12.4: Volume of Prisms and Cylinders Pg. 580 # 7,8,10-13,15,16,19,20
7
a V = 7 s 5 4= 23 cra
b
23.33 62,4 . 1.466 lb
10 a V = Bh
TA = LA + 28
xr2b
=
)202)
=
81
n(12) ,
2437r
TA = 2yrrh +114
TA = 24(12) + 11)2
TA 108n + 40,57:
TA = 148.6%
lit(6)2(20)
(18)1100)
V = 36071
TA = li(LA 4 B1 B + And
i(2nrh + nr2 + nr2) + bh
,
(2,Irrh + 27E1'2) +
+ nr2 + bh
n(6X20) + /OW + + 800)
= 1207r + 36n + 32{20)
1.5671 + 240
12.4: Volume of Prisms and Cylinders Pg. 580 #7,8,10-13,15,16,19,20
11 Let x be the length of a side,. Vcvi, =x A cube has
6 square faces. Each face has an area of x2, TA. 6x
TA
Vcabe
-
6x2
X3 — 6.712
0
6)
oi= 6
12 Vpr = Eh
(,ap)h
V = ii(3.45.:X36) 0)
V = 544-3-(10) :4540Z
TA
LA + Aimiwa
TA u 6(6X,10) + 24 3VX
•
TA = 360 +108\g.
la The face diagonal forms a 464510"
Vciabp
$'71
= (5-NIZ3
V = 250
12.4: Volume of Prisms and Cylinders Pg. 580 #7,8,10-13,15,16,19,20
15
V
jT, Fib
(9X7X3) 189
3_6
VplLz
twh
ITh
— (15X1
= /IT2h
760 cru CITi
stf4A15)
240%
Vey' w' 240(3„14)
753,6 rti cm
Yes,. It will ove. rllow by 3.6 cu
19
V pri.su,
Bh
7,A sector h
-40
31:00)2(11)
= 11(400)(15)
5
IT
TA = 3—
46°0 (2rt 20 . 35) + 21.3fo n(20)2 + 15 20.1
= 1(4070(15) + 2ftX4007L) + 2(35X20)
=
TA
GOO $00
+
titoo
+ 600
+ 600
1400
+ 600
12.4: Volume of Prisms and Cylinders Pg. 580 #7,8,10-13,15,1619,20
20 a
lib
VI„„h = nr2h
Veube (03
\late=
Vicu = (4)3
64 cu cm
V1
= x(1)2(4)
4(3.14) 12.56 cu cm
Vice = /1171.1,11>e """
V so
64— 1256 tilt cm
V
51.4 cil cm
b V 10 cubes 10(51.44 cu cm) 514.4 cu cu
V 30 melted cubes - 514,4 cu cm — 11%(51.4.4 cu cm)
V 10 melted ,cubes (.89X514.4 cu cm)... 457.8 cu cr
TA . 6(A face of the cube) — 2(A base of cyl) + LAcyl
c
TA A-- 6(s2)— 2(nr2) + eh
1.--• 6(4)2 — 2(n(1)2) 271(1X4)
:a 6(16)— 27z + 6rc
— 96 2(3.14) + 8(334)
TA
114.8 sqcm
d TA of a cube without hole = 6(52)
TA = 6(42)
TA
114.S
tfiE3
96 sq cm
- 1.20
His claim is not true, 114.8- sq cm vs, 96 sq cm,