Problem: In the pool, there are two swimmers. They decided they

Background: For years parents
and faculty tried to think of
ways to finance for a new pool.
Later, they instructed Theodore
Vierra to draw the plans for
making an olympic sized pool.
Also, they needed locker rooms
for both boys and girls. The
pool including both the P.E and
Athletic Department locker
rooms cover 24,090 square feet
and cost $591,621. The pool
was dedicated to princess Ruth
Ke‘elikölani and was dedicated
on May 1, 1964 before a crowd.
The ceremony included prayers,
speeches, songs, and water
ballet by girls from Punahou.
The pool is used for many
events such as swimming
tournaments, water polo games,
and diving tournaments. It is
also used for P.E classes in
their swimming units.
Math Concept:
Systems of equations
Math Standard:
Algebra
Problem: In the pool, there are
two swimmers. They decided
they wanted to see who can
swim further down in the
deepest part of the pool.
Swimmer #2's depth was 4
feet less than 3 times the 1st
swimmers depth. Both their
depths add up to 23 feet.
Solve and find the depths for
both the swimmers. What is
the percent of difference
between the two swimmers.
Problem: In the pool, there are
two swimmers. They decided
they wanted to see who can
swim further down in the
deepest part of the pool.
Swimmer #2's depth was 5
feet less than 3 times the 1st
swimmers depth. Both their
depths add up to 23 feet.
Solve and find the depths for
both the swimmers. What is
the percent of difference
between the two swimmers.
Solution: Variables~ Swimmer 1= x Swimmer 2= y
Make two equations~ x+y=23------ y=3x-5
Use the substitution method~ x+3x-5=23
simplify the equation~ 4x-5=23
Add four to both sides~ 4x-5+5=23+5
Simplify~ 4x=28
Divide by four on both sides~ 4x/4=28/4
x=7
New equation~ 7+y=23
Subtract 7 from both sides~ 7+y-7=23-7
Answer~Swimmer 1= 7 feet~~~~ Swimmer 2= 16 feet
16-7= 9~Find difference
9/16=x/100~Make equation
56.25%~ Solve for x
56.25% difference
MATH CONCEPT- Systems of Equations
MATH STANDARD-Algebra