Perfect Squares and Perfect Cubes! Square Roots Perfect Squares Explanation Which Equals β1 1 πππππ’π π 1 × 1 = 12 1 β4 2 πππππ’π π 2 × 2 = 22 4 β9 3 πππππ’π π β16 4 πππππ’π π β25 5 πππππ’π π β36 6 πππππ’π π β49 7 πππππ’π π β64 8 πππππ’π π β81 9 πππππ’π π β100 10 πππππ’π π β121 11 πππππ’π π β144 12 πππππ’π π β169 13 πππππ’π π β196 14 πππππ’π π β225 15 πππππ’π π β256 16 πππππ’π π β289 17 πππππ’π π β324 18 πππππ’π π β361 19 πππππ’π π β400 20 πππππ’π π β441 21 πππππ’π π β484 22 πππππ’π π β529 23 πππππ’π π β576 24 πππππ’π π β625 25 πππππ’π π β676 26 πππππ’π π β729 27 πππππ’π π β784 28 πππππ’π π β841 29 πππππ’π π β900 30 πππππ’π π Perfect Squares and Perfect Cubes! Square Roots Perfect Squares Explanation Which Equals 3 β1 1 πππππ’π π 1 × 1 × 1 = 13 1 3 2 πππππ’π π 2 × 2 × 2 = 23 8 3 β27 3 πππππ’π π 3 4 πππππ’π π 3 β125 5 πππππ’π π 3 β216 6 πππππ’π π 3 β343 7 πππππ’π π 3 β512 8 πππππ’π π 3 9 πππππ’π π 3 β1000 10 πππππ’π π 3 β1331 11 πππππ’π π 3 12 πππππ’π π β8 β64 β729 β1728 Four Formulas I need to Know! Vocabulary ( A= Area, V= Volume, S= side length of the shape or figure) Inverse Operations: Statements: ο· ο· The Inverse Operation of Squaring is Square Rooting The Inverse Operation of Cubing is Cube Rooting Area of a Square π΄ = π 2 Volume of a Cube π = π 3 Side Length of a Square π = βπ΄ Side Length of a Cube π = βπ 3
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