Edexcel IGCSE Chemistry Chapter 22, pages 185 - 186 ANSWERS Remaining questions will be addressed at a later stage. 1. 69 x 0.602 = 41.5 71 x 0.398 = 28.3 69.8 2. Total abundance = 100 + 5.10 + 3.36 = 108.46 28 x (100/108.46) = 25.8 29 x (5.10/108.46) = 1.4 30 x (3.36/108.46) = 0.9 28.1 3. a) Relative atomic mass is the weighted average mass of the isotopes of an element. b) RAM Cu: 63 x 0.691 = 43.5 65 x 0.309 = 20.1 63.6 RAM S: 32 x 0.950 = 30.4 33 x 0.0076 = 0.3 34 x 0.0422 = 1.4 35 x 0.0002 = 0.0 32.1 Relative formula mass of CuS = 63.6 + 32.1 = 95.7 4. a) CO2 = 12 + (2 x 16) = 44 b) (NH4)2SO4 = 2(14 + 4 x 1) + 32 + 4 x 16 = 132 c) Na2CO3.10H2O = (2 x 23 + 12 + 3 x 16) + 10(2 x 1 + 16) = 106 + 180 = 286 d) Cr2(SO4)3 = 2 x 52 + 3(32 + 4 x 16) = 104 + 96 = 200 e) (NH4)2SO4.FeSO4.6H2O = 2(14 + 4 x 1) + 32 + 4 x 16 + 56 + 32 + 4 x 16 + 6(2 x 1 + 16) = 284 + 108 = 392 Edexcel IGCSE Chemistry Chapter 22, pages 185 - 186 ANSWERS Remaining questions will be addressed at a later stage. 5. a) RAM carbon = 12 x 3 = 36 RFM propane = 3 x 12 + 8 x 1 = 44, so % by mass of carbon = 36/44 x 100 = 82% b) RFM hydrated magnesium sulfate crystals = (24 + 32 + 4 x 16) + 7(2 x 1 + 16) = 120 + 126 = 246 So % by mass of water = 126/246 x 100 = 51% 6. a) RFM urea = 12 + 16 + 2(14 + 2 x 1) = 60, of which 28 is N, so 28/60 x 100 = 47% b) RFM potassium nitrate = 39 + 14 + 3 x 16 = 101, of which 14 is N, so 14/101 x 100 = 14% c) RFM ammonium nitrate = (14 + 4 x 1) + (14 + 3 x 16) = 80, of which 28 is N, so 28/80 x 100 = 35% d) RFM ammonium sulfate = 2(14 + 4 x 1) + 32 + 4 x 16 = 132, of which 28 is N, so 28/132 x 100 = 21% 7. a) 207 + 2(14 + 3 x 16) = 331g b) 1 mole methane = 16g, so 4.30 x 16g = 68.8g c) 1 mole sodium carbonate = 286g, so 0.24 x 286g = 68.64g 8. a) 1 mole of copper sulfate crystals = 250g, so 50g/250g = 0.2 moles b) 1 mole of iron = 56g, so 1,000,000g/56g = 17857 moles c) 1 mole sulfur dioxide = 64g, so 0.032g/64g = 0.0005 moles 9. a) 1 mole sodium chloride = 58.5g, so 4 x 58.5g = 234g b) 1 mole calcium hydroxide = 76g, so 37g/76g = 0.48 moles c) 1 mole calcium = 40g, so 1000g/40g = 25 moles d) 1 mole copper oxide = 80g, so 80g x 0.125 moles = 10g e) 4g/0.1 mol = 40g/mol f) RFM is its molar mass (M), so 1g/0.004 mol = 250g/mol m n M
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