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Directions (Q.1-3): What will come in place
of the question mark (?) in the following
questions?
3
1
1
1. ⎯ of ⎯ of ⎯ of 30420 = ?
5
13
3
1) 362
2) 468
3) 344
4) 100
5) None of these
1
2
4
2. 3 ⎯ × 5 ⎯ ÷ 4 ⎯ = ?
5
3
5
2
4
1) 3 ⎯
2) 3 ⎯
3
5
2
4) ⎯
5) None of these
3
7
3)3 ⎯
9
6. What is the ratio between the total values of
quantity sold for items B & D respectively?
1) 3:4
2) 2:1
4) 5:3
5) 3:2
11. 6
8
135
3) 5:6
7. If the quantity sold of item C increased by
20% and the price reduced by 10% what was
the total value of the quantity sold for item C?
1
45
1) 8
2) 24
3) 12
4) 15
5) None of these
12. 8
19
173
2) Rs.68750 3) Rs.61875
1) 335
4) Rs.82500
5) None of these.
3) 85
13.
41
82
349
1) Rs.64575
8. Total value of the quantity sold for item
E is what percent of the total value of the
quantity sold for item A?
18
472.5
4
2) 82
4) 173
7
1) 7
2) 4
13
5) None of these
21
3) 33
31
4) 78
43
5) None of these
Find the original price of sugar ?
3. ? % of 584 = 21.9 × 16
1) 70.8
2) 40.2
3) 50
4) 60
5) None of these
Directions (Q.4-5): In each of the questions
below, two equations are provided. On the
basis of these you have to find out the relation
between P and Q.
Give answer 1) if P = Q Give answer 2) if P > Q
Give answer 3) if P < Q Give answer 4) if P ≥ Q
Give answer 5) if P ≤ Q
4. P2 - 16P + 63 = 0 ; 3Q2 - 23Q + 14 = 0
5. P (P+4) + 3 = P2 + 2P + 29 ; Q(Q-1) = Q2 -13
Directions (Q.6-10): Study the following graph
carefully and answer the question that follow.
Following graph gives the Quantity (in quintals)
of various items sold and price per kg.
35
30
ice
Pr
25
20
15
10
Qu
an
tity
5
0
A
B
C
D
E
F
EXPLANATIONS
3
1
1
1. ⎯ × ⎯ × ⎯ × 30420 = 468
5 13 3
1
2
4
2. 3 ⎯ × 5 ⎯ ÷ 4 ⎯
5
3
5
16 17
5
34
7
⇒⎯×⎯×⎯=⎯ =3⎯
5
3
24
9
9
?
3. ⎯ × 584 = 21.9×16
100
21.9×16×100
⇒ ? = ⎯⎯ = 60
584
4. P2-16P+63 = 0
⇒ P2-9P-7P = 0
⇒ (P-9)(P-7) = 0 ⇒ P = 9 or 7
3Q2-23Q+14 = 0
Q.APTITUDE
3) Rs.68750
8. Total value of E = 1750×Rs.30 = Rs.52500
Total value of A = 1500×17.5 = Rs.26250
52500
required% = ⎯ × 100 = 200%
26250
25+15+22.5
9. Average price = ⎯⎯ = 20.83
3
10. Total value of item C = 2500×Rs.27.5
= Rs.68750
Total value of item F = 1250×Rs.22.5
= Rs.28125
∴required difference = 68750-28125
= Rs.40625
11. 6 × 1.5 = 9
9 × 2 = 18
18 × 2.5 = 45
2
⇒ (3Q-2) (Q-7)=0 ⇒ Q=7 or ⎯
3
wrong number is 8
⇒ 2P = 26 ⇒ P = 13
Q(Q-1) = Q2-13
⇒ Q2-Q = Q2-13 ⇒ Q = 13
6. Value of the item = Quantity × Price
Value of item B = 1000kg × Rs.25
= Rs.25000
Value of item D = 2000×15 = 30000
required ratio = 25000:30000 = 5:6
7. Quantity sold by C after 20% increment
= 120%of2500=3000kg
4) Rs.47750
5) None of these
Direction (Q.11-15): In each of the
number series questions, one number is wrong. You have to identify
Quantity
sold in quintals that number and assuming that a
Price in new series starts with that number,
following the same logic as in the
Rs.Per kg
given series. Which of the numbers
given in (1), (2), (3), (4) and (5)
below each series will be the third
number in the new series?
45 × 3 = 135
⇒ P2+4P+3 = P2+2P+29
72
821
1) 72
137
262
135 × 3.5 = 472.5
8 × 1.5 = 12
12 × 2 = 24
∴ required number is 24
12. 8 × 2 + 3 = 19
19 × 2 + 3 = 41
41 × 2 + 3 = 85
85 × 2 + 3 = 173
173 × 2 + 3 = 349
wrong number is 82
82 × 2 + 3 = 167
167 × 2 + 3 = 337
∴ required number is 337
13. 22 - 1 = 3
2
4) ⎯
17
1) Rs.150
2) Rs.145
3) Rs.4350
4) Rs.4500
5) None of these
2) 163
3) 137
4) 173
5) None of these
1) 50%
2) 100%
15. 6 1.5
0.5
0.75
1.5 6
3) 25%
4) 200%
1) 1.25
2) 1.5
3) 0.1875
5) None of these
G.S.GIRIDHAR
4) 0.125
5) None of these
9. What is the approximate
16.
From
a
well
shuffled
pack
of cards two are
average price per kg of items, B, D & F?
drawn
at
random
one
after
the
other without
1) Rs.26
2) Rs.29
3) Rs.21
replacement. Find the probability that the
4) Rs.24
5) Rs.18
cards are spade cards.
10. What was the difference between the total
value of item C and the total value of item F?
2
1
17
1) ⎯
2) ⎯
3) ⎯
3
17
21
1) Rs.40625
2) Rs.28125
⇒ 3Q2-21Q-2Q+14 = 0
5. P(P+4)+3 = P2+2P+29
14. 46
478
18. There was a hostel for 30 boarders.
On the number of boarders being
increased by 10, the expenses of the
hostel increased by Rs.1300 per month,
while average expenditure per head
diminished by Rs.5. Find the original
monthly expenses.
5) None of these
17. Two pipes A and B can fill a cistern in 12
and 16 minutes respectively. Both pipes are
opened together but 4 minutes before the
cistern is full, pipe A is closed. How much
time will the cistern take to fill?
5
1) 9 ⎯ min
7
1
2) 8 ⎯min
3
1
3) 9 ⎯ min
7
4
4) 8 ⎯ min
7
5) None of these
..........
wrong number is 4
42 - 1 = 15
52 - 2 = 23
62 - 3 = 33
∴ required number is 33
14. 46 + 27 = 73
73 + 64 = 137
137 + 125 = 262
262 + 216 = 478
478 + 343 = 821
wrong number is 72
72 + 27 = 99
99 + 64 = 163
15. 6 × 0.25 = 1.5
1.5 × 0.5 = 0.75
0.75 × 1 = 0.75
19. A reduction of 20% enables a house wife to
buy 2kg more sugar for Rs.200. Find the
original price of sugar per kg?
1) Rs.25
2) Rs.18
3) Rs.20
4) Rs.24
5) None of these
20. A man deposits Rs 15600 in a bank at 8%
annual interest. After six months he withdraws Rs.8400 and after 12 months he
withdraws the remaining amount. How
much does he get as interest?
1) Rs.624
2) Rs.912
3) Rs.1200
4) Rs.1248
5) None of these
1) 2
2) 3
ANSWERS
3) 4
4) 4
5) 1
10) 1
6) 3
7) 5
8) 4
9) 3
11) 2
12) 5
13) 3
14) 2 15) 5
16) 2
17) 3
18) 4
19) 1
20) 2
Amount of water filled by B = x/16
x-4
x
12
16
⇒ 16x - 64 + 12x = 192
1 min.
⇒ 28x = 256 ⇒ x = 9 ⎯
7
18. Let the average expenditure of the boarder
be Rs.x
∴ ⎯ + ⎯ = 1 (full cistern)
total expenditure = Rs.30x
After 10 boarders joined,
Average expenditure = Rs. (x-5)
Total expenditure = 40(x-5)
∴ 40 (x-5) - 30x = 1300
⇒ x = Rs.150
∴ Original monthly expenditure
= 30 × Rs.150
= Rs.4500
19. With 20% money she can get 2 kg
0.75 × 2 = 1.5
with 100% (total money) she can get
1.4 × 4 = 6
100
⎯ × 2 = 10kg
20
originally she can get 10 - 2 = 8kg sugar
wrong number is 0.5
0.5 × 0.25 = 0.125
0.125 × 0.5 = 0.0625
∴ required number is 0.0625
13C × 12C
13×12
1
1
1
16. ⎯⎯ = ⎯ = ⎯
52C
52×51
17
2
or drawing one after the other is nothing but
drawing two cards at a time.
13×12
1
⎯ =⎯ =⎯
52C
52×51
17
2
13C
2
17. Let the cistern be filled in 'x' minutes
Pipe A fills water for (x-4) minutes
Price after 10% reduction = 90%of27.5
32 - 2 = 7
Pipe B fills water for x minutes
= Rs.24.75
42 - 3 = 13
∴ Value = 3000×24.75 = Rs.74250
52 - 4 = 21
x-4
Amount of water filled by A = ⎯
12
200
8
∴ Rate per kg = ⎯ = Rs.25
20. Interest for six months
1
15600 × ⎯ × 8
2
= ⎯⎯ = Rs.624
100
Interest for the remaining six months
1
7200 × ⎯ × 8
2
= ⎯⎯ = Rs.288
100
∴ Total interest = 624 + 288 = Rs.912.
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