Lecture 2 Chapter 1 and 2 Physics I Kinematics in One Dimension Course website: http://faculty.uml.edu/Andriy_Danylov/Teaching/PhysicsI ResponseWare App instead of a clicker PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics Today we are going to discuss basic kinematic stuff: Distance/Displacement: Section 1.3 Speed/Average velocity: Instantaneous velocity: Section 1.4 Section 2.2 Average Acceleration: Section 1.5 Instantaneous Acceleration: Section 2.7 PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics Mechanics Motion There are three branches of Mechanics: Kinematics Motion Forces Statics Motion Forces Dynamics Motion Forces Kinematics describes motion of objects we are not interested in reasons (forces) of a motion PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics Kinematics PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics Frames of Reference Before starting solving any problem, we have to define a coordinate system (a frame of reference) to describe position and motion of an object In this class, we will base problems in a Cartesian coordinate system. We will have 1D and 2D problems We have freedom to choose direction of an axis. For 1 dimensional (1D) motion (motion in a straight line), it’s better to align the x-axis along a motion direction. For falling bodies, we tend to describe position using the y-axis Two dimensional (2D) problem One dimensional (1D) problem 5 y-axis origin Negative direction -x origin 1 Positive direction +x 2 3 4 5 -5 5 x -5 PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics x-axis Distance vs. Displacement PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics Distance vs. Displacement Distance (scalar): the total path length traveled by an object Displacement (vector): how far an object is from its starting point PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics ConcepTest 1 Roller Coaster What would be your displacement after a complete roller coaster? ConcepTest 2 Walking the Dog You and your dog go for a walk to the park. On the way, your dog takes many side trips to chase squirrels or examine fire hydrants. When you arrive at the park, do you and your dog have the same A) yes B) no displacement? Yes, you have the same displacement. Because you and your dog had the same initial position and the same final position, then you have (by definition) the same displacement. Follow-up: have you and your dog traveled the same distance? ConcepTest 3 Odometer Does the odometer in a car A) distance measure distance or B) displacement displacement? C) both If you go on a long trip and then return home, your odometer does not measure zero, but it records the total miles that you traveled. That means the odometer records distance. Follow-up: how would you measure displacement in your car? Distance vs. Displacement (1D) Distance is a scalar Displacement is a vector – A vector has both magnitude and direction (or sign in 1-D) Displacement = final position – initial position Distance = 70+30 =100 m x1 x2 20 40 60 70 Displacement =x2- x1=+40 m PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics x Distance vs. Displacement (1D) Distance = 20 m Distance = 20 m x2 xx11 x1 x2 Displacement = 30-10= + 20 m Displacement = 10-30= -20 m negative PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics Speed and Velocity Even Hollywood feels that there is a difference between these two terms PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics Average Speed and Average Velocity Speed is a scalar average speed distance travelled time elapsed (Speed: Distance traveled per unit time interval) Velocity is a vector average velocity displaceme nt time elapsed (Velocity: Displacement of an object per unit time interval) PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics ConcepTest 4 Speedometer A) velocity Does the speedometer in a car B) speed measure velocity or speed? C) both D) neither The speedometer clearly measures speed, not velocity. Velocity is a vector (depends on direction), but the speedometer does not care what direction you are traveling. Graphs: Average velocity position (m) 20 15 x2 10 ∆x 5 0 0 1 2 t1 PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics ∆t 3 time (s) x1 4 5 t2 6 Average velocity does not tell the whole story… we also need Instantaneous Velocity If you watch a car’s speedometer, at any instant of time, the speedometer tells you how fast the car is going at that instant. PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics Instantaneous velocity position (m) 20 15 10 5 0 0 1 2 t1 Instantaneous velocity PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics goes to 0 3 time (s) 4 5 6 Instantaneous velocity Graphically, instantaneous velocity is the slope of the x vs t plot at a single point Mathematically, the instantaneous velocity is the derivative of the position function PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics Finding instantaneous velocity from position graphically Turning point Moves forward Moves backward . v1 (slow speed) >0 v2 (max speed) v3=0 (turning point) v positive Gentler slope ≡ lower velocity Steeper slope ≡ higher velocity 0 It flies back. v4 negative PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics ConcepTest 5 Relay baton Which one of the following x-vs-t graphs could be a reasonable representation of the motion of a baton in a relay race being passed from one runner to the next? End of class Finding Position from a Velocity Graph ∙ ∙ ∙ Let’s integrate it: x ∙ Geometrical meaning of an integral is an area Initial Total position displacement The total displacement ∆s is called the “area under the velocity curve.” (the total area enclosed between the t-axis and the velocity curve). Example displacement The displacement is the shaded area ∆ v(t) t PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics ConcepTest Position from velocity Here is the velocity graph of an object that is at the origin (x = 0 m) at t = 0 s. At t = 4.0 s, the object’s position is A) 20 m B) 16 m C) 12 m D) 8 m E) 4 m Displacement = area under the curve Acceleration PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics Acceleration Velocity can also change with time: acceleration change of velocity average acceleration time elapsed Instantaneous acceleration If we are given x(t), we can find both velocity v(t) and acceleration a(t) as a function of time Speeding up: acceleration PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics Slowing down: deceleration Example 2-7: Acceleration given x(t). A particle is moving in a straight line so that its position is given by the relation x = (2 m/s2)t2 + (3 m). Calculate (a) its average acceleration during the time interval from t1 = 1 s to t2 = 2 s, (b) its instantaneous acceleration as a function of time. PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics Thank you See you on Wednesday PHYS.1410 Lecture 2 Danylov Department of Physics and Applied Physics
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