Day 55_Test Review.notebook
November 30, 2015
10 cm
22
c
m
Find the total surface area
12 cm
2 cm
8 cm
12 cm
1
Day 55_Test Review.notebook
November 30, 2015
22
c
m
Find the total surface area
10 cm
12 cm
2 cm
8 cm
12 cm
2
Day 55_Test Review.notebook
November 30, 2015
10 cm
22
cm
Find the total surface area
12 cm
2 cm
8 cm
12 cm
3
Day 55_Test Review.notebook
November 30, 2015
Test
Wednesday, Dec 2
Square roots and perfect squares
Surface area of composite objects
4
Day 55_Test Review.notebook
November 30, 2015
Test
Square roots and perfect squares
Area of a square = (side)2 Side of square = √area of square
­ square root is 2.4 means find the perfect square # so multiply by itself
­ is it a perfect square take the square root and if the decimal stops or repeats then the number was perfect
­ square root of fraction take square root of top and bottom
or check top and bottom of a fraction
­ bench marks find the perfect square that the number falls between
Perfect Squares: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225
section 1.1 to 1.2
Surface area of composite objects
section 1.3 & 1.4
5
Day 55_Test Review.notebook
November 30, 2015
Area of square
The Area of a square is 625 m2, what is the length of the side?
6
Day 55_Test Review.notebook
November 30, 2015
Perfect Squares (1)2 = 1 x 1 = 1
(2)2 = 2 x 2 = 4
(3)2= 3 x 3 = 9
(4)2= 4 x 4 = 16
(5)2= 5 x 5 = 25
(6)2= 6 x 6 = 36
(7)2= 7 x 7 = 49
(8)2= 8 x 8 = 64
(9)2= 9 x 9 = 81
(10)2= 10 x 10 = 100
(11)2= 11 x 11 = 121
(12)2= 12 x 12 = 144
(13)2= 13 x 13 = 169
(14)2= 14 x 14 = 196
(15)2= 15 x 15 = 225
(16)2= 16 x 16 = 256
(17)2= 17 x 17 = 289
(18)2= 18 x 18 = 324
(19)2= 19 x 19 = 361
(20)2= 20 x 20 = 400
(21)2= 21 x 21 = 441
(22)2= 22 x 22 = 484
(23)2= 23x 23 = 529
(24)2= 24 x 24 = 576
(25)2= 25 x 25 = 625
7
Day 55_Test Review.notebook
November 30, 2015
What is the area of the following What is the area?
11
10
Square
11
10
What is the perimeter? 8
Day 55_Test Review.notebook
November 30, 2015
Area of square =
What is the length of the sides?
What it the perimeter of the square
9
Day 55_Test Review.notebook
November 30, 2015
You Try!!!!
For each area of a sqaure find the length of its side
**Find the square root
1)
2)
3)
4)
10
Day 55_Test Review.notebook
November 30, 2015
Warm Up Math 9
1) Find the perfect square whose square root is a) 0.6
b)
3
5
2) Is the following fractions or decimals perfect squares? Explain
a) 0.64 b) 62.5 c) 49
d) 13
144
25
11
Day 55_Test Review.notebook
November 30, 2015
Estimate the square root of 130
12
Day 55_Test Review.notebook
November 30, 2015
To Determine if a Fraction is a Perfect Square
BOTH Numerator and Denominator MUST be Perfect Square Numbers
***Simplify fractions first ***
Is each fraction a perfect square? Explain
a)
b)
c)
13
Day 55_Test Review.notebook
November 30, 2015
Identifying Decimals that are Perfect Squares
1.44
Method 1
Write the decimal as a fraction
Method 2
Use a Calculator.
Use the square root button Simplify the fraction. Divide the numerator and denominator by 4.
1.44
= 1.2
1.44 =
= X
Since the sqaure root is a terminating decimal then 1.44 is a perfect square.
THUS 1.44 is a perfect square
14
Day 55_Test Review.notebook
November 30, 2015
Without a calculator
Determine if the decimal is a perfect square?
1.69
perfect
square
0.016
not perfect
15
Day 55_Test Review.notebook
November 30, 2015
Calculate the surface area of the following shape: (Show ALL WORK) 2 cm
2 cm
2 cm
16
Day 55_Test Review.notebook
November 30, 2015
Calculate the total surface area of the following: (Show all work) 17
Day 55_Test Review.notebook
November 30, 2015
How much paint is needed to cover the following shape?
You try!!!
8 cm
15 cm
Overlap
20 cm
10 cm
30 cm
Cylinder Area of Cylinder = 2πr2 + 2πrh
15
4
4 2 + 2(3.14) (___) (___)
= 2(3.14) (___)
= 2(3.14) (_ 16__) + 2(3.14) (_ 4__) (15)
=
100.48 + 376.8
=
477.28
Rectangular Prism
Top
A = 30 cm x 10 cm
= 300 cm2
A = 20 cm x 30 cm
= 600 cm 2
A = 10 cm x 20 cm
= 200 cm 2
Total SA small = 2Top +2Side +2Front
= 2( 300cm2) +2(600cm2) + 2(200cm2)
= 600 cm2 + 1200cm2 + 400cm2
= 2200cm2
Overlap Area = πr2
= 3.14 (4)2
= 3.14 (16)
= 50.24
Total Surface Area = cylinder + Prism ­ 2(Overlap area)
=
=
=
=
477.28 + 2200 cm2 ­ 2( 50.24cm2 )
477.28 + 2200 cm2 ­ 100.48 cm2 2677.28 cm2 ­ 100.48 cm2
2576.8 cm2
18
Day 55_Test Review.notebook
November 30, 2015
19
Day 55_Test Review.notebook
November 30, 2015
Find the area of the warehouse with the attached storage space.
(Think if you were going to paint this....How much paint is needed???)
40 m
20 m
1 m
15 m
6 m
5 m
3 m
10 m
Step 1) Calculate the sides of all of the larger prism, So surface area of the storage space is:
Step 2) Storage space consist of 3 walls and a roof
So surface area of the storage space is:
20
Day 55_Test Review.notebook
November 30, 2015
Class / Homework
Review For Test
­ Handout: Surface Area Worksheet
Questions: 1­6 answers were on the board
­ Questions from Textbook:
page 45 ­ 46 #2(b, d, f, h)
#3(a,b,c,d,e)
#4(a,d)
#5 (a, c, e)
#6 (b,d)
# 7(ad)
# 12ac
#13ab
#15(bc)
#16(bc)
#19(a)
Page 48
# 5 Warehouse question
21