Secondary II Term 2 Final Review Key 1. concave down (opens

Secondary II Term 2 Final Review Key
1. concave down (opens down)
24. π‘₯ = 5
Vertex is a maximum at (0,4)
25. π‘₯ β‰ˆ 5.07 𝑓𝑒𝑒𝑑
Zeros / x-intercepts / roots (-2,0)(2,0)
26. 𝐴(𝑀) = 𝑀(40 βˆ’ 2𝑀)π‘œπ‘Ÿ 40𝑀 βˆ’ 2𝑀 2 π‘œπ‘Ÿ βˆ’ 2𝑀 2 +
40𝑀
Y intercept (0,4)
27. Austin is correct – not enough information
a=-1, b=0, c=4
28. 100 𝑓𝑑 β„Žπ‘–π‘”β„Ž
2a. yes
29. 2.5 seconds
2b. yes
3. yes pythagorean theorem 32 + 42 = 52
31. Part of Problem missing DO NOT DO
4. sides: √3, 2, 1
32. quadratic
5. 8√2
6. (βˆ’1,0)(βˆ’3,0)
33. linear
7. (βˆ’2,4)
8. (0, βˆ’12)
34. 𝑔(βˆ’2) = 4
9. 𝑓(π‘₯) = βˆ’4(π‘₯ + 2)2 + 4
π‘₯
35. sin 42 = 25
10. 𝑓(π‘₯) = βˆ’4(π‘₯ + 1)(π‘₯ + 3)
11. parabola that opens up or is concave up (smiley)
12. sin 𝐡 =
30. 5 seconds
37. 900
𝑏
𝑐
2
13. π‘ π‘‘π‘Žπ‘›π‘‘π‘Žπ‘Ÿπ‘‘ π‘“π‘œπ‘Ÿπ‘š: 𝑓(π‘₯) = π‘₯ + 2π‘₯ βˆ’ 8
2
π‘£π‘’π‘Ÿπ‘‘π‘’π‘₯ π‘“π‘œπ‘Ÿπ‘š: 𝑓(π‘₯) = (π‘₯ + 1) βˆ’ 9
π‘“π‘Žπ‘π‘‘π‘œπ‘Ÿπ‘’π‘‘ π‘“π‘œπ‘Ÿπ‘š: 𝑓(π‘₯) = (π‘₯ + 4)(π‘₯ βˆ’ 2)
14. π‘₯ = βˆ’3
15. π‘…π‘Žπ‘›π‘”π‘’ [3, ∞) π‘œπ‘Ÿ 𝑦 β‰₯ 3
16. (1, ∞) π‘œπ‘Ÿ π‘₯ > 1
17. π‘π‘œ sin 42 =
36. 158⁰
π‘₯
25
18. 14.17 𝑖𝑛
19. Part of problem missing Do Not Do
20. 443.17 π‘š π‘‘π‘Žπ‘™π‘™
21. max π‘Žπ‘Ÿπ‘’π‘Ž 56.25 π‘ π‘žπ‘’π‘Žπ‘Ÿπ‘’ 𝑓𝑒𝑒𝑑
22. π‘€π‘–π‘‘π‘‘β„Ž 𝑖𝑠 7.5 𝑓𝑒𝑒𝑑 π‘Žπ‘›π‘‘ π‘™π‘’π‘›π‘”π‘‘β„Ž 𝑖𝑠 7.5 𝑓𝑒𝑒𝑑
23. 50 π‘ π‘žπ‘’π‘Žπ‘Ÿπ‘’ 𝑓𝑒𝑒𝑑
38. 2π‘₯
39. 700
40. π‘₯ = 6
41. 9.42 π‘π‘š2
Μ‚ = 134⁰
42. π‘šπΉπΈπ·
43. tangent line
44. 4.5πœ‹
45. βˆ πΎπ‘‚πΏ
46. 19.7 π‘š
47. (π‘₯ βˆ’ 4)2 + 𝑦 2 = 9
48. 29π‘π‘š
49. 660
50. π‘₯ = 68⁰