PROJECTILES 2 ANGLE PROJECTILES ./ An angle projectile follows the path of a full parabola .,/ The velocity of an angle projectile has both horizontal and vertical components .,/ The x-component of an angle projectile is a constant horizontal motion .,/ The y-component of an angle projectile is a free fall motion of an object thrown up ./ Refer to the Angle Projectile template for all the angle projectile problems 1. A small missile is fired with a velocity of 399. meters per second at an angle of 39.9° above the ground. After a total flight time of 39.6 seconds, the missile retur~ to the level ground. [Neglect air reSistance.] +~ __,~-~--~~ ~ ",...x Dx C rrs: V' $l'llt, x · .... (a) Calculate the initial horizontal and vertical components of the velocity. H OY'l'20'l\-\~) ~- (b) c. = t: 0 '00. ; $','", )qo -==- ~O. ""'1.5' l Calculate the maximum height of the missile above the ground. " V· Y'1::' l'f . t "-f -+- 2\ ~Y' . ~ (ISo ~'f '::: I. .L ~"ff r-; "\. 7 ) (I~.)s).f- z(....q·~J;")(/~. Vy• t:."tltt)r 1- 15.3 ,r) ~ 115 0 """ (c) Calculate the total horizontal range of the missile. ~)( :::: V ix . t - vy - ~ IIS0~ J S' 2. A machine launches a tennis ball at an angle of 450 with the horizontal, as shown. The ball has an initial vertical velocity of 9.0 meters per second and an initiai horizontal velocity of 9.0 meters per second. The ball reaches its maximum height 0.92 seconds after its launch. [Neglect friction and assume the ball lands at the same height from which it was launched.] Elapsed TIme __ r=O'9~S_ ,-". Viy ~ = 9.0 m/s . / / ; ". ". // ~ ; - ..... V"' , .... .... - "" ........ .... .... ,, Launcher " Horizontal , (a).. Calculate the speed of the ball as it leaves the launcher. < _f ~ t~ I V," -:: V Vl)(..(. Vi" {('t.o'!!:')t. S' + ('1.o!!!)l.. $ (b) Calculate the horizontal distance traveled by the ball during the entire time it is in the air. i),c '::- V\)C' t -= l t4r =:-1.(0.'\'25) t.. =(q.o~) f.a= s (I.&,C,» f(,.$(, ... ~ [fEJ - (. F45 (c) Compare the vertical acceleration of the ball at the time of the launch to the vertical acceleration of the ball at elapsed time 0.92 second. (d)_ Sketch a graph to represent the relationship between the horizontal speed of the ball and elapsed time. Vx v)( ~ _-----~---------7~ t (s-) is' ("o",sta",+ ("f~ khro~~~O~{ (e) State the change, if any, in both the vertical component and horizontal component of the ball' s velocity as it rises. IJ e 'J. ' f ~er-O ~ f '\11'\ V'1 (decr('".res {yo..... ~ fOJlllve vo.. Ct~ -\-Of -\-"'e", It- d.ecr~ot.S~> fro", 7:.(>""0 +0 ""'f~Qfi"~ va w'""'" t'-'.e ba" ~l~ S +~e ~ '1"0,", II\cJ) v)< ('r~w..(J..l"""S Co",.stct",t~ht'o~~~o~+ ~~ e",+c'''e Mot('O~) (f) On the diagram draw an arrow to show the direction of the ball's velocity at its maximum height. Label the arrow v. +0 L:e' ( & ...'0. 8 rro. ......) (g) On the diagram draw an arrow to show the direction of the ball's acceleration at its maximum height. Label the arrow a. • ( oh"DO. 0""0."'") 3. A shell is fired from the ground with an initial velocity of 1.70 x103 m/s (approximateLy five times the speed of sound) at an initial angle of 55.0° to the horizontal. Neglecting air re7,fstance,& find: Vix ~V\coS8::.17007'(oJ'S's°'!::" 975""$ +Y ~' 1 YL'i :: vi$i",e '::'1700 ~ ,,· ...ss<'-::. 1"3'11 ... ; .. " a. the amount of time the shell is in motion . : F.,.ov... V of 't A ~0 6 ve.,.tlC'o.{(" -se i:. 'i ~ -r (- 'f·~1 ;:) ttcr b. the maximum height of the shell o = f3q3 i1' ~ A/~ h.Q\I~: = " ~'f + ~'1' t.L4 r Q= lEj 'J ~ I> _".9/""St. 2 t"ft. ~ = ~ +)( I 'f 2 _s- -::: - {~If f . § 29c[,S Z (1C,2S) ::: c. tJ:tehorizontal range of the,shell [i>xJ= Vix' t - 'i75;. (Z8"t S) - I 27{,'foo.., ~ 277000 ...' )
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