AP Physics Mr. Brooks 04/26/2013 Mirrors and Lenses 1. A concave spherical mirror has a radius of curvature of 20.0 cm. Locate the images for object
distances of (a) 40.0 cm, (b) 20.0 cm, and (c) 10.0 cm. In each case, state whether the image is real or
virtual, upright or inverted and find the magnification.
a.) The image is 13.3 cm in front of the mirror, real and inverted. b.) The image is 20.0 cm in front of the mirror, real and inverted. c.) No image is formed, parallel rays leave the mirror. 2. A 2.00 cm high object is placed 3.00 cm in front of a concave mirror. If the image is 5.00 cm high
and virtual, what is the focal length of the mirror?
5.00 cm 3. A man standing 1.52 m in front of a shaving mirror produces an inverted image 18.0 cm in front of it.
How close to the mirror should he stand if he wants to form an upright image of his chin that is twice
the chin’s actual size?
8.05 cm 4. A child holds a candy bar 10.0 cm in front of a convex mirror and notices that the image is only one
half the size of the candy bar. What is the radius of curvature of the mirror?
-­20.0 cm 5. A spherical mirror is being used to form an image, five times as tall as an object, on a screen
positioned 5.00 m from the mirror. (a) Describe the type of mirror required. (b) Where should the
mirror be positioned relative to the object?
a.) concave b.) 1.00 m in front of the mirror 6. A converging lens has a focal length of 20.0 cm. Locate the image for object distances of
(a) 40.0 cm, (b) 20.0 cm, and (c) 10.0 cm. For each case, state whether the image is real or virtual,
upright or inverted and find the magnification.
a.) The image is real, inverted and 40.0 cm beyond the lens. b.) No image formed. Parallel rays leave the lens. c.) The image is virtual, upright, and 20.0 cm in front of the lens. AP Physics Mr. Brooks 04/26/2013 7. A diverging lens has a focal length of 20.0 cm. Locate the image for object distances of (a) 40.0 cm,
(b) 20.0 cm, and (c) 10.0 cm. For each case, state whether the image is real or virtual, upright or
inverted and find the magnification.
a.) The image is virtual, upright and 13.3 cm in front of the lens. b.) The image is virtual, upright and 10.0 cm in front of the lens. c.) The image is virtual, upright, and 6.67 cm in front of the lens. 8. The nickel’s image shown below has twice the diameter of the nickel when the lens is 2.84 cm from
the nickel. Determine the focal length of the lens.
5.68 cm 9. An object is placed 20.0 cm to the left of a converging lens of focal length 25.0 cm. A diverging lens
of focal length 10.0 cm is 25.0 cm to the right of the converging lens. Find the position and the
magnification of the final image.
The final image is 9.26 cm in front of the second lens and the overall magnification is +0.370 10. Two converging lenses, each of focal length 15.0 cm, are placed 40.0 cm apart, and an object is
placed 30.0 cm in front of the first lens. Where is the final image formed, and what is the
magnification of the system?
The final virtual image is 30.0 cm in front of the second lens and the overall magnification is -­3.00