EVAPORATION AND TRANSPIRATION (70% of annual budget) Evaporation: - change of liquid to vapor from a free water surface (net) Transpiration: - change of liquid to vapor through a plant - main loss for storms - major loss for annual budgets - incorporation of water into plant tissue - consumptive use (note: not the consumptive use defined by the SWFWMD) Sublimation - the change in phase from solid to vapor change mross/work/coursewk/watres/notes/notes4.ovh 1 TRANSPIRATION - function of vegetation type, degree of cover, soil & moisture conditions e/ z very large gradient; basic driving process for pumping water through the plant Order of Importance, for planning (Ref. Plant Physiology, Salisbury & Ross, Chapter 3): 1. Vapor pressure gradient at leaves (20 - 30 atms) 2. Osmosis at roots (<= 8 atms) 3. Capillarity (<= 1 atm) 1 atm mross/work/coursewk/watres/notes/notes4.ovh 2 33 ft Transpiration Modeling Assume: - upper limit to rate at which moisture can be moved to leaves = Qi f(plant) (pumping) - upper limit at which atm can "absorb" water; upper limit to evap. into atm = potential evapotranspiration = PET If PET > Qi - remove water until wilting occurs, soil moisture wilting point If Qi > PET - remove at rate = PET Sometimes transpiration is evident in well records: mross/work/coursewk/watres/notes/notes4.ovh 3 EVAPORATION Ways to handle evaporation: Diffusion (mass transfer) Water budget (mass balance) Energy budget Measure in field (pan evap.) Combination of methods 1) Diffusive Process Diffusion - transport from high concentration to low concentration Ts - water temperature (assume vapor is at Ts) ea - atmospheric concentration of vapor (vapor pressure) - real profile is very sharp - build up vapor layer at the surface - increase time until increase flux of vapor (by diffusion) = evaporation rate mross/work/coursewk/watres/notes/notes4.ovh 4 Evaporation as a Diffusion Process (cont.) Flux = - K (dc/dz) K increases as wind increases Diffusive Process but don't measure v Em - mass flux of vapor [mass/area-time] v - absolute humidity (vapor density) K - eddy diffusivity [length2/time] -vapor pressure - e is measurable mross/work/coursewk/watres/notes/notes4.ovh 5 Problems: - where is dz measured? - what is K? hard to measure (function of wind speed) - leads to equations of the following form (empirical): - Dalton's Law; Stelling, 1882; Diffusion method es = saturation vapor pressure at the water surface temp, Ts ea = vapor in atm E = evaporation rate R.H. x es (es is f(Tatm)) "velocity" [length/time] (in/hr) w = wind speed @ specific height a, b = empirical coefficients (see Table 2-2) Ex. TVA region - Rohwer worked well a = 0.308 (in./day)/(in. Hg) b = 0.0827 (in./day)/(mph-in. Hg) e - in. Hg E - in./day - agrees with handout for atm Patm = 29.92 in. Hg mross/work/coursewk/watres/notes/notes4.ovh 6 mross/work/coursewk/watres/notes/notes4.ovh 7 Name Formula Units Time Remarks Lake Hefner E=6.25x10-4W(es - ea) cm/3 hr, knots, mb 3 hrs Day Lake Hefner, Ok. 2587 acres, Good agreement with Lake Mead (138), Lake Eumbene, Russian Lakes (Dalton) Kohler E=.00304W(es - ea) in/day, mi/day, in Hg Day Lake Hefner, Ok. 2587 acres, Essentially the same as the Lake Hefner Zaykov E=(.15+.1W)(es-ea) mm/day, m/s, mb Meyer E=C(es-ea)(1+.1W) in/month, mph, in Hg Monthly Small Lakes and Reservoirs, ea is obtained daily from mean morning and evening measurements of Ta, RH. Increase constants by 10% If ave. of max and min are used. Morton E=(300+50W)(es-ea)/p in/month, mph Monthly Class A pan, Data from meteorological stations. Measurement Heights assumed. Rohner E=.771 (1.465-.0186B) (.44+.118W)(es-ea) in/day, mph, in Hg Daily Pans 85ft diam. tank 1300 acre reservoir, Extensive pan measurements using several types of pans. Correlated with tank and reservoir data. Ponds & Small Reservoirs, Based on Russian experience. Recommended by Shulyakovskiy W - a function of the horizontal wind speed es - the saturation vapor pressure at the water surface temperature ea - the vapor pressure of the overlaying air B - atmospheric pressure mross/work/coursewk/watres/notes/notes4.ovh 8 mross/work/coursewk/watres/notes/notes4.ovh 9 2) Water Budget Method - conservation of mass; basis for all simple hydrology 3) - measures inflows, determines all outflows and changes in storage can determine E - careful about units (volume ac of area) - change in storage ( S/ t) may be mross/work/coursewk/watres/notes/notes4.ovh 10 [ac-ft] - 1 ft of water over 1 zero for annual budget 3) Energy Budget Method - more rigorous, most popular for long-term modeling - try to find all energy sources: sun, atmosphere, inflows, discharges Ein - mross/work/coursewk/watres/notes/notes4.ovh Eout = S/ T (per unit area) 11 Energy In: Long waves - heat; convert sun's short wave radiation to long wave in the atmosphere; some of this long wave radiation is incoming to the lake Short waves - majority of energy we feel from the sun; visible light, infrared, heat waves from sun; incoming and reflected Qs - Qr = Incoming - reflected short wave radiation = Qs (1 - A) where A = Albedo Qa - Qar =Incident - reflected long wave radiation (primarily from atm) Qv = net advection by inflows - outflows mross/work/coursewk/watres/notes/notes4.ovh 12 Energy Out: Qvs Qh = = = Long wave back radiation Combined convection and conduction (mostly heat loss) of sensible heat from surface - airCsp.heat airK(dTa/dz) where K is turbulent diffusivity Heat from a stove - long wave radiation Energy in Lake: dSE/dt = dQo/dt = (1/Asurface) V - volume of water in lake Tw - temperature of water Cpw - specific heat of water Cpw(dV/dt)Tw w 1 cal/goC Max flux <<< 1.94 cal/cm2sec (1.94 is if you could capture all energy incoming) mross/work/coursewk/watres/notes/notes4.ovh 13 Energy Loss from Evaporation: Le = Latent Heat of Vaporization - add to ENERGY OUT Qe + Qw = QE = wCpwTwE + LeE = Advective Evap. Loss + Latent Heat Loss Waterways cooler than ambient air temp. because losing heat in evaporation. E = Evap. Loss = volume flux [in/hr] mross/work/coursewk/watres/notes/notes4.ovh 14 4) Field Measurement - Open Pan Evaporation - Measured daily - Annual pan total in Florida - Annual actual total in Florida - Different because: 60 - 70 in/yr 50 in/yr pan water temp. > lake water temp. pan vapor pressure diff. > lake v.p.d. - Actual evap. = pan coefficient x pan evap. - What is the pan coefficient? lakes Most common is 0.7 for - Other examples: Reference Weaver & Stevens (ref 45) Brutsaert (ref 43) Texas (ref 44) S. F. Shih et. al. mross/work/coursewk/watres/notes/notes4.ovh Pan coeff. 0.77 (St. Augustine grass) 0.85 - 1.04 (Bell peppers) 0.8 (grass, cloves) 1.2 (oak "woods") 0.7 (with Penman eq) 15 Recommendation: Penman eq. worked best for Florida; Actual ET = pan coeff. x Penman value See handout for Florida stations See Brutsaert, p. 253-4, for ways to improve pan estimates for lakes if measure pan temp., lake temp., and air temp. 5) Combining Methods - can simplify Diffusion Method + Energy Budget Method = Penman Equation (Review in text) Concentrate on evap. from open waterways THEN correlate between evaporation from open waterways and evapotranspiration mross/work/coursewk/watres/notes/notes4.ovh 16 EVAPOTRANSPIRATION - combined land surface E loss - function of Potential Evaporation or PET - similar to lake E formula - some argument whether Elake = PETland - function of plant community type - more succulent plants have higher ET - f (atmospheric conditions, insolation, temp, wind, humidity) - f (available soil moisture) - especially in root zone Potential Evapotranspiration (PET) For given atmospheric conditions (i.e., temperature, mixing, wind speed, humidity), it is the maximum ET rate possible. It is a function of atmospheric conditions, not so much land use or vegetation. Evaplake PET for a given region In central Florida: Evaplake 50"/yr PET See Appendix - TABLE I, Florida stations (mean monthly, seasonal, ...); Table 5-2, Summary of pan coefficients, Hydrology for Engineers, Linsley 1982 p.151 mross/work/coursewk/watres/notes/notes4.ovh 17 Actual ET (AET) AET < PET For Florida AET 35"/yr (about 70% PET) First, determine PET (atmospheric conditions). Then, consider all other factors that may effect it (vegetation, land use, etc.): 1) 2) 3) 4) - atmosphere - f(humidity, temperature, insolation, wind) plant community - higher for lush vegetation, depth of roots available moisture supply - rainfall, surface water, and soil water in root zone PET ET rates capped by high humidity even though temps. are higher and more water available. Decrease humidity, increase ET rate Insolation - incoming solar radiation, f (cloudiness, latitude) Plants (sparse vs. lush vegetation, more or less leafy) Available moisture supply, mross/work/coursewk/watres/notes/notes4.ovh 18 wp < fc - moisture content, associated with the wilting point of plants, may be around 0.005, decrease , increase neg. pressures - osmotic conditions in soil, can't get water up from roots - field capacity, total amount it can hold under the action of gravity; maximum soil moisture that can occur under action of gravity under wetting; if allow soil column to drip dry, fc is the moisture content remaining; f(soil composition, grains, % org., etc.) wp fc < Irrigation - only want to irrigate fc wp , fc - << fc - may be approx. 15% sat influence losses at root zone Evaporation - influences losses at surface mross/work/coursewk/watres/notes/notes4.ovh 19 Consumptive Use Hamon, Blaney-Criddle (see Viessman & paper by Shih et. al.) See Appendix - Agricultural Consumptive Use Explained, SWFWMD Hydroscope Oct. 1975 - ALL water that leaves property by ET or runoff Does not include water which infiltrates and recharges groundwater ET rate, 40 - 50 in/yr Total Consumptive Use, CU CU = water lost by irrigation + water lost by ET Total C.U. = Qp * Ka + CUc * A (irrigation) + (ET loss) Ka = f (irrigation method) For a crop in central FL: mross/work/coursewk/watres/notes/notes4.ovh Total ET = "natural ET" + amount above natural natural ET = 39 in/yr 20 Table II gives ET above natural e.g., CUc = 10.6 in/yr = 790 gpd/ac Allowed pumping rate = annual precip. - annual natural ET = 52.5 in/yr - 39 in/yr = 13.5 in/yr = 1000 gpd/ac - can pump the annual recharge e.g., - Own 240 acres, put citrus on 200 ac, irrigate by daytime sprinkling - Allowed to pump 240 x 1000 = 240,000 gpd (allowed to "use" this amount) Actually pump 300,000 gpd How much is consumed? Actual CU = 300,000 * 0.25 + 790 gpd/ac * 200 ac (= Qp * Ka + CUc * Acrop) = 233,000 gpd < 240,000 gpd (allowed) OK mross/work/coursewk/watres/notes/notes4.ovh 21
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