Lesson 4.1 Assignment Name_________________________________________________________ Date__________________________ Math Football Using Models to Understand Integers Negative integers cannot be represented in concrete reality, but they are very useful for representing some sort of progress from a starting quantity or position. Therefore, common applications of negative integers often involve money, temperature, or direction. Problems that deal with sequential events of a story can often be modeled by a number sentence involving negative integers. 1. A small dog that can jump 5 feet off the ground chases a chipmunk across a yard towards a tree. The chipmunk runs 8 feet up the tree trunk, and then cautiously walks back down 5 feet to see how close the dog is. Seeing the dog closing in, the chipmunk then scurries up 3 feet before the dog reaches the tree. a. Write a number sentence for the situation. (18) 1 (25) 1 (13) 5 16 b. Is the dog able to reach the chipmunk? Explain. The chipmunk ends up 6 feet up the tree trunk. Because the dog can only jump 5 feet high, the dog is not able to reach the chipmunk. 2. While spending the day at the beach, Keeley tries to dig a deep hole in the sand. She digs down 20 inches before the walls of the hole collapse, filling the hole with 7 inches of sand. She then continues to dig down 10 inches before the sides of the hole collapse again, filling the hole with 4 inches of sand. © 2011 Carnegie Learning a. Write a number sentence for the situation. (220) 1 (17) 1 (210) 1 (14) 5 219 b.Keeley decides to place her sand pail that is 18 inches tall into the hole in the sand. Is the hole deep enough for her entire pail to fit? Explain. Because Keeley’s pail is 18 inches tall and the hole is 19 inches deep, the hole is deep enough for her entire pail to fit. 3. Write a story problem that can be modeled by a number sentence that includes negative integers. Then write a number sentence for the situation. Answers will vary. Chapter 4 Assignments • 65 © 2011 Carnegie Learning 66 • Chapter 4 Assignments Lesson 4.2 Assignment Name_________________________________________________________ Date__________________________ Walk the Line Adding Integers, Part I The atom is the basic unit of matter. Everything is made up of atoms. Each atom is made up of protons, neutrons, and electrons. The protons carry a positive (1) charge and make up the nucleus of an atom with the neutrons. Neutrons do not carry a charge. The electrons carry a negative (2) charge and circle the nucleus. Atom – – + + + Proton Neutron + – – Electron Atoms have no positive or negative charge. This means that they must have the same number of protons and electrons. 1. A partial model of a Nitrogen atom is shown. – – + + © 2011 Carnegie Learning – + + – – + + + – – a.How many electrons should be drawn on the model of a Nitrogen atom so that it has the same number of protons and electrons? There are 7 protons in a Nitrogen atom. So, 7 electrons need to be drawn on the model. Chapter 4 Assignments • 67 Lesson 4.2 Assignment page 2 b. Complete the model of the Nitrogen atom by drawing in the electrons. See model. c.Write an expression that represents the sum of the number of protons and electrons in a Nitrogen atom. 7 1 (27) d. Use the number line to show that the sum of the number of protons and electrons in the Nitrogen atom is zero. +7 –7 –10 –5 0 5 10 15 © 2011 Carnegie Learning –15 68 • Chapter 4 Assignments Lesson 4.2 Assignment page 3 Name_________________________________________________________ Date__________________________ 2. Atoms contain protons (1), neutrons (no charge), and electrons (2). Atoms must have the same number of protons and electrons. Sometimes an atom gains electrons. It then becomes an anion. The model shows a Nitrogen anion. – – – – – + + + + + – – + + – – – a.Write an expression that represents the sum of the number of protons and electrons in the Nitrogen anion. 7 1 (210) b. Use the number line to determine the sum of the protons and electrons in the Nitrogen anion. +7 –10 © 2011 Carnegie Learning –15 –10 –5 0 5 10 15 c. What is the charge of the Nitrogen anion? The charge of the Nitrogen anion is 23. Chapter 4 Assignments • 69 Lesson 4.2 Assignment page 4 3. A Magnesium anion is shown. Anions contain more electrons (2) than protons (1). – – – – + – + + + – + + + – + + – + + – – – + – – – a. Write an expression that represents the sum of the number of protons and electrons in the Magnesium anion. 12 1 (214) b. Use the number line to determine the sum of the protons and electrons in the Magnesium anion. 12 –14 –15 –10 –5 0 5 10 15 c. What is the charge of the Magnesium anion? The charge of the Magnesium anion is 22. © 2011 Carnegie Learning 70 • Chapter 4 Assignments Lesson 4.2 Assignment page 5 Name_________________________________________________________ Date__________________________ d.Suppose that the Magnesium anion gains 7 more electrons. Complete the model shown by adding the 7 electrons. – – – – – – – + + – + – + – + + + – + + + – – + + – – – – – – – e. Write an expression that represents how the charge of the Magnesium anion changed in part (d). 22 1 (27) f. What is the charge of the Magnesium anion in part (d)? Use a number line to verify your answer. The charge of the Magnesium anion is 29. –2 –7 –10 –5 0 5 10 15 © 2011 Carnegie Learning –15 Chapter 4 Assignments • 71 © 2011 Carnegie Learning 72 • Chapter 4 Assignments Lesson 4.3 Assignment Name_________________________________________________________ Date__________________________ Two-Color Counters Adding Integers, Part II Ruth’s family is on a road trip from San Francisco, California, to Orlando, Florida. During the first day of the trip, the family drives from San Francisco to Phoenix, Arizona. On the second day, they drive from Phoenix to Las Cruces, New Mexico. On the third day, they drive to San Antonio, Texas, to visit Ruth’s grandmother. After a few days, they drive to Mobile, Alabama. Finally, on the last day of the trip, the family drives to Orlando, Florida. Ruth’s little sister, Josie, is 3 years old. When she isn’t sleeping in the car, she is usually asking, “How much longer?” Ruth’s father is a mathematician and likes to keep his children thinking. 1. When the family drives from San Francisco to Phoenix, Arizona, they get up and leave very early in the morning. Josie takes a morning nap, and when they stop for lunch she asks, “How much longer?” Ruth’s father’s answer is, “The number of hours we have left is equal to the sum of 25 and 13. Ruth, how much longer?” a.Write an expression to show how much longer Ruth’s family has to drive before they get to Phoenix, Arizona. 25 1 13 b.Simplify the expression in part (a) to determine the amount of time they have left. 25 1 13 5 8 The family has 8 hours left before they arrive in Phoenix, Arizona. © 2011 Carnegie Learning c. Draw a model to verify your answer in part (b). – + + + – + + + – + + + – + + – + + Chapter 4 Assignments • 73 Lesson 4.3 Assignment page 2 2. When Ruth’s family drives from Phoenix, Arizona to Las Cruces, New Mexico, it takes them 6 hours to make the trip. Then, they drive to San Antonio, Texas to visit Ruth’s grandmother. After driving a few hours, Ruth’s sister, Josie asks, “How much longer?” Ruth’s father says, “The number of hours we have left is equal to the absolute value of the sum of 24 and 27.” a.Write an expression to show how much longer Ruth’s family has to drive before they get to San Antonio, Texas. | 24 1 (27) | b. Simplify the expression in part (a) to determine the amount of time they have left. | 24 1 (27) | 5 | 211 | 5 11 The family has 11 hours left before they arrive in San Antonio, Texas. 3. After spending a couple of days in San Antonio, Ruth’s family travels to Mobile, Alabama. As soon as her little sister Josie is buckled in her car seat, she asks, “How much longer?” Ruth’s father replies, “The number of hours we must drive today is the sum of 23 and 212.” a.Write an expression to show how long Ruth’s family has to drive to get to Mobile, Alabama. 23 1 (212) 23 1 (212) 5 11 The family has 11 hours left before they arrive in Mobile, Alabama. 74 • Chapter 4 Assignments © 2011 Carnegie Learning b. Simplify the expression in part (a) to determine the length of their drive. Lesson 4.3 Assignment page 3 Name_________________________________________________________ Date__________________________ c. Draw a model to verify your answer in part (b). + + + – – + + + – – + + + – – + + + – – + + + – + + + – + + + – + + © 2011 Carnegie Learning – Chapter 4 Assignments • 75 Lesson 4.3 Assignment page 4 4. On the last day of a long road trip, Ruth’s family is packing the car and getting ready to leave for Orlando, Florida. Before Ruth’s sister Josie can ask how long they must drive, Ruth’s father says, “The sum of 219 and the number of hours we must drive today is 211.” a.Write an expression to show how long Ruth’s family has to drive to get to Orlando, Florida. 219 1 ______5 211 b. Simplify the expression in part (a) to determine the length of their drive. 219 1 8 5 211 The family has 8 hours left before they arrive in Orlando, Florida. c. Draw a model to verify your answer in part (b). – – + – – – + – – – + – – – + – – – + – – + – – + + © 2011 Carnegie Learning – 76 • Chapter 4 Assignments Lesson 4.4 Assignment Name_________________________________________________________ Date__________________________ What’s the Difference? Subtracting Integers 1. Some people have to wear glasses because they are nearsighted, which means they can see close objects clearly. This condition is called myopia. Others have to wear glasses because they are farsighted, meaning they can see far away objects clearly. This condition is called hyperopia. Strength of optical power is measured in a unit known as diopters. The table shows the ranges of optical power strength for each condition. Vision Range of Strength of Optical Power (diopters) Low myopia 23 to 0 Medium myopia 26 to 23 High myopia 26 or higher Low hyperopia 0 to 2 Medium hyperopia 2 to 4 High hyperopia 4 or higher a.When a person needs glasses, they go to an optometrist to get fitted for lenses that will help correct their vision so that they can see everything clearly. The table shows the strength of © 2011 Carnegie Learning optical power for several students. Using the table above, complete the vision column. Student Strength of Optical Power (diopters) Vision Anastasia 22 Low myopia Danica 5 High hyperopia Juan 27 High myopia Bernard 28 High myopia Frank 24 Medium myopia Peter 1 Low hyperopia Chapter 4 Assignments • 77 Lesson 4.4 Assignment page 2 b.Danica says that the difference between her strength of optical power and Frank’s strength of optical power can be calculated using the following expression. 5 2 (24) Draw a counter model and determine the different between Danica’s strength of optical power and Frank’s strength of optical power using her method. + + + + + + – + – + – + – The difference between Danica’s strength of optical power and Frank’s strength of optical power is 9 diopters. c.Frank says the difference between his strength of optical power and Danica’s strength of optical power can be calculated using the following expression. 24 2 5 Draw a counter model and determine the different between Danica’s strength of optical power and Frank’s strength of optical power using his method. – – + – – + – – + – – + – + The difference between Frank’s strength of optical power and Danica’s strength of optical power is 29 diopters. 78 • Chapter 4 Assignments © 2011 Carnegie Learning Lesson 4.4 Assignment page 3 Name_________________________________________________________ Date__________________________ d. Who is correct, Frank or Danica? Use a number line to help explain your answer. 9 –15 –4 –5 –10 0 5 10 15 The actual difference between Frank’s strength of optical power and Danica’s strength of optical power is the absolute value of either expression. So, neither Frank nor Danica is entirely correct. If you plot each student’s strength of optical power on a number line, you will notice that the distance between them is 9. e. Write an expression that represents the difference between Juan’s strength of optical power and Peter’s strength of optical power. Then, use the number line to calculate the difference and explain your answer. |27 2 1| or |1 2 (27)| 8 –15 –10 –7 –5 0 1 5 10 15 The difference between Juan’s strength of optical power and Peter’s strength of optical power is 8 diopters. If you plot each student’s strength of optical power on a number line, you will notice that the distance between them is 8. f. Write an expression that represents the difference between Bernard’s strength of optical power and Anastasia’s strength of optical power. Then, use the number line to calculate the difference © 2011 Carnegie Learning and explain your answer. | 28 2 (22) | or | 22 2 (28) | 6 –15 –10 –8 –5 –2 0 5 10 15 The difference between Bernard’s strength of optical power and Anastasia’s strength of optical power is 6 diopters. If you plot each student’s strength of optical power on a number line, you will notice that the distance between them is 6. Chapter 4 Assignments • 79 Lesson 4.4 Assignment page 4 g. Determine the difference between the strength of optical power for the student with the highest myopia and the student with the highest hyperopia. Show your work. Use a number line to verify your answer. 13 –15 –10 –8 –5 0 5 10 15 | 28 2 5 | 5 | 213 | 5 13 The student with the highest myopia is Bernard and the student with the highest hyperopia is Danica. The difference between Bernard’s and Danica’s strengths of optical power is 13 diopters. If you plot each student’s strength of optical power on a number line, you will notice that the distance between them is 13. h.Frank says that the difference between his strength of optical power and that of another student is 2 diopters. Write a number sentence to represent Frank’s statement and determine which student Frank is referring to. Explain your answer. | 24 2 __ | 5 2 The other student is Anastasia. Her strength of optical power is 22 and © 2011 Carnegie Learning |242(22)| 5 | 22 | or 2. 80 • Chapter 4 Assignments Lesson 4.5 Assignment Name_________________________________________________________ Date__________________________ What Do We Do Now? Adding and Subtracting Rational Numbers © 2011 Carnegie Learning 1. The table shows the freezing points of some of the elements in the periodic table. Element Freezing Point (°F) Helium 2458 Hydrogen 2434 Oxygen 2368.77 Nitrogen 3 2345 __ 4 Chlorine 2149.51 Mercury 7 237 ___ 10 Phosphorus 111.7 Potassium 146.03 Sodium 208 Sulfur 239.65 Lead 7 621 ___ 10 Zinc 787.51 Chapter 4 Assignments • 81 Lesson 4.5 Assignment page 2 a. What is the difference between the freezing points of Zinc and Potassium? Show your work. 787.51 2 146.03 5 641.48 The difference between the freezing points of Zinc and Potassium is 641.48 degrees. b. What is the difference between the freezing points of Chlorine and Helium? Show your work. 2149.51 2 (2458) 5 308.49 The difference between the freezing points of Chlorine and Helium is 308.49 degrees. c. How much greater is the freezing point of Lead than the freezing point of Nitrogen? Show your work. ( ( ) ) 3 15 14 2 2345 ___ 7 2 2345 __ 5 621 ___ 621 ___ 10 20 20 4 9 degrees The freezing point of Lead is 967 ___ greater than the freezing point of Nitrogen. 20 9 5 967 ___ 20 d. How much less is the freezing point of Chlorine than the freezing point of Zinc? 787.51 2 (2149.51) 5 937.02 The freezing point of Chlorine is 937.02 degrees less than the freezing point of Zinc. 82 • Chapter 4 Assignments © 2011 Carnegie Learning Show your work. Lesson 4.5 Assignment page 3 Name_________________________________________________________ Date__________________________ e. Patricia and Elliott are trying to figure out how much the temperature would have to increase from the freezing point of Hydrogen to reach the freezing point of Phosphorus. Patricia says the temperature would have to increase 545.7 degrees, and Elliott says the temperature would have to increase 322.3 degrees. Who is correct? Show your work and explain your reasoning. 2434 1 545.7 5 111.7 2434 1 322.3 5 2111.7 Patricia is correct. The temperature would have to increase 545.7 degrees from the freezing point of Hydrogen to reach the freezing point of Phosphorus. If the temperature increases only 322.3 degrees, it will still be a negative temperature. The freezing point of Phosphorus is 111.7 degrees Fahrenheit. f. Francine and Lisa are trying to figure out how much the temperature would have to increase © 2011 Carnegie Learning from the freezing point of Nitrogen to reach the freezing temperature of Mercury. Francine says 1 degrees, and Lisa says the temperature would the temperature would have to increase 308 ___ 20 9 degrees. Who is correct? Show your work and explain your reasoning. have to increase 383 ___ 20 15 1 308 ___ 3 1 308 ___ 1 1 5 2345 ___ 2345 __ 4 20 20 20 7 5 237 ___ 10 3 1 383 ___ 15 383 ___ 9 9 5 2345 ___ 1 2345 __ 4 20 20 20 7 5 37 ___ 10 1 degrees Francine is correct. The temperature would have to increase 308 ___ from 20 the freezing point of Nitrogen to reach the freezing point of Mercury. If the temperature 9 degrees, it will be a positive temperature. The freezing point of Mercury increases 383 ___ 20 7 ___ Fahrenheit. is 237 degrees 10 Chapter 4 Assignments • 83 © 2011 Carnegie Learning 84 • Chapter 4 Assignments
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