Area Study Guide 3/30/16

StudyGuideAnswerKEY
ComplexPolygonsandCircles–AreasandCircumference
1)Findtheareaofthecomplexshape.
3in
5in
3in
9in
!!
AreaofTriangle= ! b=9–5=4
h=3
AreaofTriangle=4(3)/2
=6π’Šπ’πŸ AreaofRectangle=bh
=9(3)
=27π’Šπ’πŸ TotalAREA=6+27=33π’Šπ’πŸ 2)Findtheareaoftheshadedregion.
11m
5m
6m
13m
heightoftrapezoid=15m.
AreaofTrapezoid=
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=180π’ŽπŸ Areaoftherectangle=bh
=6(5)
=30π’ŽπŸ Areaoftheshadedregion=AreaofTrapezoid–AreaofRectangle
=180π‘š! -30π‘š! =150π’ŽπŸ 3)Findthecircumferenceandareaofacirclethathasaradiusof6cm.
r=6cm
d=6(2)=12cm
C=πœ‹π‘‘
A=πœ‹π‘Ÿ ! C=3.14(12) A=3.14(6! )
C=37.68cm A=3.14(36) A=113.04π’„π’ŽπŸ Answerin𝝅 Answerin𝝅 C=12𝝅
A=36𝝅
4)Ifacirclehasanareaof70π’Šπ’πŸ ,whatisthediameter?
𝐴 = πœ‹π‘Ÿ ! FORMULA
70=3.14π‘Ÿ ! Pluginwhatyoudoknow.
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Dividebothsidesby3.14.
22.29=π‘Ÿ ! Squarerootbothsides.****π‘Ÿ ! =r(r)
22.29 = π‘Ÿ ! 4.72in=r
diameter=radiusx2
d=4.72(2)
d=9.44in
5)
7ft
A=Areaofasemicircle+Areaofarectangle
8ft
Areaofthecircle=πœ‹π‘Ÿ ! Areaofthesemicircle=
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Diameter=7ft
Radius=7/2=3.5ft
Areaofsemicircle=
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=19.23π’‡π’•πŸ Areaoftherectangle=bh
=(8)(7)
=56π’‡π’•πŸ TotalAREA=19.23π’‡π’•πŸ +56π’‡π’•πŸ =75.23π’‡π’•πŸ