Problems. Integral calculus 1. Evaluate the indefinite integral: . 2. Evaluate the indefinite integral: 3. Evaluate the indefinite integral: 4. Evaluate the indefinite integral: .5. Evaluate the indefinite integral: . 6. Evaluate the indefinite integral: . 7. Evaluate the indefinite integral: 8. Evaluate the indefinite integral: 9. Evaluate the indefinite integral: 10. Evaluate the indefinite integral: 11. Evaluate the indefinite integral: 12. Evaluate the indefinite integral: 13. Evaluate the indefinite integral: . . . . . . . . . . 14. Evaluate the indefinite integral: . 15. Evaluate the indefinite integral: 16. Evaluate the indefinite integral: 17. Evaluate the indefinite integral by per partes method: . 18. Evaluate the indefinite integral by per partes method: . 19. Evaluate the indefinite integral: . 20. Evaluate the indefinite integral: . 21. Evaluate the indefinite integral: 22. Evaluate the definite integral: 23. Evaluate the definite integral: 24. Evaluate the definite integral: 25. Evaluate the definite integral: 26. Evaluate the definite integral: 27. Evaluate the definite integral: . . . . . . . . . 28. Calculate the area of region bounded by the curves: . 29. Calculate the area of region bounded by the curve: 30. Find the volume generated by revolving the area bounded by the parabola: about the -axis for . 31. Find the volume generated by revolving the first- and second-quadrant area bounded by the ellipse: about the -axis. 32. Find the length of the arc of the curve: 33. Find the length of the arc of the curve: 34. Find the area of the surface of revolution generated by revolving about -axis the arc of the ellipse: . and and -axis from to for . . Solutions 1. 2. 3. 4. 5. 6. 7. Absolute value can be omitted since 8. 9. 10. 11. for all . 12. 13. 14. 15. 16. 17. We obtain an equation: from which: 18. = 19. 20. 21. First we transform the rational function to partial fractions: For the coefficients: Second integral can be evaluated by a recursive formula: We obtain: 22. 23. 24. 25. 26. 27. 28. Surface area of the region bounded by the curves: can be obtained as definite integral: First we find the crossing points of the curves: and . Fig. 1. 29. Region bounded by the curves: and . Surface area of the region bounded by the symmetric curve: can be calculated as 4 times the region located in the first quadrant: Fig. 2. Region bounded by the curve: 30. Volume generated by revolving the area bounded by the parabola: -axis for can be calculated as: about the Fig. 3. Solid of revolution generated by revolving the area bounded by the parabola: about -axis on the interval . 31. Volume generated by revolving the first- and second-quadrant area bounded by the ellipse: about the -axis can be evaluated as definite integral for the boundaries of integration : y Fig. 4. Solid of revolution generated by revolving the first- and second-quadrant area bounded by the ellipse: about -axis. 32. The length of the arc of the curve: calculated as: First we calculate: on the interval: . can be 33. The length of the arc of the curve: on the interval will be calculated as: Fig. 5. Graph of a curve: 34. The area of the surface of revolution generated by revolving about -axis the arc of the ellipse: with the length of its main axis equal to 4 will be calculated as: . First we evaluate: .
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