Chapter 26 Answers Practice Examples C C C C C C C CH3CH2CH2CH2CH2CH3 C C C C C C C (CH3)2CHCH2CH2CH3 C C C C C C C C C CH3CH2CH(CH3)CH2CH3 C C C C C C C (CH3)3CCH2CH3 (CH3)2CHCH(CH3)2 1a. C C C C C C C C CH3CH2CH2CH2CH2CH2CH3 C C C C C C C (CH3)2CHCH2CH2CH2CH3 C C C C C C CH3CH2CH(CH3)CH2CH2CH3 C C C C C C C C C (CH3)2CHCH2CHC(CH3)2 C C C C C C C (CH3)2CHCH(CH3)CH2CH3 C C C C C C C C C C (CH3)3CCH2CH2CH3 C C C C CH3CH2C(CH3) 2CH2CH3 C C C C C (CH3)3CCH(CH3)2 C C C C C C C CH(CH2CH3)3 1b. 2a. 3,6,6-trimethyloctane 2b. 3,6-dimethyloctane Copyright © 2011 Pearson Canada Inc. 1 3a. CH3 H3C CH CH3 CH H3C 3b. CH2 CH CH3 4a. conformations have the same energy. Copyright © 2011 Pearson Canada Inc. All 2 4b. 5a. 5b. 6a. (a) Achiral; (b) Chiral; (c) Chiral. 6b. (a) Achiral; (b) Chiral; (c) Chiral. Copyright © 2011 Pearson Canada Inc. 3 7a. 7b. 8a. (a) R configuration; (b) R configuration; (c) R configuration. 8b. (a) Enantiomers; (b) Enantiomers. 9a. (a) (E) stereoisomer; (b) (Z) stereoisomer; (c) (Z) stereoisomer. H3CH2C C 9b. H C H3CH2C Copyright © 2011 Pearson Canada Inc. H3C H Cl CH2CH3 H3CH2C C H C H C , (E) stereoisomer H3CH2C CH3 C CH3 C H C H C (b) (Z) stereoisomer H3CH2C (c) (Z) stereoisomer , (E) stereoisomer CH2CH3 Cl H C C H (a) (Z) stereoisomer H3CH2C CH3 , (E) stereoisomer H3C C CH3 4 10a. 10b. Integrative Example A. CH3-CH2-CH2-OH (Compound A), CH3-CH2-CH2-COOH (Compound B), CH3-CH2-CH2COO-CH3-CH2 (Compound C). B. Compounds (a) and (b) are both ethers. Ethers are relatively unreactive and the ether linkage is stable in the presence of most oxidizing and reducing agents, as well as dilute acids and Copyright © 2011 Pearson Canada Inc. 5 alkalis. Compound (c) is unsaturated secondary alcohol. It will decolorize a Br2/CCl4 solution. Compound (d), on the other hand is an aldehyde. On treatment with chromic acid it will be oxidized to carboxylic acid. Exercises Br Br C 1a. C C C C C C C C C C 1b. C C C C C C C C C C C C C C 1c. CH3 3a. H3C CH3 NO2 OH 3b. Cl COOH Cl 3c. NH2 H Cl H H C C C H 5a. H H H Copyright © 2011 Pearson Canada Inc. 6 H H H O C C O H H H 5b. H C O H C H H 5c. 7a. Each carbon atom is sp 3 hybridized. All of the C – H bonds in the structure are sigma bonds, between the 1s orbital of H and the sp 3 orbital of C. The C–C bond is between sp 3 orbitals on each C atom. H H H H H C C C H C H H H H 7b. Both carbon atoms are sp 2 hybridized. All of the C – H bonds in the structure are sigma bonds between the 1s orbital of H and the sp 2 orbital of C. The C–Cl bond is between the sp 2 orbital on C and the 3p orbital on Cl. The C = C double bond is composed of a sigma bond between the sp 2 orbitals on each C atom and a pi bond between the 2 pz orbitals on the two C atoms. H C C Cl H H 7c. The left-most C atom is sp 3 hybridized, and the C–H bonds to that C atom are between the sp 3 orbitals on C and the 1s orbital on H. The other two C atoms are sp hybridized. The righthand C – H bond is between the sp orbital on C and the 1s orbital on H. The C ≡ C triple bond is composed of one sigma bond formed by overlap of sp orbitals, one from each C atom, and two pi bonds, each formed by the overlap of two 2p orbitals, one from each C atom (that is a 2 p y 2 p y overlap and a 2 pz 2 pz overlap). H H C C C H H 9a. Identical Copyright © 2011 Pearson Canada Inc. 7 9b. Constitutional isomers 9c. No relationship 9d. Constitutional isomers 9e. Stereoisomers C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C 11. C C C C C C C C C C C C C C C C C 13a. Carbon 2 is chiral. 13b. There are no chiral carbon atoms. 13c. Carbon 2 is chiral. 15a. Carbon 2 is chiral. 15b. Carbon 2 is chiral. 15c. There are no chiral carbon atoms. 17a. Alkyl halide 17b. Aldehyde 17c. Ketone 17d. Phenol, hydroxyl group, and phenyl group. 19a. The hydroxyl group. 19b. An aldehyde has a carbonyl group with a hydrogen and a carbon group attached. In a ketone, the carbonyl group is attached to two carbons. 19c. The essential difference is the presence of the — OH group in acetic acid. 21a. Carboxylic acid, hydroxyl group and disubstituted aromatic ring. 21b. Ester group Copyright © 2011 Pearson Canada Inc. 8 21c. Ketone and carboxylic acid group. 21d. Aldehyde, hydroxyl group, and disubstituted aromatic ring. 23. O O H O O 25. O O O O H OH O OH H H O H O O O O OH OH O O O OH H H O O O O O O HO O O O HO O O H O O O O H O H O O 27. H OH OH O OH O 29. OH 31a. 3,5-dimethyloctane 31b. 2,2-dimethylpropane 31c. 3,3-dichloro-5-ethylheptane 33a. 2,2-dimethylbutane 33b. 2-methylpropene 33c. 1,2-dimethylcyclopropane Copyright © 2011 Pearson Canada Inc. 9 33d. 4-methyl-2-pentyne 33e. 3,4-dimethylhexane 33f. 3,4-dimethyl-2-propyl-1-pentene 35a. Insufficient 35b. Sufficient 35c. Insufficient 35d. Insufficient 35e. Sufficient 35f. Insufficient NO2 O2N CH3 NO2 37a. O COCH3 OH 37b. 37c. HOOCCH 2 C ( OH )( COOH ) CH 2 COOH 39a. N,N-diethylamine 39b. p-nitroaniline 39c. N-cyclopentyl-N-ethylamine 39d. N,N-diethyl-N-methylamine Copyright © 2011 Pearson Canada Inc. 10 41a. 41b. 43. The Anti conformation is lowest in energy. 45. 47a. 47b. 49. In the case of ethene there are only two carbon atoms between which there can be a double bond. In the case of propene, there can be a double bond only between the central carbon atom Copyright © 2011 Pearson Canada Inc. 11 and a terminal carbon atom. The case of butene is different since 1-butene is distinct from 2butene. 51a. (E) configuration 51b. (Z) configuration 51c. (E) configuration 53a. 53b. C CH 55a. Cl 55b. Cl 55c. 1,3,5-trihydroxybenzene 57. 59a. Identical 59b. Identical 59c. Isomers 59d. Enantiomers 59e. Identical 61a. (S)-3-bromo-2-methylpentane Copyright © 2011 Pearson Canada Inc. 12 61b. (S)-1,2-dibromopentane 61c. (R)-3-(bromomethyl)-1-chloropentan-3-ol 61d. (S)-1-bromopropan-2-ol 63a. (Z)-pent-2-ene 63b. (E)-1-chloro-2-methylbut-1-ene 63c. (E)-4-(chloromethyl)-3,7-dimethyloct-3-ene 63d. (Z)-5-bromo-3-(bromomethyl)-2-methylpent-2-enal 65a. 65b. 65c. 65d. 65e. Integrative and Advanced Exercises Copyright © 2011 Pearson Canada Inc. 13 79a. C6 H 5 NO 2 + 7 H + + 2 Fe → C6 H 5 NH 3+ + 2 H 2 O + 2 Fe3+ 79b. 3 C6 H 5CH 2 OH + 2 Cr2 O7 2− + 16 H + → 3 C6 H 5COOH + 4 Cr 3+ + 11 H 2 O 79c. 3 CH 3CH= = CH 2 + 2 MnO 4 − + 4 H 2 O → 3CH 3CHOHCH 2 OH + 2 MnO 2 + 2 OH − 81. C4H8N2O2 84. The unknown must be 1-butanol or butyraldehyde. The identity of the unknown can be established by treatment with a carboxylic acid. 89a. Ester, amine(tertiary), arene. 89b. C1= sp2, C2 = sp3, C3 = sp3, C4 = sp3, N = sp3. 89c. Carbons 2 and 4 are chiral. Self-Assessment Exercises 101. The correct answer is (c). 102. The correct answer is (b). 103. The correct answer is (e). 108. The correct answer is (c). 109. C4H8 110a. C6H12 110b. C3H7OH 110c. C6H5COOH 111a. 111b. Copyright © 2011 Pearson Canada Inc. 14 111c. Copyright © 2011 Pearson Canada Inc. 15
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