VVR 120 Fluid mechanics 4. Hydrostatics II (1.6–1.7) • Pressure and force on curved surfaces • Buoyancy / Archimedes´ principle Examples: B23, B27, and B16 VVR 120 Fluid mechanics Fig. 1.27 Pressure on a sphere VVR 120 Fluid mechanics FORCES ON CURVED SUBMERGED SURFACES (1) Resolve the force into two components, one vertical and one horizontal Pressure intensity on a curved surface. F passes through the center of curvature. VVR 120 Fluid mechanics (2) The horizontal force is obtained by projecting the curved surface onto a vertical plane. The horizontal force is equal to the force on this projected area: FH = w hc,projAproj Projection of the curved surface onto a vertical plane VVR 120 Fluid mechanics (3) The vertical force is equal to the weight of the volume of liquid above the curved surface The vertical force component, FV, caused by the weight of liquid above the surface VVR 120 Fluid mechanics (4) F2 F2 V H F and the direction of the resultant force by: tan V F H The resultant force is given by: F The direction of the resultant force, F, which must also pass through C (5) Remember that there is an equal and opposite force acting on the other side of the surface. VVR 120 Fluid mechanics ARCHIMEDES PRINCIPLE – BUOYANCY FORCE Law of buoyancy (Archimedes’ principle): • “The upthrust (buoyancy force) on a body immersed in a fluid is equal to the weight of the fluid displaced” Law of flotation: • “A floating body displaces its own weight of the liquid in which it floats” VVR 120 Fluid mechanics Proof of Archimedes principle Vertical forces acting cylinder surface: “Downwards”: p1A = ρ∙g∙yA = w ∙yA FB • “Upwards”: p2A = ρ∙g∙(y+L)A= w∙(y+L)A “Net pressure force (upthrust)”,FB: FB = w(y+L)A - wyA= wLA = = wV Eq. 1.14 VVR 120 Fluid mechanics B23 The quarter cylinder AB is 3 m long. Calculate magnitude, direction, and location of the resultant force of the water on AB. Z X C VVR 120 Fluid mechanics B27 The weightless sphere of diameter d is in equilibrium in the position shown. Calculate d as a function of w1, h1, w2, and h2. w1 buoyancy w2 Sphere volume = pd3/6 Area = pd2/4 VVR 120 Fluid mechanics B16. A circular gate, 3 m in diameter, has its center 2.5 m below the water surface and lies in a plane sloping 60o from the horisontal. Calculate magnitude, direction, and location of total force on the gate.
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