Ka = tan(45-
2
8.13
=0.271
P1 = 0.271 30 = 8.13 KN/m2
29.81
P2 = 0.271 (30+4 20) = 29.81 KN/m2
P3 = 0.271 (30+4 20+10 11.7) = 61.517 KN/m2
61.51
7
V1
V2
V3
V5
V6
V7
V4
Note : ɣcon. = 24-9.8 = 14.2 KN/m3
V1
V2
V3
V4
V5
V6
V7
Σ
H1
H2
H3
H4
Σ
Force KN/m
=2*2*24=96
= 2*3.5*24= 168
= 7*5*14.2= 497
= 3*9*14.2=383.4
=2*5*20=200
=3.5*2*20=140
=2*7*11.7=163.8
1648.2
Force KN/m
=8.13*4=32.52
=0.5*21.68*4=43.36
=29.68*10=296.8
=0.5*31.707*10=158.535
531.215
Arm
3
3.75
4.5
4.5
6.5
7.25
8
Arm
12
11.33
5
3.33
Moment
288
630
2236.5
1725.3
1300
1015
1310.4
8505.2
Moment
390.24
491.27
1484
527.92
2893.43
Point of application of resultant:
a=
= 3.405m from left side
centroid of pile group n = 6 pile each strip
C=
= 3.33m from left side
Eccentricity e=3.33- 3.405=-0.075
I = 2*[(2.33)2 + (0.83)2 ] + (1.67)2 + (4.67)2 = 30.7 pile.m2
ΣV = 1648.2*4= 6592.8 KN
ΣH = 531.215*4= 2124.86 KN
ΣM = 6592.8*-0.075= -494.46 KN
Q=
QA = 1098.8+ 16.11*(-2.33) =1061.26
α=18.43
QB = 1098.8+ 16.11*(-0.83) =1085.43
cosα=0.95
QC = 1098.8+ 16.11*(+1.67) =1125.7
QD = 1098.8+ 16.11*(+4.07) =1164.37
QA =
= 1117.12
QB =
= 1142.56
QC =
= 1184.95
not OK
OK
OK
not OK
Unbalanced the force = 2124.86 –
= 318.5 < 6*110
1061.26 + 1085.43
OK