Atomic Structure – Revision Pack (C4) Atoms: A nucleus is made up of neutral neutrons and positive protons. The nucleus is surrounded by negatively charged electrons. The nucleus is positive but the atom has no overall charge because the protons and electrons cancel each other out. Subatomic particle Relative charge Relative mass Proton +1 1 Neutron 0 1 Electron -1 0.0005 Element – made up of one type of atom; cannot be chemically broken down Compound – made of two or more elements that are chemically combined Mass and Atomic Number: 19 9 F The mass number is the larger number of the two. It represents how many neutrons and protons there are in the atom. The atomic number is the smaller number of the two. It represents how many protons there are in the atom. The number of protons is equal to the number of electrons. An atom is neutral because it has the same number of protons as neutrons; the positives cancel out the negatives. The number of neutrons is equal to the mass number take away the atomic number. Arrangement of electrons: The elements of the periodic table are arranged in order of increasing atomic number. The amount of electrons is different for the shells of an atom: Atomic Structure – Revision Pack (C4) The maximum number of electrons for the first shell is 2. The maximum number of electrons for all of the shells from then is 8. Na (shown to the left) has an electronic structure. This is 2.8.1 – two electrons in the 1st shell, 8 in the 2nd and 1 in the 3rd. The number of electron is equal to the proton number; so 2 + 8 + 1 = 11 which is the atomic (proton) number of sodium (Na). Groups and Periods: Periods = rows = number of occupied shells Groups = columns = number of electrons on outer shell Isotopes: Isotopes are elements that have the same atomic number, but differing mass numbers; this means that they have different numbers of neutrons. Isotope The different number of neutrons can be deduced, as with these lithium isotopes. Electrons Protons Neutrons 3 3 3 3 3 4 3 3 5 Atomic Structure – Revision Pack (C4) Developing the Theory: John Dalton created the original theory, which was provisional meaning it could be changed later. The theory was later confirmed by better evidence. J.J. Thompson, Rutherford and Bohr all found new evidence that changed the explanation of the model of the atom. With later evidence their predictions were confirmed. Unexpected results also change ideas rapidly. For example, Geiger and Marsden had some unexpected results which made significant contributions to the ideas of Rutherford and Bohr. Past Papers: PPQ(1): OCR Gateway June 2013 C4 C5 C6 PPQ(2): OCR Gateway June 2013 C4 C5 C6 PPQ(3): Atomic Structure – Revision Pack (C4) OCR Gateway June 2013 B4 C4 P4 Mark Schemes: PPQ(1): PPQ(2): PPQ(3): Atomic Structure – Revision Pack (C4) Why bonding? To be stable, atoms must have a full outer shell. Atoms can be made stable by transferring electrons and this is called ionic bonding. Ionic bonding ONLY happens between the group 1 (alkali) metals and non-metals. Ions are charged particles, they are either: - Positive – if they have lost an electron (e.g. Na+ or Cu2+) Negative – if they have gained (or taken) an electron (e.g. O2- or Cl-) Non-metals gain electrons to help them to get a stable electronic structure. If an atom gains an electron it becomes negatively charged because there are more negative electrons than there are positive protons. Metals gain electrons to help them to get a stable electronic structure. If an atom loses an electron it becomes positively charged because there are more positive protons in the nucleus than there are negative electrons. When ionic bonding happens, the metals become negative ions and the nonmetals become negative ions. The positive and negative ions are then attracted to one another. Dot and Cross diagrams are used to show ionic bonding: This is the bonding of magnesium oxide (MgO). Mg has the electronic structure 2.8.2 O has the electronic structure 2.6 For Mg to gain stability it has to lose two electrons. For O to gain stability it has to gain two electrons. When they reactant, there is transfer of electrons and both Mg and O are now stable. YOU must be able to draw these! Ionic compounds: Positive and negative have to cancel out. Some examples of this include: Na+ and Cl- - cancel out to make NaCl Cu2+ and Cl- - you need two Cl to cancel out the Cu2+ so makes CuCl2 Atomic Structure – Revision Pack (C4) Mg2+ and O2- - cancel out to make MgO Mg2+ and Cl- - you need two Cl to cancel out the Mg2+ so makes MgCl2 Na+ and O2- - you need two Na to cancel out the O2- so makes Na2O There is a big difference between the atom of an element and the ion of an element. For example, for a sodium atom to become stable it has to lose one electron from its outer shell. This forms a sodium ion which is fully stable. However, for negative ions there is a slight difference in what the ion is called; if an atom has to gain electrons to become stable its ion ends in ‘ide’. For example, a fluorine atom needs one electron to become stable or have a full outer shell. This forms an ion called a fluoride ion. Giant Ionic Lattice: The structure of compounds like NaCl and MgO is a giant ionic lattice. In this, positive ions have strong electrostatic forces to negative ions. They ALWAYS exist as solids. The strong electrostatic forces mean that these compounds have very high melting points. They can conduct electricity when molten or in solution because the ions are free to move. Magnesium Oxide High melting point (strong bonds) – used in fire-resistant materials Sodium Chloride High melting point (strong bonds) Insoluble in water Dissolves in water Conducts electricity when molten (ions free to move) Conducts electricity when molten and in solution (ions free to move) The melting point of different compounds is dependent on the amount of electrons that are transferred. For example, in MgO there are Mg2+ ions as opposed to in NaCl Atomic Structure – Revision Pack (C4) where there is just Na+ ions. This means there is a stronger electrostatic attraction and because two electrons have been donated there is a stronger bond. Past Papers: PPQ(1) PPQ(2): OCR Gateway June 2013 C4 C5 C6 Atomic Structure – Revision Pack (C4) OCR Gateway June 2013 B4 C4 P4 Mark Schemes: PPQ(1): PPQ(2): Atomic Structure – Revision Pack (C4) Metal Properties: Metal properties can be both chemical and physical. Chemical Properties - Resistance to attack by oxygen or other acids (shown by gold and aluminium) – makes it useful for car bodies, so they are not oxidised by rain Physical Properties - High thermal conductivity (shown by copper) – which is good for pots and pans - Lustrous and shiny (shown by aluminium & most other metals) – aesthetically pleasing - Malleable – can be hammered or pressed in to shape without breaking or cracking (shown by most metals) – good for making things like coins - Ductile – meaning it can be deformed and maintain Atomic Structure – Revision Pack (C4) - toughness (like steel) – used in wires Low Density (shown by aluminium) – lightweight so is often used in car bodies or aircrafts Metallic Bonding: Metals will generally always have high melting and boiling points. This is because of the strong metallic bonds that they possess. The bonding between atoms is very strong and a lot of energy is required to break these bonds. Metals like copper, gold and silver all conduct electricity. When they do this, the electrons in the metal move generating a charge. A metallic bond is a strong electromagnetic force between positively charged and tightly-packed metal ions and a ‘sea’ of delocalised electrons. (NOTE - ELECTROMAGNETIC FORCE is generated by differences in electrical charge – here the ions are positive and the electrons are negative!) The delocalised electrons can move through the metal very easily – this is why metals can conduct electricity. Metals have high melting and boiling points because a great deal of energy is required to break and overcome the STRONG attraction between delocalised electrons and close-packed metal ions. Superconductors: A superconductor is a material that conducts electricity with little or no resistance. Although copper, gold and silver are good conductors of electricity they DO NOT become superconductors. Mercury does become a superconductor, but at a very low temperature (-268.8oC). At this temperature the electrical resistance falls to zero. After a substance goes from its normal state to an electromagnetic state, it no longer has magnetic fields inside it. When you put a small magnet next to a superconductor, it is repelled. If you put a small permanent magnet above a superconductor, it levitates (as seen to the left). Atomic Structure – Revision Pack (C4) There are many potential benefits of superconductors, including: - Loss-free power transmission Super-fast electronic circuits Powerful electromagnets However, there are also many drawbacks with superconductors as well, for example: - They work at very low temperatures and this limits their uses However, scientists are working on a superconductor that works at room temperature (20 degrees Celsius). Past Papers: PPQ(1): Atomic Structure – Revision Pack (C4) PPQ(2): Atomic Structure – Revision Pack (C4) Mark Schemes: Atomic Structure – Revision Pack (C4) PPQ(1): PPQ(2): Purifying Water River water is often cloudy and not suitable to drink. To make it in to clean and drinkable water, it goes through a ‘water purification works’. Some pollutants get into water before purification. For example, nitrates often enter rivers from nitrogen in fertilisers and pesticides from crop spraying to kill insects often gets into the water prior to purification. Occasionally, some pollutants also get into the water AFTER purification. For example, some older houses will have lead water pipes. Gradually, the lead dissolved into the water. Water that has not yet been purified may also contain: microbes, leaves, salts and minerals. This is why purification must take place; this happens in three simple steps: Sedimentation: Chemicals are added to make solid particles and bacteria settle out. Filtration: Fine particles are filtered (and thus removed). A layer of sand on gravel filters Chlorination: Finally, chlorine is added to kill any remaining microbes within the water. This Atomic Structure – Revision Pack (C4) These steps do cost money, so water must be conserved (not wastefully overused). This can be used to provide clean water. Water is RENEWABLE (i.e. not used up or depleted when used) but the supply is certainly not endless. If it doesn’t rain enough in the winter then reservoirs don’t fill up. Also, in the UK more and more homes are being built which increases the demand for water. We also need to be careful as it takes energy to pump and purify water and this contributes to global warming (an increase in the Earth’s temperature). On occasion, soluble substances are not removed by water purification because they are dissolved in the water. Examples include nitrates from fertilisers and pesticides from crop spraying. Extra processes are required to remove these substances. This cannot happen with water from the sea because there are too many substances dissolved within it. To remove these, further distillation is required which required huge amounts of energy meaning that the process is very expensive. This is why sea water is only purified in rare cases, like when there is NO fresh water. Testing Water: Water can be tested using a precipitation reaction. Two aqueous solutions are used: Barium Chloride (BaCl2) or Silver Nitrate (AgNO3). In a precipitation reaction, two solutions react to form an insoluble chemical. This chemical will turn from liquid to solid (this is known as the precipitate) and from the colour you can identify what chemical was present. If you are testing for SULPHATE ions: STEP 1 – add the water sample to a test tube STEP 2 – add some barium chloride (BaCl2) STEP 3 - if any SULPHATE ions are present a white precipitate is formed (as seen to the left). The balanced symbol equation for this reaction would be: BaCl2 + MgSO4 BaSO4 + MgCl2 Barium Chloride + Magnesium Sulphate Barium Sulphate + Magnesium Chloride Precipitate Atomic Structure – Revision Pack (C4) If you were testing for CHLORIDE, BROMIDE or IODIDE ions: STEP 1 – add the water sample to a test tube STEP 2 – add some Silver Nitrate (AgNO3) STEP 3 – If any: - CHLORIDE ions are present, a white precipitate is formed (1st in picture to left) BROMIDE ions are present, a cream precipitate is formed (2nd in picture to left) IODIDE ions are present, a yellow precipitate is formed (3rd in picture to left) The balanced symbol equations for the reaction with silver nitrate would be: AgNO3 + NaCl AgCl + NaNO3 (CHLORIDE ions – white precipitate) AgNO3 + NaBr AgBr + NaNO3 (BROMIDE ions – cream precipitate) AgNO3 + NaI AgI + NaNO3 (IODIDE ions – yellow precipitate) NOTE – this is used to test water – do NOT forget that! Past Papers: PPQ(1): Atomic Structure – Revision Pack (C4) PPQ(2): Atomic Structure – Revision Pack (C4) PPQ(3): Atomic Structure – Revision Pack (C4) PPQ(4): Atomic Structure – Revision Pack (C4) 6 (a) This question is about drinking water. Washing-up liquid can pollute drinking water. Another pollutant is nitrates. Suggest how nitrates could get into drinking water. ................................................................................................................................. [1] (b) Joe is testing some water samples. He adds silver nitrate solution and barium chloride solution to different water samples. Look at the table. It shows his results. Water sample Result with silver nitrate solution Result with barium chloride solution A White Precipitate Colourless Solution B Cream Precipitate Colourless Solution C Colourless Solution White Precipitate ...................................................... ....................................................... D (i) What water sample contains bromide ions? ...................................................................................................................... [1] (ii) What water sample contains chloride ions? ...................................................................................................................... [1] (iii) Sample D contains iodide and sulphate ions. Complete the table. ...................................................................................................................... [1] PPQ(5): Atomic Structure – Revision Pack (C4) Mark Schemes: Atomic Structure – Revision Pack (C4) PPQ(1): PPQ(2): PPQ(3): PPQ(4): Question Answer Marks Guidance Atomic Structure – Revision Pack (C4) 9 (a) (Run off) from 1 Allow sewage / NPK fertilisers (1) 9 (b) (i) B (1) 1 9 (b) (ii) A (1) 1 9 (b) (iii) Silver nitrate – yellow 1 Both required for the mark precipitate and barium chloride – white precipitate (1) PPQ(5): Question 4 (a) Answer Insoluble material is Marks 1 removed / named Guidance Allow twigs / leaves / sand / dirt removed Ignore small particles removed insoluble material removed (1) 4 (b) Soluble substances 1 Ignore lead particles present by allow lead are not removed by ions present (1) water purification / Allow there are still dissolved substances AW (1) present / soluble pollutants still present / nitrates present / pesticides present (1) 4 (c) (i) Distillation (1) 1 Allow evaporation and condensation (1) Allow reverse osmosis (1) 4 (c) (ii) Large energy 1 Reject uses fossil fuels (0) but needs a lot requirement / need to of fossil fuels for heating (1) boil a lot of water / Ignore references to other costs (0) needs lots of heat / needs lot of electricity (1) Properties of Alkali Metals: The group 1 metals are also known as the ‘alkali metals’. They include caesium, rubidium, lithium, sodium and potassium. They all have similar properties because they come from group one and have one electron on their outer shell. These properties include: - They react vigorously with water Hydrogen is given out Atomic Structure – Revision Pack (C4) - The metal reacts with water to form an alkali (the hydroxide of the metal) You can predict the reactivity of certain elements by looking at the pattern of reactivity in other alkali metals. The balanced symbol equation for Li and H2O is: 2Li + 2H2O 2LiOH + H2 Reactivity of Group 1 Elements: Atoms of Group 1 elements will have similar properties because they have one electron in their outer shell. When the atoms of alkali metals react, they lose one electron and form: - A full outer shell, so have a stable electronic structure A positive ion which has more positive charge in its nucleus than negative charge from the surrounding shells This can be represented through the equation: Na – e- Na+ The closer the outer shell’s electron is to the nucleus, the more attractive force there is, so the electron is less easily lost. Na is more reactive than Li. The easier it is for an atom of an alkali metal to lose its electron, the more reactive it is. Oxidation: Oxidation Is Loss; for example: K - e- K+ An atom of potassium loses an electron to form a positive ion. This is an example of oxidation. Flame Tests: Atomic Structure – Revision Pack (C4) A flame test is used to find out if lithium, sodium and potassium are present in a compound. Alkali metal in the compound Lithium Sodium Potassium Colour of flame Red Yellow Lilac How to do it: STEP 1 – Put on some safety goggles STEP 2 – A flame-test wire is moistened with dilute HCl STEP 3 – The flame-test wire is then dipped into a solid chemical STEP 4 – The flame-test wire is then put in a blue Bunsen Burner flame STEP 5 – You can then identify which alkali metal is present in the compound Past Papers: PPQ(1): Atomic Structure – Revision Pack (C4) OCR Gateway C4 C5 C6 June 2013 PPQ(2): Atomic Structure – Revision Pack (C4) OCR Gateway C4 C5 C6 SPECIMEN PAPER Mark Schemes: PPQ(1): Atomic Structure – Revision Pack (C4) PPQ(2): The Halogens: The Group 7 Elements all have similar properties because they all have seven electrons in their outer shells. They have similar properties because they are trying to gain one electron when they react. In the reaction with Group 1 elements, the halogens form a negative ion and gain a full electronic structure. Group 7 Element Chlorine Bromine Iodine Colour and state at room temperature Green gas Orange liquid Grey solid It is possible to predict the properties of group 7 elements if you know properties of the other halogens because they follow a particular trend. Atomic Structure – Revision Pack (C4) The nearer the outer shell is to the nucleus, the easier it is for an atom to gain one electron. Therefore, the easier it is to gain the electron, the more reactive the halogen. Fluorine is more reactive than Chlorine. Reactions of Halogens: When a halogen reacts with an alkali metal, a metal halide is made. For example, when potassium reacts with iodine, the metal halide formed is potassium iodide. Word equation: Potassium + iodine Potassium Iodide OR 2K + I2 2KI The ‘ide’ is always the group 7 element. Another equation is: 2Li + Br2 Lithium is the alkali metal. 2LiBr Displacement Reaction: Halogen Gas (R) Chlorine Bromine Chlorine Bromine is the halogen. Lithium Bromide is the metal halide. Metal Halide (R) Metal Halide (P) Potassium Bromide Potassium Iodide Potassium Iodide Potassium Chloride Potassium Bromide Potassium Chloride Halogen Gas (P) Bromine Colour Iodine Red/Brown Solution Red/Brown Solution Iodine Orange Solution REMEMBER: Bromine can displace iodine. Chlorine can displace bromine and iodine. Iodine cannot displace either because it is the least reactive out of the three. Atomic Structure – Revision Pack (C4) BECAUSE displacement is dependent on reactivity, we can predict the reactions between halogen and metal halides. Reduction: REMEMBER - Reduction Is Gain, as shown in this ionic equation: Br2 + - 2e- 2Br- A molecule of bromine gains two electrons (one for each atom) It becomes two bromide ions that are negative ions This is reduction Past Papers: PPQ(1): Atomic Structure – Revision Pack (C4) OCR Gateway C4 C5 C6 SPECIMEN PAPER PPQ(2): Atomic Structure – Revision Pack (C4) OCR Gateway B4 C3 P4 June 2013 Mark Schemes: PPQ(1): Atomic Structure – Revision Pack (C4) PPQ(2): Covalent Bonding: Non-metals can share electron pairs between atoms – this is known as covalent bonding. The idea of covalent bonding is that when the elements react, they gain electrons to fill their outer shell and become stable. When the atoms join together, there is a strong bond that holds them together – covalent bonds. The formation of simple molecules that contain single and double bonds can be represented by ‘dot and cross’ diagrams which only show the outer shells electrons. For example: H2O has two single covalent bonds. Two pairs of electrons are shared. Oxygen atoms can each form two covalent bonds. Two pairs of electrons are shared in an O2 molecule – this is a Atomic Structure – Revision Pack (C4) Predicting chemical properties: The attraction between molecules like carbon dioxide and water is called an intermolecular force. The dot and cross diagrams for water and carbon dioxide represent how ALL the atoms bond to make a molecule – this means that you have to show ALL the electrons in each of the atoms. Carbon dioxide is made up of two oxygen and one carbon atom. The carbon atom has four electrons in its outer shell, so it needs four more. Oxygen atoms have six electrons in its outer shell, so needs to more. Two double covalent bonds are created – each oxygen outer shell is shared with two of the electrons from the carbon outer shell. This way all of the atoms have a full outer shell. The simple molecular structures, like CO2, have weak intermolecular forces so are very easy to break apart so the substances have low melting points. In covalent bonding there are no free electrons so these molecules do NOT conduct electricity. Groups and Periods: The group number (columns) is the same as the number of electrons in the outer shell. The period number (rows) is the number of shells needed for all the electrons. The development of the periodic table: Scientist Discovery Newlands 1865 – Newlands puts 56 elements into groups and noticed that every 8 elements behaved similarly. This was not accepted for another 50 years until other scientists discovered more evidence. Mendeleev 1869 – Mendeleev put all the elements in order in a table. He noted periodic changes in the elements and made the prediction that new elements would be discovered. 1891 – Mendeleev did not include the noble gases in his periodic table. Atomic Structure – Revision Pack (C4) After 1891 – Later investigations by other scientists confirmed Mendeleev’s idea of periodicity. His prediction that other elements would be found are correct. Past Paper Questions: PPQ(1): Atomic Structure – Revision Pack (C4) PPQ(2): Atomic Structure – Revision Pack (C4) Mark Schemes: Atomic Structure – Revision Pack (C4) PPQ(1): PPQ(2): What are the Transition Metals? The transition elements are a block of metallic elements that are located between group 2 and group 3 of the periodic table. This block contains elements such as iron (Fe), copper (Cu), platinum (Pt) and zinc (Zn). The transition elements have typical metallic properties and their compounds are often coloured, for example: - Copper compounds are blue Iron (II) compounds are pale green Iron (III) compounds are often orange or brown Atomic Structure – Revision Pack (C4) Transition elements and their compounds are often used as catalysts, for example: - Iron (Fe) is used in the Haber process to make ammonia, which is used in fertilisers Nickel (Ni) is used in the manufacture of margarine to harden the oils Thermal Decomposition of metal carbonates: If a transition metal carbonate is heated it undergoes thermal decomposition to form metal oxide and carbon dioxide; you can adapt this formula to any transition metal: (Transition) Metal Carbonate Metal Oxide + Carbon Dioxide Some examples of thermal decomposition include: - Iron carbonate Iron Oxide + Carbon Dioxide Nickel carbonate Nickel Oxide + Carbon Dioxide Zinc carbonate Zinc Oxide + Carbon Dioxide The metals will generally change colour during this reaction. You should also be able to write balanced symbol equations for this reaction, for example: - FeCO3 FeO + CO2 NiCO3 NiO + CO2 ZnCO3 ZnO + CO2 The CO3 part is the carbonate. Metal Metal C O + O C The O part is the oxide. The CO2 part is the carbon dioxide. O O O O Atomic Structure – Revision Pack (C4) This is an experiment to test whether thermally decomposing a transition element makes carbon dioxide. During heating, a transition element should ALWAYS give off carbon dioxide! The delivery tube should send the gas produced down into the limewater, if it turns milky then carbon dioxide was made. Precipitation Reactions with Sodium Hydroxide (Na+OH-) solution: Sodium hydroxide is added to solutions to identify what transition elements are present. The NaOH solution reacts with compounds of each transition metal to make a solid of a certain colour, for example: - Cu2+ ions form a blue solid Fe2+ ions form a grey / green solid Fe3+ ions form a orange / brown solid You will often be asked to write a balanced symbol equation of a precipitate reaction, for example: - Cu2+ + 2OH- Cu(OH)2 Fe2+ + 2OH- Fe(OH)2 Fe3+ + 3OH- Fe(OH)3 Past Papers: Atomic Structure – Revision Pack (C4) PPQ(1): PPQ(2): 11 Iron and copper are transition elements. (a) Brahim adds a small volume of sodium hydroxide solution to five different solutions. An insoluble solid called a precipitate is made each time. Look at the results table. It is not finished. Solution Copper chloride Formula Colour of precipitate made CuCl2 Blue Copper nitrate Cu(NO3)2 ....................................................... Iron (II) chloride FeCl2 Green Iron (II) sulphate FeSO4 Green Iron (III) nitrate Fe(NO3)3 ...................................................... (i) Finish the table. (ii) Look at the formulas in the table. [2] Which formula contains six oxygen atoms? Choose from the table. ......................................................................................................... [1] PPQ(3): Atomic Structure – Revision Pack (C4) PPQ(4): Mark Schemes: PPQ(1): Atomic Structure – Revision Pack (C4) Question 7 (c) Answer Fe(OH)2 Marks Guidance 1 PPQ(2): Question 11 (a) (i) Answer Copper nitrate – blue Marks Guidance 2 (1) Iron (III) nitrate – Allow foxy red / red-brown (1) orange / rusty / brown (1) 11 (a) (ii) Ignore red or yellow Copper nitrate / 1 Cu(NO3)2 (1) Ignore CuNO3 PPQ(3): Question Answer 11 (a) (iii) Cu2+ + 2OH- Marks 2 Guidance Allow any correct multiple Cu(OH)2 Allow 1 mark for correct balancing with Correct formula (1) minor errors of case or subscript Correct balancing (1) Allow = instead of arrow Ignore state symbols Not + for and PPQ(4): Question 8 (c) Answer Fe3+ +3OH- Fe(OH)3 (1) Marks 1 Guidance Look for balancing on the printed examination as well as the answer line.
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