NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 20 M5 GEOMETRY Lesson 20: Cyclic Quadrilaterals Classwork Opening Exercise Given cyclic quadrilateral π΄π΅πΆπ· shown in the diagram, prove that π₯ + π¦ = 180°. Example Given quadrilateral π΄π΅πΆπ· with πβ π΄ + πβ πΆ = 180°, prove that quadrilateral π΄π΅πΆπ· is cyclic; in other words, prove that points π΄, π΅, πΆ, and π· lie on the same circle. Lesson 20: Cyclic Quadrilaterals This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M5-TE-1.3.0-10.2015 S.143 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 20 M5 GEOMETRY Exercises 1. Assume that vertex π·β²β² lies inside the circle as shown in the diagram. Use a similar argument to Example 1 to show that vertex π·β²β² cannot lie inside the circle. Lesson 20: Cyclic Quadrilaterals This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M5-TE-1.3.0-10.2015 S.144 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 20 M5 GEOMETRY 2. Quadrilateral πππ π is a cyclic quadrilateral. Explain why β³ πππ ~ β³ ππ π. 3. A cyclic quadrilateral has perpendicular diagonals. What is the area of the quadrilateral in terms of π, π, π, and π as shown? Lesson 20: Cyclic Quadrilaterals This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M5-TE-1.3.0-10.2015 S.145 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 20 NYS COMMON CORE MATHEMATICS CURRICULUM M5 GEOMETRY 1 4. Show that the triangle in the diagram has area ππ sin(π€). 5. Show that the triangle with obtuse angle (180 β π€)° has area ππ sin(π€). 2 1 2 Lesson 20: Cyclic Quadrilaterals This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M5-TE-1.3.0-10.2015 S.146 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 20 NYS COMMON CORE MATHEMATICS CURRICULUM M5 GEOMETRY 6. 1 2 Show that the area of the cyclic quadrilateral shown in the diagram is Area = (π + π)(π + π) sin(π€). Lesson 20: Cyclic Quadrilaterals This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M5-TE-1.3.0-10.2015 S.147 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 20 NYS COMMON CORE MATHEMATICS CURRICULUM M5 GEOMETRY Lesson Summary THEOREMS: Given a convex quadrilateral, the quadrilateral is cyclic if and only if one pair of opposite angles is supplementary. The area of a triangle with side lengths π and π and acute included angle with degree measure π€: Area = 1 ππ β sin(π€). 2 Μ Μ Μ Μ and Μ Μ Μ Μ The area of a cyclic quadrilateral π΄π΅πΆπ· whose diagonals π΄πΆ π΅π· intersect to form an acute or right angle with degree measure π€: Area(π΄π΅πΆπ·) = 1 β π΄πΆ β π΅π· β sin(π€). 2 Relevant Vocabulary CYCLIC QUADRILATERAL: A quadrilateral inscribed in a circle is called a cyclic quadrilateral. Problem Set 1. Quadrilateral π΅π·πΆπΈ is cyclic, π is the center of the circle, and πβ π΅ππΆ = 130°. Find πβ π΅πΈπΆ. Lesson 20: Cyclic Quadrilaterals This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M5-TE-1.3.0-10.2015 S.148 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 20 M5 GEOMETRY 2. Quadrilateral πΉπ΄πΈπ· is cyclic, π΄π = 8, πΉπ = 6, ππ· = 3, and πβ π΄ππΈ = 130°. Find the area of quadrilateral πΉπ΄πΈπ·. 3. Μ Μ Μ Μ β₯ Μ Μ Μ Μ In the diagram below, π΅πΈ πΆπ· and πβ π΅πΈπ· = 72°. Find the value of π and π‘. 4. Μ Μ Μ . Find πβ πΆπΈπ· and πβ πΈπ·πΆ. In the diagram below, Μ Μ Μ π΅πΆ is the diameter, πβ π΅πΆπ· = 25°, and Μ Μ Μ πΆπΈ β Μ π·πΈ Lesson 20: Cyclic Quadrilaterals This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M5-TE-1.3.0-10.2015 S.149 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 20 NYS COMMON CORE MATHEMATICS CURRICULUM M5 GEOMETRY 5. In circle π΄, πβ π΄π΅π· = 15°. Find πβ π΅πΆπ·. 6. Given the diagram below, π is the center of the circle. If πβ πππ = 112°, find πβ πππΈ. 7. Given the angle measures as indicated in the diagram below, prove that vertices πΆ, π΅, πΈ, and π· lie on a circle. Lesson 20: Cyclic Quadrilaterals This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M5-TE-1.3.0-10.2015 S.150 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 20 M5 GEOMETRY 8. In the diagram below, quadrilateral π½πΎπΏπ is cyclic. Find the value of π. 9. Do all four perpendicular bisectors of the sides of a cyclic quadrilateral pass through a common point? Explain. 10. The circles in the diagram below intersect at points π΄ and π΅. If πβ πΉπ»πΊ = 100° and πβ π»πΊπΈ = 70°, find πβ πΊπΈπΉ and πβ πΈπΉπ». 11. A quadrilateral is called bicentric if it is both cyclic and possesses an inscribed circle. (See diagram to the right.) a. What can be concluded about the opposite angles of a bicentric quadrilateral? Explain. b. Each side of the quadrilateral is tangent to the inscribed circle. What does this tell us about the segments contained in the sides of the quadrilateral? c. Based on the relationships highlighted in part (b), there are four pairs of congruent segments in the diagram. Label segments of equal length with π, π, π, and π. d. What do you notice about the opposite sides of the bicentric quadrilateral? Lesson 20: Cyclic Quadrilaterals This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M5-TE-1.3.0-10.2015 S.151 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 20 M5 GEOMETRY 12. Quadrilateral πππ π is cyclic such that Μ Μ Μ Μ ππ is the diameter of the circle. If β ππ π β β πππ , prove that β πππ is a right angle, and show that π, π, π, and π lie on a circle. Lesson 20: Cyclic Quadrilaterals This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M5-TE-1.3.0-10.2015 S.152 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
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