12.4: Volume of Prisms and Cylinders Pg. 580 # 7,8,10-13,15,16,19,20 7 a V = 7 s 5 4= 23 cra b 23.33 62,4 . 1.466 lb 10 a V = Bh TA = LA + 28 xr2b = )202) = 81 n(12) , 2437r TA = 2yrrh +114 TA = 24(12) + 11)2 TA 108n + 40,57: TA = 148.6% lit(6)2(20) (18)1100) V = 36071 TA = li(LA 4 B1 B + And i(2nrh + nr2 + nr2) + bh , (2,Irrh + 27E1'2) + + nr2 + bh n(6X20) + /OW + + 800) = 1207r + 36n + 32{20) 1.5671 + 240 12.4: Volume of Prisms and Cylinders Pg. 580 #7,8,10-13,15,16,19,20 11 Let x be the length of a side,. Vcvi, =x A cube has 6 square faces. Each face has an area of x2, TA. 6x TA Vcabe - 6x2 X3 — 6.712 0 6) oi= 6 12 Vpr = Eh (,ap)h V = ii(3.45.:X36) 0) V = 544-3-(10) :4540Z TA LA + Aimiwa TA u 6(6X,10) + 24 3VX • TA = 360 +108\g. la The face diagonal forms a 464510" Vciabp $'71 = (5-NIZ3 V = 250 12.4: Volume of Prisms and Cylinders Pg. 580 #7,8,10-13,15,16,19,20 15 V jT, Fib (9X7X3) 189 3_6 VplLz twh ITh — (15X1 = /IT2h 760 cru CITi stf4A15) 240% Vey' w' 240(3„14) 753,6 rti cm Yes,. It will ove. rllow by 3.6 cu 19 V pri.su, Bh 7,A sector h -40 31:00)2(11) = 11(400)(15) 5 IT TA = 3— 46°0 (2rt 20 . 35) + 21.3fo n(20)2 + 15 20.1 = 1(4070(15) + 2ftX4007L) + 2(35X20) = TA GOO $00 + titoo + 600 + 600 1400 + 600 12.4: Volume of Prisms and Cylinders Pg. 580 #7,8,10-13,15,1619,20 20 a lib VI„„h = nr2h Veube (03 \late= Vicu = (4)3 64 cu cm V1 = x(1)2(4) 4(3.14) 12.56 cu cm Vice = /1171.1,11>e """ V so 64— 1256 tilt cm V 51.4 cil cm b V 10 cubes 10(51.44 cu cm) 514.4 cu cu V 30 melted cubes - 514,4 cu cm — 11%(51.4.4 cu cm) V 10 melted ,cubes (.89X514.4 cu cm)... 457.8 cu cr TA . 6(A face of the cube) — 2(A base of cyl) + LAcyl c TA A-- 6(s2)— 2(nr2) + eh 1.--• 6(4)2 — 2(n(1)2) 271(1X4) :a 6(16)— 27z + 6rc — 96 2(3.14) + 8(334) TA 114.8 sqcm d TA of a cube without hole = 6(52) TA = 6(42) TA 114.S tfiE3 96 sq cm - 1.20 His claim is not true, 114.8- sq cm vs, 96 sq cm,
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