SUMMATIVE ASSESSMENT- (SA-1) 2016-17
Marking Scheme Cum Solution
CLASS-Vll
Section (A)
M.Marks 60
1x8=8 Marks
Q(1) (C) -4
1Mark
Q(2) (a)
1Mark
Q(3) (d) 0.2 kg.
1Mark
Q(4) (d) 6
1Mark
Q(5) (a) 0.05
1Mark
Q(6) (c) 15°
1Mark
Q(7) (c) 105°
1Mark
Q(8) (d) 9
1Mark
Section (B)
Q(9)
Q(10)
2x6=12 marks
(-3)2x(-5)2
=9x25
1 Mark
=225
1 Mark
x+50°+60° =180°
1 Mark
X=180°-110°
(1/2) Mark
X=70°
(1/2) Mark
Q(11)
P.M is altitude
(1) Mark
PD is median
(1) Mark
Q(12) (1)
Three-fourth of t is 15 ,3/4t=15
(2)
Q(13)
2 subtract from y is 8,Y-2=8
1 Mark
1 Mark
Median 13,16,12,14,19,12,14,13,14.
Ascending order 12,12,13,13,14,14,14,16,19,
(1/2) Mark
No of terms (n) =9
Median = (n+1)/2 th terms
(1/2) Mark
Median =(9+1)/2th terms =5th terms
(1/2) Mark
=14
Q(14) (i)
(ii) 2x1/2
2x1/5
1 Mark
(1/2) Mark
1 Mark
Section (C)
Q(15)
3x8=24 Marks
(i)
Rabbits
(1) Mark
(ii)
8 students
(1) Mark
(iii)
8+10+12+5+3=38
(1) Mark
Q(16)
Assending order 6,8,10,10,15,15,15,50,80,100,120
(1/2) Mark
Most repeted term=15 mode-15
(1/2) Mark
No of term =11
Mean=sum of term /no of term
1/2 Mark
Mean=6+8+10+10+15+15+15+50+80+100+120/11
=429/11= 39
(1/2) Mark
Median= (n+1)/2th term=15term
Q(17)
shyam baught=5kg.300g+8kg 450g
(1/2) Mark
(1) Mark
=13kg750g
Sarala baught =4kg 8980g+4kg 750g
(1) Mark
=9kg 640g
Shyam bought more ______ =132kg 750g
= 9kg 640g
4kg 110g
Q(18) (i)
4/9÷2/3, 4/9 x 3/2
(1) Mark
(ii)
4/9 ÷5, 4/9 x 1/5
Q(19)
(1)
4/45
(1/2) Mark
total height =10-(-350) m
(1) Mark
=10+350=360m
(1/2) Mark
Rate =60m/min
(1/2) Mark
Time =360m÷60m/min=6 minutes
Q(20) (i)
(1) Mark
x+4=9
(1) Mark
(ii) 6y-6=60
(1)Mark
(iii) 7m+7=77
(1)Mark
Q(21) 45-5 x a8-5 b3-2
(1) Mark
a° x a3 x b
(1) Mark
1 x a3 b =a3b
(1) Mark
Q(22)
6cm
6
C
6cm
on construction (3 marks )
A
A
Section (D )
4 x 4 =16 marks
Q(23) Pythagoras property
C
CP2= BC2 + PB 2 (1/2) Mark
5m
CP= 13m
13m
(1) Mark
CP=AC
A
(1/2) Mark
B
p
12m
Original height=AC+BC
=13m +5m =18m
Q(24)
(1) Mark
let lowest mark = X
ATC
(1/2) Mark
2x+7=87
(1/2) Mark
2x = 87-7
(1) Mark
X= 80/2=40
(1) Mark
Q(25) (i) perimeter of ABC =5/2(m+2 ¾ cm+3 3/5cm
=5/2+11/4+18/5
=
=
Q(25) (ii)
=
=8
cm
(1/2) Mark
(1/2) Mark
(1/2) Mark
(1/2) Mark
Perimeter of rectangle BCDE
Perimeter =
2 x (length + breath )
= 2 x (2
=2x(
+
+
)
)
(1/2) Mark
(1/2) Mark
=2 x (
Q(26)
(1/2) Mark
=
=15
(i) (-3) x (-9)
=72
(1/2) Mark
(ii) 5 x (-7)
= -3
(1/2) Mark
(iii) 7 x (-8)
=-56
(1/2) Mark
(iv)
(-11) x (-12) =132
(v)
(-75) ÷ (75)
(vi)
369 ÷ 1 = 369
(vii)
(viii)
(-206) ÷ (-206) = 1
(-48) ÷ 48 = -1
(1/2) Mark
(1/2) Mark
(1/2) Mark
(1/2) Mark
(1/2) Mark
(1/2) Mark