March 08, 2012
10-3
1.) Use log
10
5 = 0.6990
and
log 7 = 0.8451
10
to find log10 35
2.) Use log 8 = 1.1606
6
and log 32 = 1.9343 to
6
approximate the value of log6 4
March 08, 2012
3.) Use log5 2 = 0.4307 to approximate the value of log5 250
4.) Given log 6 = 1.1133, approximate the value of log 216
5
5
March 08, 2012
Solve each equation
5.) A.
B.
4 log2 x - log2 5 = log2 125
log8 x + log8 (x-12) = 2