Quadratic equation: - any equation that can be written in the form ππ₯ 2 + ππ₯ + π = 0 o π and/or π can equal zero, but π cannot o if π = 0 the equation is NOT quadratic - the degree of a quadratic equation is always 2 - the following are all examples of quadratic equations o 2π₯ 2 β 3π₯ β 5 = 0 o βπ₯ 2 + 4π₯ = 0 1 3 o 2 π₯2 + 4 = 0 o β3π₯ 2 = 0 Zero Factor Theorem: - the product of two or more factors is zero if and only if at least one of the factors is zero o π₯π¦ = 0 if and only if π₯ = 0 or π¦ = 0 o (π₯ β 2)(π₯ + 3) = 0 if and only if π₯ β 2 = 0 or π₯ + 3 = 0 ο§ this means that π₯ = 2 or π₯ = β3, so there are two solutions o this Theorem does NOT work for any other numbers but zero ο§ if π₯ β π¦ = 1, there are an infinite number of possible values for the factors π₯ and π¦ When an equation is factorable, we set it equal to zero so we can use the Zero Factor Theorem to solve it. Steps for Solving an Equation by Factoring: 1. write the equation as a polynomial and set it equal to zero 2. factor the polynomial (review the Steps for Factoring if needed) 3. use Zero Factor Theorem to solve Example 1: Solve the following equations for π₯ and enter exact answers only (no decimal approximations). If there is more than one solution, separate your answers with commas. If there are no real solutions, enter NO SOLUTION. a. 15π₯ 2 β 2 = 13π₯ b. π₯(3π₯ + 10) = 8 Quadratic equations are not the only type of equation that can be solved by factoring. Other polynomial equations such as 2π₯ 4 β 168π₯ 2 + 486 = 0 (which we will see in a future lesson) that are not quadratic can still be solved by factoring. Example 2: Solve the following equations for π₯ and enter exact answers only (no decimal approximations). If there is more than one solution, separate your answers with commas. If there are no real solutions, enter NO SOLUTION. a. π₯ = b. b 15β4π₯ 2 17 c. 10 + 17π₯ = 6π₯ 2 d. d b. 26π₯ + 24 = 5π₯ 2 d. (π₯ β 1)(π₯ β 2) = 6 e. π₯ 2 β 25 = 0 f. (3π₯ )2 β 16 = 0 Again, this method of solving equations can be used to solve more than just quadratic equations, as we will see in future lessons. Answers to Examples: 2 2 3 4 1a. π₯ = β 15 , 1 ; 1b. π₯ = β4, 3 ; 2a. π₯ = β5, 4 ; 2b. π₯ = 5 , 6 ; 1 10 2c. π₯ = β 2 , 3 4 4 ; 2d. π₯ = β1, 4 ; 2e. = β5, 5 ; 2f. π₯ = β 3 , 3 ;
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