CHEMISTRY 11 – ELECTRON CONFIGURATION WORKSHEET #3
1) Write the energy level occupancy for the following:
(a) C
(b) I
C (1s2, 2s2, 2p2)
= 2, 4
I (1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2,
4d10, 5p5)
= 2, 8, 18, 18, 7
(c) Pb
(d) Ba
Pb (1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2,
4d10, 5p6, 6s2, 4f14, 5d10, 6p2)
= 2, 8, 18, 32, 18, 4
Ba (1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2,
4d10, 5p6, 6s2)
= 2, 8, 18, 18, 8, 2
2) Draw the electron shell diagram for the following:
(a) O (1s2, 2s2, 2p4)
(b) Na (1s2, 2s2, 2p6, 3s1)
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(c) Co (1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d7)
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(d) Bi (1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2,
4d10, 5p6, 6s2, 4f14, 5d10, 6p3)
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(e) Cl (1s2, 2s2, 2p6, 3s2, 3p5)
(f) Cr (1s2, 2s2, 2p6, 3s2, 3p6, 4s1, 3d5)
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3) How many valence electrons do the following contain?
(a) O
O ([He] 2s2, 2p4)
=6
(c) V
V ([Ar] 4s2, 3d3)
=5
(e) Xe
Noble gas therefore 0 valence electrons
(g) Te
Te ([Kr] 5s2, 4d10, 5p4)
=6
(i) I5+
I5+ ([Kr] 5s2)
=2
(k) Zn2+
Noble gas configuration therefore 0 valence
electrons
(m) Tc4+
Tc4+ ([Kr] 4d3)
=3
(o) OO- ([Kr] 2s2, 2p5)
=7
(b) P
P ([Ne] 3s2, 3p3)
=5
(d) Ca
Ca ([Ar] 4s2)
=2
(f) Hg
Hg ([Xe] 6s2, 4f14, 5d10)
=2
(h) ClNoble gas configuration therefore 0 valence
electrons
(j) Xe2+
Xe2+ ([Kr] 5s2, 4d10, 5p4)
=6
(l) Ge4+
Noble gas configuration therefore 0 valence
electrons
(n) Sb3+
Sb3+ ([Kr] 5s2, 4d10)
=2
(p) Nb3+
Nb3+ ([Ar] 4d2)
=2