Maths AS Mathematics Flying Start Assignment Video examples of all these topics are available on examsolutions.net, click on the links 1. Expand & Simplify (a) (x + 2)(x + 3) (d) (3x + 5)(x + 7) 2. Factorise the following quadratic expressions (a) x2 + x (b) (d) x2 + 5x β 24 (e) 3. Solve the following quadratic equations (a) x2 - 6x + 8 = 0 (b) (d) x2 + 8x = 0 (e) 4. Find the following in their simplest form (a) 32 + 45 5. Express as a single fraction and simplify (b) 1 3π₯ 2 4 β (b) (b) 5 (x β 3)(x β 4) (c) (x - 3)(x + 5) (e) (f) (4t - 5)2 x2 + 7x + 10 (c) x2 - 9x + 14 3x2 + 17x + 20 (f) x2 β 16 x2 + x β 30 = 0 (c) 2x2 + x β 15 = 0 x2 β 25 = 0 (f) x2 + 28 = 11x 2 76 β 37 2π₯ (c) 3 6. Express in the form (a) x2 + 8x + 17 (b) (q - 3)(q + 3) 1 (c) 1 3π₯ + 6 β 54 1 2π₯ (π₯ + π)2 + π x2 β 4x + 10 (e) 1 π₯+2 + 1 π₯+3 where p & q are integers 7. Solve each pair of simultaneous equations: (a) x + 4y = 7 2x + 3y = 9 (b) 3x + 2y = 8 2x β y = 3 8. Use substitution to solve these pairs of simultaneous equations (a) y = 3x2 y β 2 = 5x 9. Simplify: (a) β8 (b) (b) β12 (c) β50 10. Expand and simplify (a) (β5 + 2) (β5 - 2) 11. Evaluate (a) 162 12. (a) 13. (a) 1 (b) Write in the form 10 βπ₯ (b) (b) 2 83 ππ₯ π xy = 5 y = 2x+3 (e) β32 2 (f) (2 + β3 )2 (c) (c) 1 100β2 β200 + β18 β β72 (1 + β2) (3 β 2β2) (d) where a and n are constants 8 π₯3 (c) (b) 2π₯ find The gradient of AB (example) (c) The equation of the line AB (example) (d) The gradient of a line perpendicular to AB (example) (e) The equation of the perpendicular bisector of AB (example) 1 e.g. 10βπ₯ = 10π₯ 2 1 For the two points A (2,3) and B(4,11) The midpoint of AB (example) 3 4β2 Maths AS Further Mathematics Flying Start Assignment You must first complete the AS Mathematics Flying Start Assignment. In addition to this you need to find out a little about complex numbers. Watch the following you-tube clips: https://www.youtube.com/watch?v=oxF5VQSA4Hw https://www.youtube.com/watch?v=-IJuqR6nz_Q http://www.examsolutions.net/maths-revision/further-maths/complexnumbers/introduction/tutorial-1.php (Donβt worry about the cubic) Try to solve the following equations, some are straight forward, some require more thought: 1. π₯π₯ 2 = β25 2. π₯π₯ 2 + 8 = 0 3. (π₯π₯ β 2)2 = β4 4. π₯π₯ 2 β 4π₯π₯ + 8 = 0 5. π₯π₯ 2 + 6π₯π₯ + 5 = 0 6. π₯π₯ 2 + 3π₯π₯ + 3 = 0 7. 2π₯π₯ 2 + 8π₯π₯ + 9 = 0 8. π₯π₯ 2 = 2ππ 9. π₯π₯ 4 = 1 10. π₯π₯ 3 = 1
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