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1. A grazes 10 sheep for 3 weeks and B grazes 15 sheep for 4 weeks in a field. In what ratio
should they divide a rent of Rs. 60?
a. 1:2
b. 2:1
c. 3:4
d. 4:1
2. A man saves Rs. 200 at the end of each year and lends the money at 5% compound
interest. How much it will become at the end of 3 years?
a. Rs. 635.00
b. Rs. 662.02
c. Rs. 666.50
d. Rs. 565.25
3. A person purchases 90 clocks and sells 40 clocks at a gain of 10% and 50 clock sat a gain
of 20%. If he sold all of them at a uniform profit of 15%, then he would have got Rs.40 less.
Find the cost price of each clock.
a. Rs.60
b. Rs. 90
c. Rs. 80
d. Rs. 50
4. When the price of cloth was reduced by 25%, then the quantity of cloth sold increased by
20%. What was the effect on the gross receipt?
a. 5% increase
b. 5% decrease
c. 10% increase
d. 10% decrease
5. If 6 men can do a piece of work in 20 days and one man can do the work of two boys, then
in how many days can 10 men and 5 boys do the same work?
a. 8 days
b. 10 days
c. 12 days
d. None of these
6. X can do a piece of work in 40 days. He works at it for 8 days and then Y finished it in 16
days. How long will they together take to complete the work?
a. 20 days
b. 15 days
c. 56 days
d. 40/3 days
7. A sum was put at S.I at a certain rate for 2 years. Had it been put at 3% higher rate, it
would have fetched Rs. 72 more. The sum is
a. Rs.1200
b. Rs.1500
c. Rs.1600
d. Rs.1800
8. The CI on Rs. 30,000 at 7% per annum is Rs.4347. The period in year is
a. 2
b. 2 ½
c. 3
d. 4
9. Find the length of a rope by which a cow must be tethered in order that it may graze and
area of 9856 sq.metres.
a. 60 m
b. 56 m
c. 62 m
d. 65 m
10. From a rectangular wooden block of dimension 20 cm X 5 cm X 2 cm, a cone of height
14 cm and base radius 3 cm is carved out. Find the wastage percentage of wood.
a) 37%
b) 36%
c) 34%
d) 41%
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141. a A:B dividing ratio = (10 X 3) : ( 15 X 4) = 1:2, option ‘a’
142. b 1st year = 200 X 5/100 = 10. 2nd year = 410 X 5/100 = 20.5. ( 210+200=410)3rd
year= 630.5 X 5/100 = 31.52. ( 410 + 20.5+ 200 = 630.5) Therefore,total= 630.5+31.52 = Rs
662.02, option ‘b’
143. c Let the cost of clock be x. Thus, we have the following: (x + 10x/100)40 + (x +
20x/100)50 =(x + 15x/100)90 +40. Solving, we get x= 80, option ‘c’
144. d To get gross receipt, apply the formula x+y +xy/100. Here, we have x= -25, y= 20.
substituting , we get –10, which implies, 10% decrease in gross receipt, option ‘d’
145. d 12 boys can do the work in 20 days, hence, 25 boys can do in 48/5 days, hence option
‘d’
146. d x in 1 day= 1/40, so x in 8 days= 1/5 of work. Balance 4/5 done by y in 16 days. So y
can do the work in 20 days. Therefore, in 1 day x + y = 1/40 + 1/20 =3/40. So together they
would complete in 40/3 days, option ‘d’
147.a Let ‘P’ be the principle, ‘R’ be the rate of interest. We have, (P X 2 X R)/100 + 72 =
((PX 2 X (R+3))/100. ‘P’ will be 1200 option ‘a’
148.a Interest on 1st year = 2100. Principle for 2nd year = 32100. Interest on 2nd year =
2247. Therefore accumulated interest = 4347, hence the period is 2 years, option ‘a’
149. b Given that ╥R2 = 9856, solving, R = 56 option ‘b’
150. c Volume of wood = 200 cu cms. Volume of cone = 1/3 ╥R 2 h = 132 cu cms.
Therefore, wastage = 68 cu cms. Wastage % = 68/200 X 100 = 34 option ‘c’
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