Areas of Shapes Area of a Rectangle Area = length × width = a×b Example 1 Find the area of the rectangle: Area Area of a Square A square is a rectangle with equal sides. Area = length × width =a×a = a2 Example 2 Find the area of the square: Area = 3 cm × 3 cm = 9 cm2 Gareth Lotwick, March 2006 = 5 mm × 3 mm = 15 mm2 Calculating the Area of a Triangle Case 1: Right-angled Triangles It can be seen that the area of ∆ ABC is half the area of the rectangle ABCD. Area of ∆ ABC = ½(AB × BC) = ½ base length × perpendicular height Case 2: Triangles which are not right angled Consider a ∆ ABC as shown which is not rightangled. Draw AD such that AD is perpendicular to BC Area of ∆ ABC = Area ∆ ABD + Area ∆ ACD = ½(BD×AD) + ½(DC×AD) = ½ (BD + DC)×AD = ½ BC×AD = ½ base length × perpendicular height So whether a triangle is right-angled or not, the area can be calculated in the same way. Area of a Triangle Area = ½ base length × perpendicular height = ½ a ×b Areas of Shapes Page 2 of 6 Student Development & Study Skills Service Example 3 Find the area of ∆ ABC Area = ½ × 4cm × 5cm = 10 cm2 Example 4 Find the area of ∆ ABC Area = ½ × 4 cm × 6 cm = 12 cm2 Area of a Trapezium This is a quadrilateral with one pair of parallel sides. Area = ½ ×sum of parallel sides × distance between them = ½ (a + b) c So why is this the area of a trapezium? Area ABCF = Area ∆ AEF + Area ABDE + Area ∆ BDC = ½ EF×c + ac + ½ CD×c = [ ½EF + a + ½ CD ] c = [ ½a + (½EF + ½a + ½ CD) ] c = ½ [ a + (EF + a + CD)] c = ½ (a + b) c Areas of Shapes Page 3 of 6 Student Development & Study Skills Service Example 5 Find the area of the Trapezium Area = ½ (12 mm + 21 mm) × 8 mm = ½ × 33 × 8 = 132 mm2 Area of a Circle Area = π r2 where r is the radius of the circle. Area of a Semi-circle This is half the area of a circle, so Area = ½ π r 2 where r is the radius of the circle. Example 6 Find the area of the circle Area = π × 52 = 78.54 cm2 Example 7 Find the area of the semi-circle Radius = ½ × 3 mm = 1.5 mm Area = ½ π × 1.52 = 3.53 mm2 Areas of Shapes Page 4 of 6 Student Development & Study Skills Service Example 8 A garden consists of a rectangular lawn and semi-circular flower bed of radius 2.5 m as shown. Determine the area of the garden. Area of lawn = 8 × 5 = 40 m2 Area of flower bed =½ π × 2.52 = 9.82 m2 Total area of garden = 40 + 9.82 = 49.82 m2 Exercises 1. Find the area of a rectangle, length 12 m, breadth 8 m. 2. Find the area of the triangle shown 3. A triangle with a base of 3m has an area of 30m2. What is the height of the triangle? 4. Find the area of the trapezium shown 5. Find the area of a circle with diameter 4 mm. 6. Find the area of a semi-circle of radius 3 cm. 7. A circle has an area of 100m2, what is its radius? Areas of Shapes Page 5 of 6 Student Development & Study Skills Service Answers 1) 96m2 2) 15cm2 3) Area ∆ = ½ base length × perpendicular height 30m2 = ½ × 3m × height = 1.5 × height So height = 30 / 1.5 = 20m 4) 16.5m2 5) 12.57 mm2 6) 14.14cm2 7) Area = π r 2 100m2 = π r 2 100 So r = = 5.64 m Areas of Shapes Page 6 of 6 Student Development & Study Skills Service
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