ME-GATE-2016
GATE 2016 – A Brief Analysis
(Based on student test experiences in the stream of ME on 31st
January, 2016 – (Forenoon Session)
Section wise analysis of the paper
Section Classification
1 Mark
Engineering Mathematics
Engineering Mechanics
Strength of Materials
Design of Machine Elements
Theory of Machines
Vibrations
Fluid Mechanics
Thermal Science
Heat Transfer
Manufacturing Science
Industrial Engineering
Verbal Ability
Numerical Ability
5
1
2
1
2
1
3
1
3
4
2
3
2
30
2 Marks
4
4
3
1
1
1
3
4
3
4
2
2
3
35
Total No of
Questions
9
5
5
2
3
2
6
5
6
8
4
5
5
65
Type of questions asked from each section
Engineering Mechanics
Questions came from Free body diagrams.
Strength of materials
Questions came from 2D stress, Bending equation
Machine design
Questions came from Bearings.
Theory of machines
Questions came from Degrees of freedom for links,
Balancing.
Vibrations
Questions came from Resonance, single degree of freedom
of free vibration.
Fluid mechanics and Hydraulic
machines
Questions came from Stream lines, Boundary layer, Impact
of jet, Branched piper.
Thermal science
Questions came from Air compressors, vapour
compression refrigeration system, SFEE, Psychrometry.
Heat transfer
Questions came from composite slabs, Lumped system
analysis, Dimensions less numbers, Radiation, Heat
exchanger.
Manufacturing
Questions came from Machining, Casting, Punching,
welding and Material science.
Industrial Engineering
Questions came from NC codes, PERT, LPP, Forecasting.
Disclaimer – This paper analysis and questions have been collated based on the memory of some students who appeared in the
paper and should be considered only as guidelines. GATEFORUM does not take any responsibility for the correctness of the
same.
1
ME-GATE-2016
Questions from the Paper
General Aptitude
1.
Key:
Exp:
S, P, M and E are four persons, working on project efficiency of M is twice that of others and M
works only for half of the total days worked by E. M works 6 hours/day and E works 12
hours/day. Ratio of contribution of work to project of M and E is (i.e., work done by
M work done by E)
(A) 1 : 1
(B) 1 : 2
(A)
M - 6hr day  1 unit of work
(C) 1 : 4
(D) 1 : 3
E  12h day  1 unit of work
M 1

E 1
2.
Key:
3.
Key:
4.
Key:
Exp:
Mr. X has height 6 feet and Mr. Y has 4 feet. Identify the correct statement
(A) Mr. X is longer than Mr. Y
(B) Mr. X is taller than Mr. Y
(C) Mr. X is bigger than Mr. Y
(D) Mr. X is higher than Mr. Y
(B)
The teacher was ________ on teacher’s day for her work.
(A) Facilitated
(B) Felicitated
(C) Fascinated
(B)
(D) Facillitated
Two hours and 15 min back, reflection of wall clock is viewed in the mirror which shows 1:30.
The actual present time in the clock is
(A) 8:15
(B) 11:45
(C) 12:15
(D) 12:45
(D)
If reflection is seen as
1: 30
Actual will be
10 : 30
Thus present time will be 10 : 30  2 :15 12 : 45
Disclaimer – This paper analysis and questions have been collated based on the memory of some students who appeared in the
paper and should be considered only as guidelines. GATEFORUM does not take any responsibility for the correctness of the
same.
2
ME-GATE-2016
5.
Exp:
A wire of length 340 mm is cut into two pieces. One piece in used to form a square and other
piece is used to form a rectangle whose sides are in the ratio of 1: 2. Determine the side of square
if combined area of square and rectangular is minimum (in mm)
(A) 30
(B) 40
(C) 180
(D) 160
x  y  340
 x 2x 
Perimeter of rectangle  2     2x
3 3 
Perimeter of square  340  2x
340  2x
Length of square 
4
 340  2x  2 2
Totalarea  
  x  f (x)
4

 9
4
2x  340
f '(x)  x 
0
9
4
4
1
 x   340  2x   x  90
9
4
340  2x
 40mm
Length of square 
4
x
2 x/ 3
x
2
Square
x/ 3
Rectangle
Technical
1.
A cylindrical steel rod of 0.01m in diameter and 0.2m in length is first heated to 750oC and then
immersed in a water bath at 100oC. The convective heat transfer coefficient is 250 W m 2 K . The
density specific heat and thermal conductivity are 7801 kg m3 , 473 J/kg K and 43 W mK
Key:
Exp:
respectively. The time required for the rod to reach 300oC is _____ seconds
43.49
d = 0.01 m
L = 0.2m, R=7801 kg/m3.
t i  750o C, C  473J / kgK
t   100o C, k  43 W / mK
 2
d
V
d
h  250 W / m2 K, Lc   4

A d 4
 t  t   hA
h
ln 
 


cLc
 t i  t   Vc
 t  t   h  4
ln 


 t i  t   c  d
250  4
 300  100 
ln 


 750  100  7801 473  0.01
  43.49s
Disclaimer – This paper analysis and questions have been collated based on the memory of some students who appeared in the
paper and should be considered only as guidelines. GATEFORUM does not take any responsibility for the correctness of the
same.
3
ME-GATE-2016
2.
Key:
3.
Key:
Exp:
4.
Key:
Exp:
Internal gears are manufactured by
(A) Hobbing
(B) Shaping with pinion cutter
(C) Shaping with rack cutter
(D) Milling
(A)
Grashoff number signifies the ratio of
(A) inertia force to viscous force
(C) buoyancy force to inertia force
(D) Inertial force to surface tension force
(B)
Inertia force  Buoyant force
Grashoff number (Gr) 
(Viscous force) 2
Engineering strain of a mild steel sample is recorded has 0.100%, the true strain is
(A) 0.010 %
(B) 0.055%
(C) 0.099%
(D) 0.101%
(C)
0.1

100
We know,
T  ln 1    , where T is True strain and  is Engineering strain
0.1 

 T  ln 1 
  0.0009995
 100 
5.
Key:
6.
Key:
Exp:
(B) buoyancy force to viscous force
T %  0.0009995  100  0.099%
Which of the bearings given below should not be subjected to a thrust load?
(A) Deep groove ball bearing
(B) Angular contact ball bearing
(C) Cylindrical roller bearing
(D) Single row tapered roller bearing
(C)
A sheet metal of 2 mm thickness, a hole of 10 mm diameter needs to be punched. Yield strength
in tension of the sheet material is 100 MPa and its ultimate shear strength is 80 MPa. The force
required to punch the hole (in kN) is _____
5.0265
t  2mm
d  10mm
s  80MPa
Syt  100MPa
F dt  s   10  2  80  5026.5N  5.0265kN
Disclaimer – This paper analysis and questions have been collated based on the memory of some students who appeared in the
paper and should be considered only as guidelines. GATEFORUM does not take any responsibility for the correctness of the
same.
4
ME-GATE-2016
7.
In a 3-stage air compressor, the initial pressure is P1, discharge pressure is and the intermediate
pressure are P2 and P3  P2  P3  . The total pressure ratio is 10 and the pressure ratios of stages
where equal. If P1  100kPa, the value of P3  in kPa  is ______
Key:
Exp:
464.16
3 stage compressor;
P1= 100 kPa.
Pressure ratios of all stages are equal
P2 P3 P4
 
P1 P2 P3
Overall pressure ratio 
 rp 
P4
 10
P1
P2 P3 P4 3
   10  2.154
P1 P2 P3
P3  (rp )2  P1
 P3  2.514  2.514 100  464.16kPa
8.
Key:
Exp:
In a single point turning operation with cemented carbide tool and steel work piece, it is found
that the Taylors’ exponent is 0.25. If the cutting speed is reduced by 50% then the tool life
changes by ___ times
16
n = 0.25
V
V2  1
2
V1T1n  V2T2n
V1T1n 
V1 n
T2
2
 T2 
 T
1

0.25
2
T2  T1  24
T2  16  T1
Tool life changes by 16 times
9.
Key:
In PERT chart, the activity time distribution is
(A) Normal
(B) Binomial
(C) Poisson
(D) Beta
(D)
Disclaimer – This paper analysis and questions have been collated based on the memory of some students who appeared in the
paper and should be considered only as guidelines. GATEFORUM does not take any responsibility for the correctness of the
same.
5
ME-GATE-2016
10.
A force F is acting on a bent bar which is clamped at one end as shown in figure.
60o
The correct Free body diagram is
(A)
(B)
60
60o
o
F
Ry
Ry
Rx
Rx
M
M
(C)
60o
60o
(D)
F
F
Ry
Ry
Rx
M
Key:
Exp:
(A)
A free body diagram is the diagram in which all connecting pieces are removed.
Correct option is (A) because the fixed support will give reaction of forces in x and y direction
and moment also.
Disclaimer – This paper analysis and questions have been collated based on the memory of some students who appeared in the
paper and should be considered only as guidelines. GATEFORUM does not take any responsibility for the correctness of the
same.
6
ME-GATE-2016
10.
The cross-section of solid bar, made up of same material as shown in the figure, the square crosssection has flexural (bending) rigidity I1, while the circular cross-section has flexural rigidity I2,
I
both section have the same cross-section the ratio of 1 is
I2
(A)
Key:
Exp:
1

(B)
2

(C)

3
(D)

6
(C)
Flexural rigidity = EI
Both have same cross-section area

 a 2  d 2 where a is side of square and d is diameter of circle.
4
2 4
d
16
2 d 4
a4
E1 
I
12  12  16  
 1 
 4
I2
3
d 4
d
E2 
64
64
 a4 
11.
Key:
12.
( E1  E2 because of same material)
Match the following part programming code with the respective functions
PPC
Function
P. G01
I. Spindle stop
Q. G03
II. Spindle rotation clockwise
R. M03
III. Circular interpolation anticlockwise
S. M05
IV. Linear interpolation
(A) P-II, Q-I, R-IV, S-III
(B) P  IV,Q  II,R  III,S  I
(C) P-IV, Q-III, R-II, S-I
(C)
(D) P-III, Q-IV, R-II, S-I
The state of stress at a point on an element is shown figure (a). The same of stress is shown in
another coordinate system in figure (b).
 yy
p
xy
p
 xx
45o
p
p
a 
xy
 xx
xy
xy
 yy
b
Disclaimer – This paper analysis and questions have been collated based on the memory of some students who appeared in the
paper and should be considered only as guidelines. GATEFORUM does not take any responsibility for the correctness of the
same.
7
ME-GATE-2016
The component of  xx , yy , xy  is
Key:
Exp:
 P P 
(A) 
,
,0 
 2 2 
(B)
We know,
(B)
 0,0,P
P 

(C)  P,  P,

2

P 

(D)  0,0,

2

 x   y   x   y 
  

 cos 2  xy sin 2
2  
2 

Where,  is the location of any oblique plane which making an angle  in CCW direction.
 When   45o ,   xx ,  x  p,  y  p
pp pp
  xx  
 
 cos90  0
 2   2 
When   45O ,  yy
pp pp
  
 
 cos90  0
 2   2 
When   45O ,   xy
 x   y 
We know   
 sin 2  xy cos 2
 2 
pp
   xy  
 sin 90  p
 2 
xx , yy , xy is 0, 0,p
14.
The number of degree of freedom in a planar mechanism having n links and j simple hinge joints
is
(A) 3 n  3  2j
(B) 3 n  1  2j
(C) 3n  2j
(D) 2j  3n  4
Key:
(B)
15.
In wire-cut EDM process, the necessary condition that have to met for making successfully cut
are that
(A) Wire and sample are electrically non-conducting
(B) Wire and sample are electrically conducting
(C) Wire is electrically conducting and sample is electrically non-conducting
(D) Sample is electrically conducting and wire is electrically non-conducting
(D)
Key:
16.
Key:
The static defect of a spring gravity, when a mass of 1 kg is suspended from it is 1 mm. Assume
the acceleration due to gravity, g = 10 m/s2. The natural frequency of this spring mass system (in
rad/s) is _____
100
Disclaimer – This paper analysis and questions have been collated based on the memory of some students who appeared in the
paper and should be considered only as guidelines. GATEFORUM does not take any responsibility for the correctness of the
same.
8
ME-GATE-2016
Exp:
  1mm
g  10m s2
n  g
17.

10
 10 103 100rad s
3
10

Steady 1-D heat conduction takes place across the faces 1 and 3 of a composite slab consisting of
slabs A and B in perfect contact as shown in the figure, where k A ,k B denote the respective
thermal conductivites. Using the data as given in the figure, the interference temperature
T2  in oC is ____.
A
1
T1  130 C
2
o
k A  20 W/ mK
0.1m
Key:
Exp:
B
3
k B  100W / mK
T3  30o C
0.3m
67.5
T1  T2 T2  T3

LA
LB
kA  A kB  A
130  T2 T2  30

0.1
0.3
20
100
390  3T2  5T2  150
8T2  540
T2  67.5o C
 Interface temperature  67.5o C
18.
For a heat exchanger Tmax is the max temperature difference and Tmin
is the minimum
temperature difference between the two fluids LMTD is the log mean and maximum heat and
Cmax are the possible heat transfer (Qmax) between the two fluids is
(A) Cmin LMTD
(B) Cmin Tmax
(C) Cmax Tmax
Key:
Exp:
(D) Cmax Tmin
(B)
In a heat exchanger, maximum possible heat transfer will be.
Qmax  Cmin Tmax
Disclaimer – This paper analysis and questions have been collated based on the memory of some students who appeared in the
paper and should be considered only as guidelines. GATEFORUM does not take any responsibility for the correctness of the
same.
9
ME-GATE-2016
19.
Key:
Exp:
Steam at an initial enthalpy of 100 kJ/kg, and inlet velocity of 100 m/s, enters an insulated
horizontal nozzle. It leaves the nozzle at 200 m/s. The exit enthalpy (in kJ/kg) is _______
85
h1  100kJ / kg
2
C  100m / s
1
1
C2  200m / s
C12
C2
 h2  2
2000
2000
1002 2002
h 2  100 

 85kJ / kg
2000 2000
h1 
20.
Key:
Exp:
C1
C2
h1
h2
Spot welding of two steel sheets inch 2 mm thick is carried out successfully by passing 4kA of
current 0.2 seconds through the electrodes. The resulting weld nugget formed between the sheets
is 5 mm in diameter. Assuming cylindrical shape for the nugget, the thickness of nugget is
___mm.
Let end heat of fusion for steel
Effective resistance of weld joint density of steel
Latent Heat of fusion for steel
1400 kJ/kg
Effective resistance of weld joint
200
Density of steel
8000 kg/m3
2.91
t s  2mm
I  4kA
t  0.2
d  5mm
tn  ?
L.H 1400
R  200
  8000kg m3
Energy supplied = I2 Rt


3 2
 4  10
… (a)
 200  106  0.2  640J
Energy required for melting =  V   L.H 
… (b)

 1400  103  8000   52  106  t n  219911.4858t n
4
Equating (a) & (b)
640 = 219911.4858t n t n  2.91mm
Disclaimer – This paper analysis and questions have been collated based on the memory of some students who appeared in the
paper and should be considered only as guidelines. GATEFORUM does not take any responsibility for the correctness of the
same.
10
ME-GATE-2016
21.
Key:
Exp:
In a mixture of dry air and water vapour at a total pressure of 750 mm of Hg, the partial pressure
water vapour is 20 mm of Hg. The humidity ratio of air (in grams) of water vapour per kg of dry
 g

air  w.v  is______
 kg d.a 
17
Pt  750 mm of Hg
Pv  20 mm of Hg
Humidity ratio (or) specific Humidity
PV
w  0.622
Pt  PV
 20 
 0.622  

 750  20 
kg
 0.017 w.v
kg d.a
g
 17 w.v
kg d.a
22.
Two parallel plates are separated by a distance of 10 mm and temperature of one plate is 1000 K
and that of other is 400 K. If 1  0.5,  2  0.25 , the net radiation heat exchange between the plate
is kW m 2 is ______
Key:
11.049
Exp:
Q1 2
  T14  T24 

1 1
 1
1 2
T1  1000K
5.67  108 10004  4004 
1
1

1
0.5 0.25
 11049.696 W 2  11.049 kW 2
m
m
T2  400K

23.
Exp:
2  0.25
3k
. What is the ratio of
m
amplitude of excitation to the static deflection because of the forced excitation ____
In a single Degree of Freedom, excluded with a frequency of
k
Key:
1  0.5
m
Fosint
0.5
M.F  
1
 
1 
2

1
1
  0.5
1 3 2
n
Disclaimer – This paper analysis and questions have been collated based on the memory of some students who appeared in the
paper and should be considered only as guidelines. GATEFORUM does not take any responsibility for the correctness of the
same.
11
ME-GATE-2016
24.
Key:
Exp:
In an exponential smoothing forecast, if the demand for the month of April is 900 units and for
the month of May it is 1030 units, with smoothing constant of 0.6. The forecast for the month of
June is _______
(A) 850
(B) 927
(C) 910
(D) 970
(D)
April
May
Demand
900
1030
Forecast
850
FMay  FApr   DApr  FApr   850  0.6  50  880
FJune  FMay   DMay  FMay   880  0.61030  880  970
25.
In a normal distribution curve, the percentage area between +3 and -3 standard deviation value is
______
Key:
Exp:
99.74
3  99.74%
0
1  68.4%
2  95.45%

Disclaimer – This paper analysis and questions have been collated based on the memory of some students who appeared in the
paper and should be considered only as guidelines. GATEFORUM does not take any responsibility for the correctness of the
same.
12