Solving Systems Algebraically
MFM 2P1
We don’t have to graph to solve a system. We can solve algebraically.
A) SUBSTITUTION
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03x—4y=6
=—5x—13
‘=3x+II
‘y=—3x—9
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Solve the following systems of linear’equations by substitution.
a)
e)
y=—2x+6
3x+y=7
9x—3y=6
y=—3x—9
5x—y=1
2x+3y=6
y=x+2
Answers:
b)
y=—x+3
Ia) (1,4)
e) (2,4)
b) (-1,-6)
0 (3,0)
c)
g)
y=2x—13
x+2y=—6
3x+y=I1
y=x—1
c) (4,-5)
g) (3,2)
d)
h)
d) (3,-I)
h) (-4,—8)
y=—2x+5
3x=2y+11
3x=y—4
y=2x
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