Extra Practice - Stoichiometry Answers

Honors Chemistry
Extra Stoichiometry Problems
1. Silver nitrate reacts with barium chloride to form silver chloride and barium nitrate.
a. Write and balance the chemical equation.
2 AgNO3 + BaCl2 ! 2 AgCl + Ba(NO3)2
b. If 39.02 grams of barium chloride are reacted in an excess of silver nitrate, how many
representative particles (and what type) of silver chloride are produced?
39.02 𝑔 π΅π‘ŽπΆπ‘™!
1 π‘šπ‘œπ‘™π‘’ π΅π‘ŽπΆπ‘™!
2 π‘šπ‘œπ‘™π‘’π‘  𝐴𝑔𝐢𝑙 6.02 π‘₯ 10!" 𝑓. 𝑒. 𝐴𝑔𝐢𝑙
π‘₯ π‘₯ π‘₯ = 2.256 π‘₯ 10!" 𝑓. 𝑒. 𝐴𝑔𝐢𝑙
1
208.233 𝑔 π΅π‘ŽπΆπ‘™! 1 π‘šπ‘œπ‘™π‘’ π΅π‘ŽπΆπ‘™!
1 π‘šπ‘œπ‘™π‘’ 𝐴𝑔𝐢𝑙
c. If 410.8 grams of barium nitrate are produced how many grams of silver nitrate were
reacted?
410.8 𝑔 π΅π‘Ž(𝑁𝑂! )!
1 π‘šπ‘œπ‘™π‘’ π΅π‘Ž(𝑁𝑂! )!
2 π‘šπ‘œπ‘™π‘’π‘  𝐴𝑔𝑁𝑂!
169.872 𝑔 𝐴𝑔𝑁𝑂!
π‘₯ π‘₯ π‘₯ = 534.1 𝑔 𝐴𝑔𝑁𝑂!
1
261.335 𝑔 π΅π‘Ž(𝑁𝑂! )! 1 π‘šπ‘œπ‘™π‘’ π΅π‘Ž(𝑁𝑂! )!
1 π‘šπ‘œπ‘™π‘’ 𝐴𝑔𝑁𝑂!
2. Nitrogen gas is reacted with hydrogen gas to form nitrogen trihydride.
a. Write and balance the chemical equation.
N2(g) + 3 H2(g) ! 2 NH3(g)
b. How many liters of nitrogen trihydride are produced at STP if 80.28 grams of hydrogen
gas are reacted in an excess of nitrogen?
80.28 𝑔 𝐻!
1 π‘šπ‘œπ‘™π‘’ 𝐻!
2 π‘šπ‘œπ‘™π‘’π‘  𝑁𝐻!
22.4 𝐿 𝑁𝐻!
π‘₯ π‘₯ π‘₯ = 594.7 𝐿 𝑁𝐻!
1
2.016 𝑔 𝐻!
3 π‘šπ‘œπ‘™π‘’π‘  𝐻!
1 π‘šπ‘œπ‘™π‘’ 𝑁𝐻!
c. How many grams of hydrogen are needed to fully react 621.9 grams of nitrogen gas?
621.9 𝑔 𝑁!
1 π‘šπ‘œπ‘™π‘’ 𝑁!
3 π‘šπ‘œπ‘™π‘’π‘  𝐻! 2.016 𝑔 𝐻!
π‘₯ π‘₯ π‘₯ = 134.3 𝑔 𝐻!
1
28.014 𝑔 𝑁!
1 π‘šπ‘œπ‘™π‘’ 𝑁!
1 π‘šπ‘œπ‘™π‘’ 𝐻!
d. How many liters of nitrogen gas are needed to completely react 90.38 L of hydrogen gas
at STP?
90.28 𝐿 𝐻! 1 π‘šπ‘œπ‘™π‘’ 𝐻! 1 π‘šπ‘œπ‘™π‘’ 𝑁!
22.4 𝐿 𝑁!
π‘₯ π‘₯ π‘₯ = 30.09 𝐿 𝑁! 1
22.4 𝐿 𝐻!
3 π‘šπ‘œπ‘™π‘’ 𝐻! 1 π‘šπ‘œπ‘™π‘’ 𝑁!
OR
90.28 𝐿 𝐻! 1 𝐿 𝑁!
π‘₯ = 30.09 𝐿 𝑁!
1
3 𝐿 𝐻!
3. For the following problem, use the following chemical equation:
C8H18(l) + O2(g) ! CO2(g) + H2O(g)
a. Balance the chemical equation.
2 C8H18(l) + 25 O2(g) ! 16 CO2(g) + 18 H2O(g)
b. How many moles of oxygen are needed to fully react 837.4 grams of C8H18?
837.4 𝑔 𝐢! 𝐻!"
1 π‘šπ‘œπ‘™π‘’ 𝐢! 𝐻!"
25 π‘šπ‘œπ‘™π‘’π‘  𝑂!
π‘₯ π‘₯ = 91.63 π‘šπ‘œπ‘™π‘’π‘  𝑂!
1
114.232 𝑔 𝐢! 𝐻!" 2 π‘šπ‘œπ‘™π‘’π‘  𝐢! 𝐻!"
c. How many liters of carbon dioxide gas are formed at STP when 3.829 x 1025
representative particles of C8H18 are reacted in an excess of oxygen gas?
3.829 π‘₯ 10!" π‘šπ‘œπ‘™π‘’π‘π‘’π‘™π‘’π‘  𝐢! 𝐻!"
1 π‘šπ‘œπ‘™π‘’ 𝐢! 𝐻!"
16 π‘šπ‘œπ‘™π‘’π‘  𝐢𝑂!
22.4 𝐿 𝐢𝑂!
π‘₯ π‘₯ π‘₯ = 1.140 π‘₯ 10! 𝐿 𝐢𝑂!
!"
1
6.02 π‘₯ 10 π‘šπ‘œπ‘™π‘’π‘π‘’π‘™π‘’π‘  𝐢! 𝐻!" 2 π‘šπ‘œπ‘™π‘’π‘  𝐢! 𝐻!" 1 π‘šπ‘œπ‘™π‘’ 𝐢𝑂!
d. How many grams of water are produced when 382.9 liters of oxygen gas at STP are
fully reacted?
382.9 𝐿 𝑂! 1 π‘šπ‘œπ‘™π‘’ 𝑂! 18 π‘šπ‘œπ‘™π‘’π‘  𝐻! 𝑂 18.015 𝑔 𝐻! 𝑂
π‘₯ π‘₯ π‘₯ = 221.7 𝑔 𝐻! 𝑂
1
22.4 𝐿 𝑂!
25 π‘šπ‘œπ‘™π‘’π‘  𝑂!
1 π‘šπ‘œπ‘™π‘’π‘  𝐻! 𝑂